Evaluate the value of an arithmetic expression in Reverse Polish Notation.

Valid operators are+,-,*,/. Each operand may be an integer or another expression.

Some examples:

  ["2", "1", "+", "3", "*"] -> ((2 + 1) * 3) -> 9
["4", "13", "5", "/", "+"] -> (4 + (13 / 5)) -> 6 将字符串序列转化为算式并计算,且符号在数字之后
 class Solution {
public:
int evalRPN(vector<string> &tokens) {
stack<int> s;
for(int i=;i<tokens.size();i++){
string cur = tokens[i];
int temp = atoi(cur.c_str());
if(cur=="+"||cur=="-"||cur=="*"||cur=="/"){
int left,right;
if(!s.empty()){
right=s.top();
s.pop();
}
if(!s.empty()){
left=s.top();
s.pop();
}
if(cur=="+")
temp=left+right;
else if(cur=="-")
temp=left-right;
else if(cur=="*")
temp=left*right;
else if(cur=="/")
temp=left/right; }
s.push(temp);
}
int res = s.top();
return res;
}
};

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