uva-10391-枚举

题意：对于输入的字符串,判断是否存在一个单词a=b+c

俩种方法,枚举每一个单词进行拼接,复杂度是n*n

枚举每一个单词,对单词进行substr,判断substr出来的是不在map里面

#include "pch.h"
#include <string>
#include<iostream>
#include<map>
#include<memory.h>
#include<vector>

namespace cc
{
	using std::cout;
	using std::endl;
	using std::cin;
	using std::map;
	using std::vector;
	using std::string;

	constexpr int N = 120000;

	string a[N];
	map<string, int>strMaps;
	void solve()
	{
		int n = 0;
		while (cin >> a[n])
		{
			strMaps[a[n]] = 1;
			n++;
		}
		for (int i=0;i<n;i++)
		{
			for (int j = 0;j < a[i].size();j++)
			{
				string str = a[i].substr(0,j+1);
				if (strMaps[str] == 0)
					continue;
				str = a[i].substr(j+1);
				if (strMaps[str] == 0)
					continue;
				cout << a[i] << endl;
				break;
			}

		}

	}

};

int main()
{

#ifndef ONLINE_JUDGE
	freopen("d://1.text", "r", stdin);
#endif // !ONLINE_JUDGE
	cc::solve();

	return 0;
}