关于oracle样例数据库emp、dept、salgrade的mysql脚本复杂查询分析

大家可以自行网上找资源（网上资源比较多，不建议下载我的），也可以在我这里下载：

1.取得每个部门最高薪水的人员名称：正确一共有4个单位，要进行左外连接其中一个单位没得员工

SELECT dept.dname, emp.ename, emp.sal

FROM emp

RIGHT JOIN dept ON emp.deptno = dept.deptno

RIGHT JOIN (

	SELECT dept.dname, MAX(emp.sal) AS 'max_sal'

	FROM emp

	RIGHT JOIN dept ON emp.deptno = dept.deptno

	GROUP BY dept.dname

)AS tt

ON tt.dname = dept.dname AND tt.max_sal = emp.sal

GROUP BY dname;

2.哪些人的薪水在部门平均薪水之上：不确定

SELECT dept.dname, emp.ename, emp.sal

FROM emp

INNER JOIN dept ON emp.deptno = dept.deptno

INNER JOIN (

	SELECT dept.dname, AVG(emp.sal) AS 'avg_sal'

	FROM emp

	INNER JOIN dept ON emp.deptno = dept.deptno

	GROUP BY dname

)AS tt

ON tt.dname = dept.dname AND tt.avg_sal <= emp.sal;

3.取得部门中所有人的平均薪水等级

SELECT tt.dname, salgrade.grade

FROM

(

	SELECT dept.dname, AVG(emp.sal) AS 'avg_sal'

	FROM emp

	RIGHT JOIN dept ON emp.deptno = dept.deptno

	GROUP BY dname

) AS tt,

salgrade

WHERE tt.avg_sal >= salgrade.losal AND tt.avg_sal <= hisal;

4.不准使用组函数（MAX），取得最高薪水

SELECT emp.ename, emp.sal

FROM emp

ORDER BY sal DESC -- 由高到底， asc 由低到高

LIMIT 0, 1;

5.取得平均薪水最高的部门的部门编号

SELECT deptno

FROM

(

	SELECT dept.deptno, AVG(emp.sal) AS 'avg_sal'

	FROM emp

	INNER JOIN dept ON emp.deptno = dept.deptno

	GROUP BY dname

	ORDER BY avg_sal DESC

	LIMIT 0, 1

)AS tt;

6.取得平均薪水最高的部门的部门名称

SELECT dname

FROM

(

	SELECT dept.dname, AVG(emp.sal) AS 'avg_sal'

	FROM emp

	INNER JOIN dept ON emp.deptno = dept.deptno

	GROUP BY dname

	ORDER BY avg_sal DESC

	LIMIT 0, 1

)AS tt;

7.求平均薪水的等级最低的部门的部门名称

SELECT dname

FROM

(

	SELECT t1.dname , SALGRADE.`GRADE`

	FROM

	(

		SELECT dept.dname, AVG(emp.sal) AS 'avg_sal'

		FROM emp

		INNER JOIN dept ON emp.deptno = dept.deptno

		GROUP BY dname

	) AS t1	, SALGRADE

	WHERE t1.avg_sal >= SALGRADE.`LOSAL` AND t1.avg_sal <= SALGRADE.`HISAL`

)AS tt

WHERE tt.grade =

(

	SELECT MIN(SALGRADE.`GRADE`)

	FROM

	(

		SELECT dept.dname, AVG(emp.sal) AS 'avg_sal'

		FROM emp

		INNER JOIN dept ON emp.deptno = dept.deptno

		GROUP BY dname

	) AS t1	, SALGRADE

	WHERE t1.avg_sal >= SALGRADE.`LOSAL` AND t1.avg_sal <= SALGRADE.`HISAL`

);

8.取得比普通员工（员工代码没有在mgr上出现的）的最高薪水

SELECT emp.ename

FROM emp

WHERE emp.mgr IS NULL

AND sal >

(

	SELECT MAX(sal) FROM emp WHERE mgr IS NOT NULL

);

9.取得薪水最高的5名员工

SELECT emp.`EMPNO` AS '编号', emp.`ENAME` AS '姓名'-- , emp.`SAL` as '薪资'

FROM emp

ORDER BY emp.`SAL` DESC

LIMIT 0, 5;

10.取得薪水最高的第六到第十名员工

SELECT emp.`EMPNO` AS '编号', emp.`ENAME` AS '姓名'-- , emp.`SAL`

FROM emp

ORDER BY emp.`SAL` DESC

LIMIT 5, 5;

11.取得最后入职的5名员工

SELECT tt.no AS '编号', tt.name AS '姓名'-- , tt.days

FROM

(

	SELECT emp.`EMPNO` AS 'no', emp.`ENAME` AS 'name', TO_DAYS(HIREDATE) AS 'days'

	FROM emp

) AS tt

ORDER BY days DESC

LIMIT 0, 5;

12.取得每个薪水等级有多少员工

SELECT salgrade.`GRADE` AS '薪资等级', COUNT(tt.`EMPNO`) AS '员工数'

FROM salgrade,

(

	SELECT emp.`EMPNO`, emp.`SAL`

	FROM emp

) AS tt

WHERE tt.`SAL` >= salgrade.`LOSAL` AND tt.`SAL` <= salgrade.`HISAL`

GROUP BY salgrade.`GRADE`;

13.列出所有员工及领导的名字

SELECT emp.`ENAME` AS '员工名称', tt.lname AS '领导名称'

FROM

emp LEFT JOIN

(

	SELECT emp.`EMPNO`, emp.`ENAME` AS 'lname'

	FROM emp

	WHERE empno IN

	(

		SELECT mgr FROM emp

	) -- 找出所有是领导的员工no

) AS tt

ON emp.`MGR` = tt.empno;

14.列出受雇日期早于直接上级的所有员工编号、姓名、部门

SELECT t2.eno AS '编号', t2.ename AS '姓名', dept.`DNAME` AS '部门名称', t2.ehiredate AS '员工受雇日期', t2.lhiredate AS '领导受雇日期'

FROM dept

INNER JOIN

(

	SELECT emp.`EMPNO` AS 'eno', emp.`ENAME`, emp.`HIREDATE` AS 'ehiredate', t1.lhiredate, emp.`DEPTNO`

	FROM

	emp LEFT JOIN

	(

		SELECT emp.`EMPNO` AS 'lno', emp.`HIREDATE` AS 'lhiredate'

		FROM emp

		WHERE empno IN

		(

			SELECT mgr FROM emp

		) -- 找出所有是领导的员工no

	) AS t1

	ON emp.`MGR` = t1.lno

) AS t2

ON t2.deptno = dept.`DEPTNO`

WHERE t2.ehiredate <  t2.lhiredate OR t2.lhiredate IS NULL;

15.列出部门名称和这些部门的员工信息，同时列出那些没有员工的部门

SELECT dept.`DNAME` AS '部门名称', emp.`ENAME` AS '员工名称', emp.`JOB` AS '职位', emp.`HIREDATE` AS '入职时间', emp.`SAL` AS '薪水'

FROM dept LEFT JOIN emp ON dept.`DEPTNO` = emp.`DEPTNO`

16.列出至少有5个员工的所有部门

SELECT dept.`DNAME` AS '部门名', COUNT(emp.`EMPNO`) AS '员工个数'

FROM dept LEFT JOIN emp ON dept.`DEPTNO` = emp.`DEPTNO`

GROUP BY dept.`DNAME` HAVING COUNT(emp.`EMPNO`) >= 5;

17.列出薪水比“SMITH”多的所有员工信息

SELECT *

FROM emp

WHERE emp.`SAL` >

(

	SELECT emp.`SAL`

	FROM emp

	WHERE emp.`ENAME` = 'SMITH'

);

18.列出所有“CLERK”办事员的姓名及其部门名称，部门人数

SELECT emp.`ENAME` AS '姓名', dept.`DNAME` AS '部门名称', tt.emp_count AS '部门人数'

FROM emp LEFT JOIN dept ON emp.`DEPTNO` = dept.`DEPTNO`

INNER JOIN

(

	SELECT dept.`DEPTNO`, COUNT(emp.`EMPNO`) AS 'emp_count'

	FROM dept LEFT JOIN emp ON dept.`DEPTNO` = emp.`DEPTNO`

	GROUP BY dept.`DEPTNO` 

) AS tt

ON emp.`DEPTNO` = tt.deptno

WHERE emp.`JOB` = 'CLERK';

19.列出最低薪水大于1500的各种工作及从事此工作的全部雇员人数

SELECT emp.`JOB` AS '工作名称', COUNT(emp.`EMPNO`) AS '雇员人数'

FROM emp

WHERE emp.`JOB` IN (

	SELECT emp.`JOB`

	FROM emp

	GROUP BY emp.`JOB` HAVING MIN(emp.`SAL`) >1500

)

GROUP BY emp.`JOB`;

-- 20.列出在部门“SALES”<销售部>工作的员工姓名（假定不知道销售部门的部门编号）

SELECT emp.`ENAME` AS '销售部人员'

FROM emp

WHERE emp.`DEPTNO` = (

	SELECT dept.`DEPTNO`

	FROM dept

	WHERE dept.`DNAME` = 'sales'

);

21.列出薪水高于公司平均薪水的所有员工，所在部门、上级领导、雇员的工资等级

SELECT t1.ename AS '员工名称', dept.`DNAME` AS '部门名称', t2.ename AS '上级名称', t1.grade AS '工资等级', t1.sal AS '工资'

FROM

(

	SELECT emp.`EMPNO`, emp.`DEPTNO`, emp.`ENAME`, emp.`SAL`, emp.`MGR`,salgrade.`GRADE`

	FROM emp, salgrade

	WHERE emp.`SAL` > (

		SELECT AVG(sal) AS 'avg_sal'

		FROM emp

	) AND emp.`SAL` >= salgrade.`LOSAL` AND emp.`SAL` <= salgrade.`HISAL`

) AS t1

LEFT JOIN

(

	SELECT emp.`EMPNO` AS 'mgr', emp.`ENAME` -- 注意这里是查出所有领导的empno，作为mgr编号

	FROM emp

	WHERE emp.`EMPNO` IN

	(

		SELECT DISTINCT(emp.`MGR`) -- 必须要distinct 不然查出来的mgr有重复，后面上层再查重复值接近笛卡尔积

		FROM emp

		WHERE mgr IS NOT NULL

	)

) AS t2

ON t1.mgr = t2.mgr

LEFT JOIN dept ON t1.deptno = dept.`DEPTNO`;

22.列出“SCOTT”从事相同工作的所有员工及部门名称

SELECT emp.`EMPNO` AS '员工编号', emp.`ENAME` AS '员工名称', dept.`DNAME` AS '部门名称'-- , emp.`DEPTNO`

FROM emp, dept

WHERE emp.`JOB` = (

	SELECT emp.`JOB` -- 查询出SCOTT从事的职业

	FROM emp

	WHERE emp.`ENAME` = 'SCOTT'

) AND emp.`ENAME` <> 'SCOTT'

AND emp.`DEPTNO` = dept.`DEPTNO`;

23.列出薪水等于部门30中员工的薪水的其它员工的姓名和薪水

SELECT emp.`EMPNO` AS '员工编号', emp.`ENAME` AS '员工名称', emp.`SAL` AS '员工薪水'

FROM emp

WHERE emp.`DEPTNO` <> 30

AND emp.`SAL` IN(

	SELECT DISTINCT emp.`SAL` -- 查询出部门为30的所有的员工的sal 不重复

	FROM emp

	WHERE emp.`DEPTNO` = 30

);

24.列出薪金高于在部门 30 工作的所有员工的薪金的员工姓名和薪金、部门名称

SELECT emp.`EMPNO` AS '员工编号', emp.`ENAME` AS '员工名称', emp.`SAL` AS '员工薪水', dept.`DNAME` AS '部门名称'

FROM emp, dept

WHERE emp.`DEPTNO` <> 30

AND emp.`SAL` >(

	SELECT MAX(emp.`SAL`) -- 查询出部门为30的所有的员工的sal 不重复

	FROM emp

	WHERE emp.`DEPTNO` = 30

)

AND dept.`DEPTNO` = emp.`DEPTNO`;

25. 列出在每个部门工作的员工数量、平均工资和平均服务期限

SELECT dept.`DNAME` AS '部门名称', COUNT(emp.`EMPNO`) AS '员工数量', ROUND(AVG(emp.`SAL`), 2) AS '平均工资', t2.avg_year AS '平均服务年限'

FROM dept LEFT JOIN emp ON dept.`DEPTNO` = emp.`DEPTNO`

LEFT JOIN

(

	SELECT t1.deptno, ROUND(AVG(t1.year), 0) AS 'avg_year' -- 四舍五入，保留0位小数

	FROM

	(

		SELECT emp.`DEPTNO`, ROUND((TO_DAYS(NOW())-TO_DAYS(emp.`HIREDATE`))/366, 0) AS 'year'

		FROM emp

	) AS t1

	GROUP BY t1.deptno

) AS t2

ON dept.`DEPTNO` = t2.deptno

GROUP BY dept.`DEPTNO`;

26. 列出所有员工的姓名、部门名称和工资

SELECT emp.`ENAME` AS '员工名称', dept.`DNAME` AS '部门名称', emp.`SAL` AS '工资'

FROM emp, dept

WHERE dept.`DEPTNO` = emp.`DEPTNO`;

27. 列出所有部门的详细信息和人数

SELECT dept.`DEPTNO` AS '部门编号', dept.`DNAME` AS '部门名称', dept.`LOC` AS '部门地址', tt.num AS '部门人数'

FROM dept LEFT JOIN

(

	SELECT emp.`DEPTNO`, COUNT(emp.`EMPNO`) AS 'num'

	FROM emp

	GROUP BY emp.`DEPTNO`

) AS tt

ON dept.`DEPTNO` = tt.`DEPTNO`;

28. 列出各种工作的最低工资及从事此工作的雇员姓名

SELECT emp.`SAL`, emp.`ENAME`

FROM emp,

(

	SELECT emp.`JOB`, MIN(emp.`SAL`) AS 'min_sal'

	FROM emp

	GROUP BY emp.`JOB`

)AS tt

WHERE emp.`JOB` = tt.job AND emp.`SAL` = tt.min_sal;

29. 列出各个部门 MANAGER 的最低薪金

SELECT dept.`DNAME` AS '部门名称', MIN(tt.sal) AS '最低薪资'

FROM dept LEFT JOIN

(

	SELECT emp.`DEPTNO`, emp.`SAL`

	FROM emp

	WHERE emp.`JOB` = 'manager'

) AS tt

ON dept.`DEPTNO` = tt.deptno

GROUP BY dept.`DEPTNO`;

30. 列出所有员工的年工资，按年薪从低到高排序

SELECT emp.`EMPNO` AS '员工编号', emp.`ENAME` AS '员工名称', (emp.`SAL`*12) AS '年薪'

FROM emp

ORDER BY 年薪 ASC;

31. 求出员工领导的薪水超过 3000 的员工名称和领导名称

SELECT tt.ename AS '领导名称', emp.`ENAME` AS '雇员名称'

FROM emp RIGHT JOIN

(

	SELECT emp.`EMPNO`, emp.`ENAME`

	FROM emp

	WHERE emp.`EMPNO` IN

	(

		SELECT DISTINCT emp.`MGR`

		FROM emp

		WHERE emp.`MGR` IS NOT NULL

	) AND emp.`SAL` >= 3000

) AS tt

ON emp.`MGR` = tt.empno

32. 求部门名称中带“S”字符的部门员工的工资合计、部门人数

SELECT tt.dname AS '部门名称', SUM(emp.`SAL`) AS '工资合计', COUNT(emp.`EMPNO`) AS '部门人数'

FROM emp RIGHT JOIN

(

	SELECT dept.`DEPTNO`, dept.`DNAME`

	FROM dept

	WHERE dept.`DNAME` LIKE '%s%'

) AS tt

ON emp.`DEPTNO` = tt.deptno

GROUP BY emp.`DEPTNO`;

32+.查询名字中有s的员工的工资总和（按照部门进行分组）

SELECT dept.`DNAME` AS '部门名称', SUM(tt.`SAL`) AS '工资'

FROM dept LEFT JOIN

(

	SELECT emp.`EMPNO`, emp.`ENAME`, emp.`SAL`, emp.`DEPTNO`

	FROM emp

	WHERE emp.`ENAME` LIKE '%s%'

) AS tt

ON dept.`DEPTNO` = tt.deptno

GROUP BY dept.`DEPTNO`;

33. 给任职日期超过 30 年的员工加薪 10%

UPDATE emp SET emp.`SAL` = emp.`SAL` + emp.`SAL`*10

WHERE emp.`EMPNO` IN(

	SELECT tt.`EMPNO`

	FROM (

		SELECT emp.`EMPNO`, ROUND((TO_DAYS(NOW())-TO_DAYS(emp.`HIREDATE`))/366, 0) AS 'work_year'

		FROM emp

	) AS tt

	WHERE tt.work_year > 30

);

关于oracle样例数据库emp、dept、salgrade的mysql脚本复杂查询分析的更多相关文章

oracle学习创建和准备Oracle样例数据库
此处有一个Oracle创建数据库和表和插入数据的脚本: http://www.forta.com/books/0672336073/
mysql样例数据库employees
Oracle和sqlserver都有基于员工信息的样例数据库,同样mysql上也是有的. 给出一个连接地址https://github.com/datacharmer/test_db. 下载后直接调用 ...
Sakila——MySQL样例数据库解析（已经迁移）
一.Introduction Sakila可以作为数据库设计的参考,也可作为实验数据.我是用作数据仓库和ODI学习的实验数据. The Sakila sample database was devel ...
SQL-AdventureWorks样例数据库
1. 下载样例数据库文件输入网址:http://www.codeplex.com/ , 搜索:microsoft sql server product samples 下载对应数据库的Adventu ...
SQL SEVER 2008中的演示样例数据库
SQL SEVER 2008数据库是什么我就不说了,我在这里分享一下怎样学习SQL SEVER 2008数据库,假设是对数据库或是SQL SEVER 数据库全然陌生或是不熟悉的人来说,建议看看一些视频 ...
Android SqlDelight具体解释和Demo样例
一.简单介绍 SQLDelight 和 SqlBrite 是 Square 公司推出的一个 Android 平台数据库解决方式. 在了解这个两个东西前,必须先得有Andorid的Sqlite的知识(S ...
MySQL、SqlServer、Oracle 三种数据库的优缺点
MySQL.SqlServer.Oracle 三种数据库的优缺点一.MySQL 优点: 缺点: 二.SqlServer 优点: 缺点: 三.Oracle 优点: 缺点: 一.MySQL 优点: 体积 ...
Deinstall卸载RAC之Oracle软件及数据库+GI集群软件
Deinstall卸载Oracle软件及数据库+GI集群软件 1. 本篇文档应用场景: 需要安装新的ORACLE RAC产品,系统没有重装,需要对原环境中的RAC进行卸载: #本篇文档,在AIX 6. ...
[Oracle]数据库的Control File 取Dump后的样例
[Oracle]数据库的Control File 取Dump后的样例: 片段截取-------------------------------(size = 40, compat size = 40, ...

随机推荐

【Tips】有道云笔记中Markdown插入图片
在有道云笔记中用MarkDown插入图片新建一个文档专门用来放图片把所有要用的图片专门放在一个笔记里,用普通模式先同步笔记,然后用分享笔记会有一个链接,用浏览器打开这个分享的笔记就能找到所有的图 ...
关于 junit4 90% 的人都不知道的特性，详解 junitperf 的实现原理
前言上一节介绍了 https://github.com/houbb/junitperf 的入门使用. 这一节我们从源码的角度,剖析一下其实现方式. 性能测试该怎么做? Junit Rules jun ...
架构之:REST和HATEOAS
目录简介 HATEOAS简介 HATEOAS的格式 HATEOAS的Spring支持总结简介我们知道REST是一种架构方式,它只是指定了六种需要遵循的基本原则,但是它指定的原则都比较宽泛,我们 ...
计算机基础-Socket
计算机基础-Socket 当时明月在,曾照彩云归. 简介:计算机基础-Socket 一.I/O 模型一个输入操作通常包括两个阶段: 等待数据准备好从内核向进程复制数据对于一个套接字上的输入操作, ...
Guass消元总结
Guass消元约旦·高斯消元法求线性方程组我们用一个\(n*(n+1)\)的矩阵存储线性方程组各项系数和零次项系数. 每一次找到一个未知数系数最大的方程,交换当前行方程和该方程,并将其他行该未知 ...
mysql jdbc8.0连接mysql
SpringBoot之yaml语法及静态资源访问
配置文件-yaml 在spring Boot开发中推荐使用yaml来作为配置文件. 基本语法: key: value:kv之间有空格大小写敏感使用缩进表示层级关系缩进不允许使用tab,只允许空格 ...
微信小程序对接显示阿里云数据库数据
现实需求在项目中需求,有时候现场设备发生故障,需要远程的人员知道.除了邮件方式,以微信小程序的方式也很好.今天进行尝试,并制作了一个demo版本. 1.微信小程序申请制作前端 1.1lists文件( ...
关于vue3简单状态管理约定引发的思考
官方文档的代码是这样的 export const store = { debug: true, state: reactive({ message: 'Hello!' }), setMessageAc ...
我快被Framework源码烦死了！
前言这段时间,忙到没时间学新东西,都有点心有余而力不足,想着抽空补补课,于是重读了Framework源码. 因为Framework源码太重要了,像掉帧监控.函数插装.慢函数检测.ANR 监控.启动监 ...

关于oracle样例数据库emp、dept、salgrade的mysql脚本复杂查询分析

关于oracle样例数据库emp、dept、salgrade的mysql脚本复杂查询分析的更多相关文章

随机推荐

热门专题