Queues and Priority Queues are data structures which are known to most computer scientists. The Team Queue, however, is not so well known, though it occurs often in everyday life. At lunch time the queue in front of the Mensa is a team queue, for example.

  In a team queue each element belongs to a team. If an element enters the queue, it first searches the queue from head to tail to check if some of its teammates (elements of the same team) are already in the queue. If yes, it enters the queue right behind them. If not, it enters the queue at the tail and becomes the new last element (bad luck). Dequeuing is done like in normal queues: elements are processed from head to tail in the order they appear in the team queue.

  Your task is to write a program that simulates such a team queue.

Input

  The input file will contain one or more test cases. Each test case begins with the number of teams t (1 ≤ t ≤ 1000). Then t team descriptions follow, each one consisting of the number of elements belonging to the team and the elements themselves. Elements are integers in the range 0..999999. A team may consist of up to 1000 elements.

  Finally, a list of commands follows. There are three different kinds of commands:

  • ENQUEUE x — enter element x into the team queue

  • DEQUEUE — process the first element and remove it from the queue

  • STOP — end of test case

  The input will be terminated by a value of 0 for t.

  Warning: A test case may contain up to 200000 (two hundred thousand) commands, so the implementation of the team queue should be efficient: both enqueing and dequeuing of an element should only take constant time.

Output

  For each test case, first print a line saying ‘Scenario #k’, where k is the number of the test case. Then, for each ‘DEQUEUE’ command, print the element which is dequeued on a single line. Print a blank line after each test case, even after the last one.

Sample Input

2
3 101 102 103
3 201 202 203
ENQUEUE 101
ENQUEUE 201
ENQUEUE 102
ENQUEUE 202
ENQUEUE 103
ENQUEUE 203
DEQUEUE
DEQUEUE
DEQUEUE
DEQUEUE
DEQUEUE
DEQUEUE
STOP
2
5 259001 259002 259003 259004 259005
6 260001 260002 260003 260004 260005 260006
ENQUEUE 259001
ENQUEUE 260001
ENQUEUE 259002
ENQUEUE 259003
ENQUEUE 259004
ENQUEUE 259005
DEQUEUE
DEQUEUE
ENQUEUE 260002
ENQUEUE 260003
DEQUEUE
DEQUEUE
DEQUEUE
DEQUEUE
STOP
0

Sample Output

Scenario #1
101
102
103
201
202
203 Scenario #2
259001
259002
259003
259004
259005
260001

HINT

这个题目不用紫皮书上的方法好像没有啥简单点的方法了。用的双队列,因为题目的意思是每一个排队成员都有属于自己的队伍,因此没进来一个人都会去找到自己的团队里面的最后一个的后面排队。因此用队列数组存储每一个小团队的队列,然后再加一个队列来存储各个团队的队列。更具体的壳代码和紫皮书就好。

Accepted

#include<algorithm>
#include <iostream>
#include<sstream>
#include<map>
#include<string>
#include<vector>
#include<set>
#include<stack>
#include<queue> using namespace std; int main()
{
int m,id, n,num=1;
while (1){
map<int, int>teams; //记录组名;
cin >> m;
if (!m)break;
for (int i = 0;i < m;i++){
cin >> n;
for (int j = 0;j < n;j++){
cin >> id;
teams[id] = i;
}
}
queue<int>q1, q2[1010];
string s;
cout << "Scenario #" << num++ << endl;
while (cin >> s && s != "STOP")
{
if (s == "DEQUEUE"){
cout << q2[q1.front()].front() << endl;
q2[q1.front()].pop();
if (q2[q1.front()].empty())q1.pop();
}
else {
cin >> id;
if (q2[teams[id]].empty())q1.push(teams[id]);
q2[teams[id]].push(id);
}
}
cout << endl;
}
}

Team Queue UVA - 540的更多相关文章

  1. uva 540 (Team Queue UVA - 540)

    又是一道比较复杂的模拟题.题中有两种队列,一种是总队列,从前向后.其他的是各个团体的小队列,因为入队的人如果有队友的话,会优先进入团体队列. 所以我们先设置两个队列和一个map,设置map倒是可以不用 ...

  2. UVA.540 Team Queue (队列)

    UVA.540 Team Queue (队列) 题意分析 有t个团队正在排队,每次来一个新人的时候,他可以插入到他最后一个队友的身后,如果没有他的队友,那么他只能插入到队伍的最后.题目中包含以下操作: ...

  3. UVA 540 Team Queue(模拟+队列)

    题目代号:UVA 540 题目链接:https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page ...

  4. uva 540 - Team Queue(插队队列)

    首发:https://mp.csdn.net/mdeditor/80294426 例题5-6 团体队列(Team Queue,UVa540) 有t个团队的人正在排一个长队.每次新来一个人时,如果他有队 ...

  5. 【UVA - 540】Team Queue (map,队列)

    Team Queue Descriptions: Queues and Priority Queues are data structures which are known to most comp ...

  6. UVA Team Queue

    版权声明:本文为博主原创文章.未经博主同意不得转载. https://blog.csdn.net/u013840081/article/details/26180081 题目例如以下: Team Qu ...

  7. hdu 1387(Team Queue) STL

    Team Queue Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)Total ...

  8. Team Queue (uva540 队列模拟)

    Team Queue Queues and Priority Queues are data structures which are known to most computer scientist ...

  9. UVA 540 stl

    Queues and Priority Queues are data structures which are known to most computer scientists. The Team ...

随机推荐

  1. css故障文字动画

    免费分享95套java实战项目,不仅有源码还有对应的开发视频,关注公众号『勾玉技术』回复"95"即可获取 首先给内容上hover和before, .glitch:hover:bef ...

  2. SpringBoot常见的异常问题

    1. org.mybatis.logging.LoggerFactory Springboot启动报错 Caused by: java.lang.ClassNotFoundException: org ...

  3. .Net -- NLog日志框架配置与使用

    NLog是适用于各种.NET平台(包括.NET标准)的灵活,免费的日志记录平台,NLog可将日志写入多个目标,比如Database.File.Console.Mail.下面介绍下NLog的基本使用方法 ...

  4. .NET测试--模拟框架NSubstitute

    .NET测试--模拟框架NSubstitute .NET测试 NSubstitute在GitHub的开源地址:https://github.com/nsubstitute/nsubstitute/do ...

  5. MySQL之四 存储引擎

    1.介绍 存储引擎MySQL中的"文件系统" MySQL体系结构 InnoDB存储引擎介绍 My1SAM 和InnoDB区别  mysql MariaDB [(none)]> ...

  6. MySQL 异常有这一篇就够了!

    摘要:在本文中,总结了开发过程中最为常见的几种 MySQL 抛出的异常以及如何解决,包括高版本驱动的问题.时区配置问题.SSL 连接问题等,是一篇经验总结贴. 前言 在本文中,总结了开发过程中最为常见 ...

  7. 分布式session实现方式

    一.背景 在搭建完集群环境后,不得不考虑的一个问题就是用户访问产生的session如何处理. 如果不做任何处理的话,用户将出现频繁登录的现象,比如集群中存在A.B两台服务器,用户在第一次访问网站时,N ...

  8. Java流程控制:三种基本结构

    顺序结构: Java的基本结构就是顺序结构,除非特别指明,否则就按照顺序一句一句执行顺序结构是最简单的算法结构语句与语句之间,框与框之间是按从上到下的顺序进行的,它是由若干个依次执行的处理步骤组成的, ...

  9. sitemesh简单介绍

    SiteMesh 是一个网页布局和修饰的框架,利用它可以将网页的内容和页面结构分离,以达到页面结构共享的目的. Sitemesh是由一个基于Web页面布局.装饰以及与现存Web应用整合的框架. 它能帮 ...

  10. 字符串匹配-BF算法和KMP算法

    声明:图片及内容基于https://www.bilibili.com/video/av95949609 BF算法 原理分析 Brute Force 暴力算法 用来在主串中查找模式串是否存以及出现位置 ...