原题地址:

打怪升级 一开始有N个怪物;主角有K个能力;只有K个能力都击败怪物才能斩杀怪物并获得K个能力的增值;问最多能杀几个怪物;

做法:

用优先队列把怪物能力装进去;能力小放前面;

最重要的是数据量要用读入挂才能过;(读入挂太神奇了!!)

 
 
代码:

#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
const ll mod=;
const int maxn=1e5+;
const ll inf=0x3f3f3f3f3f3f;
namespace IO{
#define BUF_SIZE 100000
#define OUT_SIZE 100000
#define ll long long
//fread->read bool IOerror=;
inline char nc(){
static char buf[BUF_SIZE],*p1=buf+BUF_SIZE,*pend=buf+BUF_SIZE;
if (p1==pend){
p1=buf; pend=buf+fread(buf,,BUF_SIZE,stdin);
if (pend==p1){IOerror=;return -;}
//{printf("IO error!\n");system("pause");for (;;);exit(0);}
}
return *p1++;
}
inline bool blank(char ch){return ch==' '||ch=='\n'||ch=='\r'||ch=='\t';}
inline void read(int &x){
bool sign=; char ch=nc(); x=;
for (;blank(ch);ch=nc());
if (IOerror)return;
if (ch=='-')sign=,ch=nc();
for (;ch>=''&&ch<='';ch=nc())x=x*+ch-'';
if (sign)x=-x;
}
inline void read(ll &x){
bool sign=; char ch=nc(); x=;
for (;blank(ch);ch=nc());
if (IOerror)return;
if (ch=='-')sign=,ch=nc();
for (;ch>=''&&ch<='';ch=nc())x=x*+ch-'';
if (sign)x=-x;
}
inline void read(double &x){
bool sign=; char ch=nc(); x=;
for (;blank(ch);ch=nc());
if (IOerror)return;
if (ch=='-')sign=,ch=nc();
for (;ch>=''&&ch<='';ch=nc())x=x*+ch-'';
if (ch=='.'){
double tmp=; ch=nc();
for (;ch>=''&&ch<='';ch=nc())tmp/=10.0,x+=tmp*(ch-'');
}
if (sign)x=-x;
}
inline void read(char *s){
char ch=nc();
for (;blank(ch);ch=nc());
if (IOerror)return;
for (;!blank(ch)&&!IOerror;ch=nc())*s++=ch;
*s=;
}
inline void read(char &c){
for (c=nc();blank(c);c=nc());
if (IOerror){c=-;return;}
}
//fwrite->write
struct Ostream_fwrite{
char *buf,*p1,*pend;
Ostream_fwrite(){buf=new char[BUF_SIZE];p1=buf;pend=buf+BUF_SIZE;}
void out(char ch){
if (p1==pend){
fwrite(buf,,BUF_SIZE,stdout);p1=buf;
}
*p1++=ch;
}
void print(int x){
static char s[],*s1;s1=s;
if (!x)*s1++='';if (x<)out('-'),x=-x;
while(x)*s1++=x%+'',x/=;
while(s1--!=s)out(*s1);
}
void println(int x){
static char s[],*s1;s1=s;
if (!x)*s1++='';if (x<)out('-'),x=-x;
while(x)*s1++=x%+'',x/=;
while(s1--!=s)out(*s1); out('\n');
}
void print(ll x){
static char s[],*s1;s1=s;
if (!x)*s1++='';if (x<)out('-'),x=-x;
while(x)*s1++=x%+'',x/=;
while(s1--!=s)out(*s1);
}
void println(ll x){
static char s[],*s1;s1=s;
if (!x)*s1++='';if (x<)out('-'),x=-x;
while(x)*s1++=x%+'',x/=;
while(s1--!=s)out(*s1); out('\n');
}
void print(double x,int y){
static ll mul[]={,,,,,,,,,
,10000000000LL,100000000000LL,1000000000000LL,10000000000000LL,
100000000000000LL,1000000000000000LL,10000000000000000LL,100000000000000000LL};
if (x<-1e-)out('-'),x=-x;x*=mul[y];
ll x1=(ll)floor(x); if (x-floor(x)>=0.5)++x1;
ll x2=x1/mul[y],x3=x1-x2*mul[y]; print(x2);
if (y>){out('.'); for (size_t i=;i<y&&x3*mul[i]<mul[y];out(''),++i); print(x3);}
}
void println(double x,int y){print(x,y);out('\n');}
void print(char *s){while (*s)out(*s++);}
void println(char *s){while (*s)out(*s++);out('\n');}
void flush(){if (p1!=buf){fwrite(buf,,p1-buf,stdout);p1=buf;}}
~Ostream_fwrite(){flush();}
}Ostream;
inline void print(int x){Ostream.print(x);}
inline void println(int x){Ostream.println(x);}
inline void print(char x){Ostream.out(x);}
inline void println(char x){Ostream.out(x);Ostream.out('\n');}
inline void print(ll x){Ostream.print(x);}
inline void println(ll x){Ostream.println(x);}
inline void print(double x,int y){Ostream.print(x,y);}
inline void println(double x,int y){Ostream.println(x,y);}
inline void print(char *s){Ostream.print(s);}
inline void println(char *s){Ostream.println(s);}
inline void println(){Ostream.out('\n');}
inline void flush(){Ostream.flush();}
#undef ll
#undef OUT_SIZE
#undef BUF_SIZE
}; int v[];
int value[maxn][];
int b[maxn][];
struct node{
int id;
int num;
node(int id,int num){this->id=id;this->num=num;}
bool friend operator<(node a,node b){
return a.num>b.num;
}
};
priority_queue<node>pq[];
void init(){
for(int i=;i<=;i++){
while(!pq[i].empty())pq[i].pop();
}
}
int n,k,t;
int main()
{
// std::ios::sync_with_stdio(false);
//std::cin.tie(0);
IO::read(t);
while(t--){
init();
IO::read(n);IO::read(k);
for(int i=;i<=k;i++)IO::read(v[i]);
for(int i=;i<=n;i++){
for(int j=;j<=k;j++){
IO::read(value[i][j]);
}
pq[].push(node(i,value[i][]));
for(int j=;j<=k;j++)IO::read(b[i][j]);
}
int ans=,ans1=-;
while(ans!=ans1){
ans1=ans;
for(int i=;i<k;i++){
while(!pq[i].empty()&&pq[i].top().num<=v[i]){
int now=pq[i].top().id;
pq[i].pop();
pq[i+].push(node(now,value[now][i+]));
}
}
while(!pq[k].empty()&&pq[k].top().num<=v[k]){
ans++;
int now=pq[k].top().id;
pq[k].pop();
for(int i=;i<=k;i++)v[i]+=b[now][i];
}
}
IO::println(ans);
for(int i=;i<=k;i++){
if(i!=)IO::print(' ');
IO::print(v[i]);
}
IO::print('\n');
}
return ;
}

 

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