24. Swap Nodes in Pairs
24. Swap Nodes in Pairs
Given a linked list, swap every two adjacent nodes and return its head.
For example,
Given 1->2->3->4
, you should return the list as 2->1->4->3
.
Your algorithm should use only constant space. You may not modify the values in the list, only nodes itself can be changed.
找时间加入递归的写法
- class Solution(object):
- def swapPairs(self, head):
- """
- :type head: ListNode
- :rtype: ListNode
- """
- if head==None or head.next==None:
- return head
- temp_head=ListNode(-1)
- temp_head.next=head
- prehead=temp_head
- while prehead.next!=None and prehead.next.next!=None:
- a=prehead.next
- b=a.next
- prehead.next,a.next,b.next=b,b.next,a
- prehead=a
- return temp_head.next
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