HDU 5095 Linearization of the kernel functions in SVM(模拟)
主题链接:http://acm.hdu.edu.cn/showproblem.php?
pid=5095
= ax^2 + by^2 + cz^2 + dxy + eyz + fzx + gx + hy + iz + j. By introducing new variables p, q, r, u, v, w, the linearization of the function f(x,y,z) is realized by setting the correspondence x^2 <-> p, y^2 <-> q, z^2 <-> r,
xy <-> u, yz <-> v, zx <-> w and the function f(x,y,z) = ax^2 + by^2 + cz^2 + dxy + eyz + fzx + gx + hy + iz + j can be written as g(p,q,r,u,v,w,x,y,z) = ap + bq + cr + du + ev + fw + gx + hy + iz + j, which
is a linear function with 9 variables.
Now your task is to write a program to change f into g.
= ax^2 + by^2 + cz^2 + dxy + eyz + fzx + gx + hy + iz + j.
2
0 46 3 4 -5 -22 -8 -32 24 27
2 31 -5 0 0 12 0 0 -49 12
46q+3r+4u-5v-22w-8x-32y+24z+27
2p+31q-5r+12w-49z+12
pid=5098" style="color:rgb(26,92,200); text-decoration:none">5098
pid=5097" style="color:rgb(26,92,200); text-decoration:none">5097
5096pid=5094" style="color:rgb(26,92,200); text-decoration:none">5094
5093PS:
一道比較坑的模拟题。
注意1和-1 的情况。
代码例如以下:
#include <cstdio>
#include <cstring>
#include <algorithm>
#include <iostream>
using namespace std;
int main()
{
int M;
int a[17];
char b[17] = {'#','p','q','r','u','v','w','x','y','z'};
scanf("%d",&M);
getchar();
while(M--)
{
for(int k = 1; k <= 10; k++)
{
scanf("%d",&a[k]);
}
int cont = 0;
int flag = 0;
for(int k = 1; k < 10; k++)
{
if(a[k]==0)
continue;
cont++;
if(cont == 1)
{
if(a[k] != 1 && a[k] != -1)
printf("%d%c",a[k],b[k]);
else if(a[k] == 1)
printf("%c",b[k]);
else if(a[k] == -1)
printf("-%c",b[k]);
flag = 1;
}
else
{
if(a[k] > 0)
printf("+");
if(a[k] != 1 && a[k] != -1)
printf("%d%c",a[k],b[k]);
else if(a[k] == 1)
printf("%c",b[k]);
else if(a[k] == -1)
printf("-%c",b[k]);
flag = 1;
}
}
if(a[10])
{
if(a[10] > 0 && flag)
printf("+");
printf("%d",a[10]);
flag = 1;
}
if(!flag)//没有答案
printf("0");
printf("\n");
}
return 0;
}
/*
99
0 0 0 0 0 0 0 0 0 -1
0 0 0 0 0 0 0 0 0 1
0 0 0 0 0 0 0 0 0 0
1 0 0 0 0 0 0 0 0 0
-1 0 0 0 0 0 0 0 0 0
-1 -1 -1 -41 -1 -1 -1 -1 -1 -1
-1 5 -2 0 0 0 0 0 0 0
1 1 1 1 1 1 1 1 1 1
-1 -1 -1 -1 -1 -1 -1 -1 -1 -1
0 0 0 0 0 -1 -1 -1 -1 -1
0 0 0 0 0 1 1 1 1 1
1 1 1 1 1 0 0 0 0 0
-1 -1 -1 -1 -1 0 0 0 0 0
1 1 1 1 1 1 1 1 1 0
*/
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