Given a digit string, return all possible letter combinations that the number could represent.

A mapping of digit to letters (just like on the telephone buttons) is given below.

Input:Digit string "23"
Output: ["ad", "ae", "af", "bd", "be", "bf", "cd", "ce", "cf"].

Note:
Although the above answer is in lexicographical order, your answer could be in any order you want.

解题思路:

需要穷举不同中排列可能,典型需要回溯的思想;

可以选择递归或非递归的形式实现回溯;

递归:

 class Solution {
public:
vector<string> letterCombinations(string digits) {
vector<string> lst;
string ans;
if (digits == "")
return lst;
Backtracking(lst, ans, digits, );
return lst;
} void Backtracking(vector<string> &lst, string ans, string digits, int idx) {
if (idx == digits.size()) {
lst.push_back(ans);
return;
}
string cur_chars = d2l[digits[idx] - ''];
for (int i = ; i < cur_chars.size(); ++i)
Backtracking(lst, ans + cur_chars[i], digits, idx + );
} private:
vector<string> d2l = {
" ", "", "abc", "def", "ghi", "jkl",
"mno", "pqrs", "tuv", "wxyz"
};
};

非递归:

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