Lintcode: Rehashing

The size of the hash table is not determinate at the very beginning. If the total size of keys is too large (e.g. size >= capacity / 10), we should double the size of the hash table and rehash every keys. Say you have a hash table looks like below:

size=3, capacity=4
[null, 21->9->null, 14->null, null]

The hash function is:

int hashcode(int key, int capacity) {
    return key % capacity;
}

here we have three numbers, 9, 14 and 21, where 21 and 9 share the same position as they all have the same hashcode 1 (21 % 4 = 9 % 4 = 1). We store them in the hash table by linked list.

rehashing this hash table, double the capacity, you will get:

size=3, capacity=8
index:           0    1    2     3      4    5     6    7
hash table: [null, 9, null, null, null, 21, 14, null]

Given the original hash table, return the new hash table after rehashing .
Note
For negative integer in hash table, the position can be calculated as follow:

In C++/Java, if you directly calculate -4 % 3 you will get -1. You can use function: a % b = (a % b + b) % b to make it is a non negative integer.

In Python, you can directly use -1 % 3, you will get 2 automatically.

Example
Given [null, 21->9->null, 14->null, null], return [null, 9->null, null, null, null, 21->null, 14->null, null]

这道题就是根据条件老老实实的做

 /**
  * Definition for ListNode
  * public class ListNode {
  *     int val;
  *     ListNode next;
  *     ListNode(int x) {
  *         val = x;
  *         next = null;
  *     }
  * }
  */
 public class Solution {
     /**
      * @param hashTable: A list of The first node of linked list
      * @return: A list of The first node of linked list which have twice size
      */
     public ListNode[] rehashing(ListNode[] hashTable) {
         // write your code here
         int oldSize = hashTable.length;
         int newSize = oldSize * 2;
         if (hashTable==null || oldSize==0) return null;
         ListNode[] res = new ListNode[newSize];
         for (int i=0; i<oldSize; i++) {
             if (hashTable[i] != null) rehash(hashTable, res, i);
         }
         return res;
     }

     public void rehash(ListNode[] hashTable, ListNode[] res, int i) {
         int newSize = res.length;
         ListNode cur = hashTable[i];
         while (cur != null) {
             int val = cur.val;
             int newPos = val>=0? val%newSize : (val%newSize+newSize)%newSize;
             if (res[newPos] == null) res[newPos] = new ListNode(val);
             else {
                 ListNode temp = res[newPos];
                 while (temp.next != null) {
                     temp = temp.next;
                 }
                 temp.next = new ListNode(val);
             }
             cur = cur.next;
         }
     }
 };