POJ3090 Visible Lattice Points （数论：欧拉函数模板）

题目链接：传送门

思路：

　　所有gcd(x, y) = 1的数对都满足题意，然后还有(1, 0) 和 (0, 1)。

#include <iostream>
#include <cstring>

using namespace std;
const int MAX_N = 1e3 + ;
int prime[MAX_N+], phi[MAX_N+];
void getPrime_and_Phi() {
    memset(prime, , sizeof prime);
    phi[] = ;
    for (int i = ; i <= MAX_N; i++) {
        if (!prime[i]) prime[++prime[]] = i, phi[i] = i-;
        for (int j = ; j <= prime[] && prime[j] <= MAX_N/i; j++) {
            prime[i*prime[j]] = ;
            phi[i*prime[j]] = phi[i] * (i%prime[j] ? prime[j]- : prime[j]);
            if (i%prime[j] == ) break;
        }
    }
}

int main()
{
    getPrime_and_Phi();
    int C;
    cin >> C;
    for (int kase = ; kase <= C; kase++) {
        int N;
        cin >> N;
        long long ans = ;
        for (int i = ; i <= N; i++)
            ans += phi[i]*;
        cout << kase << ' ' << N << ' ' << ans << endl;
    }
    return ;
}