According to Wikipedia:

Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort removes one element from the input data, finds the location it belongs within the sorted list, and inserts it there. It repeats until no input elements remain.

Heap sort divides its input into a sorted and an unsorted region, and it iteratively shrinks the unsorted region by extracting the largest element and moving that to the sorted region. it involves the use of a heap data structure rather than a linear-time search to find the maximum.

Now given the initial sequence of integers, together with a sequence which is a result of several iterations of some sorting method, can you tell which sorting method we are using?

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤100). Then in the next line, N integers are given as the initial sequence. The last line contains the partially sorted sequence of the N numbers. It is assumed that the target sequence is always ascending. All the numbers in a line are separated by a space.

Output Specification:

For each test case, print in the first line either "Insertion Sort" or "Heap Sort" to indicate the method used to obtain the partial result. Then run this method for one more iteration and output in the second line the resuling sequence. It is guaranteed that the answer is unique for each test case. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.

Sample Input 1:

10
3 1 2 8 7 5 9 4 6 0
1 2 3 7 8 5 9 4 6 0

Sample Output 1:

Insertion Sort
1 2 3 5 7 8 9 4 6 0

Sample Input 2:

10
3 1 2 8 7 5 9 4 6 0
6 4 5 1 0 3 2 7 8 9

Sample Output 2:

Heap Sort
5 4 3 1 0 2 6 7 8 9 我的答案
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h> void PrintA(int A[], int N)
{
int i;
for(i=;i<N;i++) {
if(i != N-)
printf("%d ", A[i]);
else
printf("%d\n", A[i]);
}
} int IsSameArr(int A[], int C[], int N)
{
int i;
for(i=;i<N;i++)
if(A[i] != C[i]) return ;
return ;
} void CopyArr(int A[], int B[], int N)
{
int i;
for(i=;i<N;i++)
B[i] = A[i];
} void Read(int A[], int B[], int N)
{
int i;
for(i=;i<N;i++) {
if(i!=N-)
scanf("%d ", &A[i]);
else
scanf("%d\n", &A[i]);
} for(i=;i<N;i++) {
if(i!=N-)
scanf("%d ", &B[i]);
else
scanf("%d\n", &B[i]);
}
} int InsertionSort(int A[], int B[], int N)
{
int P, i;
int Tmp, ret = ;
int flag = ; for(P=;P<N;P++) {
Tmp = A[P];
for(i=P;i> && A[i-]>Tmp;i--)
A[i] = A[i-];
A[i] = Tmp;
if(IsSameArr(A, B, N)) {
printf("Insertion Sort\n");
flag = ;
ret = ;
continue;
}
if(flag== ) {
flag = ;
PrintA(A, N);
}
}
if(flag == )
PrintA(A, N); return ret;
} void PrecDown(int A[], int P, int N)
{
int Parent, Child, temp = A[P];
for(Parent=P;Parent*+<N;Parent=Child) {
Child = Parent*+;
// printf("Child=%d A[Child]=%d temp=%d \n", Child, A[Child], temp);
if((Child < N-)&&(A[Child+] > A[Child]))
Child++;
if(temp < A[Child])
A[Parent] = A[Child];
else
break; // printf("[PecDown] ");
// PrintA(A, N);
}
A[Parent] = temp;
} void Swap(int *a, int *b)
{
int tmp;
tmp = *b;
*b = *a;
*a = tmp;
} void Heap_Sort(int A[], int B[], int N)
{
int i, flag = ;
// PrintA(A, N);
for(i=N/-;i>=;i--) {
// printf("Heap_Sort[i] = %d\n", i);
PrecDown(A, i, N);
if(IsSameArr(A, B, N)) {
printf("Heap Sort\n");
flag = ;
continue;
}
if(flag == ) {
flag = ;
PrintA(A, N);
}
} // printf("-----------\n"); for(i=N-;i>;i--) {
Swap(&A[], &A[i]);
PrecDown(A, , i);
if(IsSameArr(A, B, N)) {
printf("Heap Sort\n");
flag = ;
continue;
}
if(flag == ) {
flag = ;
PrintA(A, N);
}
}
} int main()
{
int N;
int *A, *B, *Tmp;
scanf("%d\n", &N);
A = (int *)malloc(sizeof(int)*N);
B = (int *)malloc(sizeof(int)*N);
Tmp = (int *)malloc(sizeof(int)*N);
Read(A, B, N);
CopyArr(A, Tmp, N);
if(!InsertionSort(Tmp, B, N)) {
CopyArr(A, Tmp, N);
Heap_Sort(Tmp, B, N);
}
return ;
}
 

09-排序3 Insertion or Heap Sort(25 分)的更多相关文章

  1. PTA 09-排序3 Insertion or Heap Sort (25分)

    题目地址 https://pta.patest.cn/pta/test/16/exam/4/question/676 5-14 Insertion or Heap Sort   (25分) Accor ...

  2. 【PAT甲级】1098 Insertion or Heap Sort (25 分)

    题意: 输入一个正整数N(<=100),接着输入两行N个数,表示原数组和经过一定次数排序后的数组.判断是经过插入排序还是堆排序并输出再次经过该排序后的数组(数据保证答案唯一). AAAAAcce ...

  3. 09-排序3 Insertion or Heap Sort (25 分)

    According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and gr ...

  4. 1098 Insertion or Heap Sort (25分)

    According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and gr ...

  5. pat1098. Insertion or Heap Sort (25)

    1098. Insertion or Heap Sort (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yu ...

  6. pat 甲级 1098. Insertion or Heap Sort (25)

    1098. Insertion or Heap Sort (25) 时间限制 100 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yu ...

  7. PAT甲题题解1098. Insertion or Heap Sort (25)-(插入排序和堆排序)

    题目就是给两个序列,第一个是排序前的,第二个是排序中的,判断它是采用插入排序还是堆排序,并且输出下一次操作后的序列. 插入排序的特点就是,前面是从小到大排列的,后面就与原序列相同. 堆排序的特点就是, ...

  8. PAT Advanced 1098 Insertion or Heap Sort (25) [heap sort(堆排序)]

    题目 According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and ...

  9. 1098. Insertion or Heap Sort (25)

    According to Wikipedia: Insertion sort iterates, consuming one input element each repetition, and gr ...

  10. PAT (Advanced Level) 1098. Insertion or Heap Sort (25)

    简单题.判断一下是插排还是堆排. #include<cstdio> #include<cstring> #include<cmath> #include<ve ...

随机推荐

  1. 【转】时间序列分析——基于R,王燕

    <时间序列分析——基于R>王燕,读书笔记 笔记: 一.检验: 1.平稳性检验: 图检验方法:     时序图检验:该序列有明显的趋势性或周期性,则不是平稳序列     自相关图检验:(ac ...

  2. CentOS防火墙命令集

    1. firewalld的基本使用 启动防火墙: systemctl start firewalld 防火墙状态: systemctl status firewalld 停止防火墙: systemct ...

  3. jsp(java server page)

    jsp的组成元素; 1, 指令 page指令 <%@ page ..........%> language---当前页面使用的语言:java import---当前页面引入的类库, 默认是 ...

  4. inclusion_tag 基本使用

    inclusion_tag的用途 inclusion_tag可以实现从后台往前端传递绑定数据的样式,一般用来动态显示模板页面中显示固定格式的数据. inclusion_tag的用法 step1: 编写 ...

  5. adb常用命令-android学习第一天

    转载出处:http://www.cnblogs.com/xiaoxuetu/ 转载来源:https://www.cnblogs.com/xiaoxuetu/p/3411214.html 平时开发and ...

  6. 数据库之Query Builder

    Yii的查询构造器提供了一个用面向对象的方法来构造SQL语句.他让开发人员可以用类的方法,属性来作为SQL语句的一部分.然后把不同部分组装到一个正确的SQL语句中,调用DAO的方法来执行.下面的例子演 ...

  7. 问题 1436: 地宫取宝 (dp)

    题目传送门 时间限制: 1Sec 内存限制: 128MB 提交: 423 解决: 94 题目描述 X  国王有一个地宫宝库.是  n  x  m  个格子的矩阵.每个格子放一件宝贝.每个宝贝贴着价值标 ...

  8. qt 如何使用私有类?

    在模块后面加上 -private 关键字,例如 widgets-private 然后 qmake 让配置文件运行一下. 在使用 QStackedLayout 布局并设置 QStackedLayout: ...

  9. C#面试 笔试题 三

    1.传入某个属性的set方法的隐含参数的名称是什么? value,它的类型和属性所声名的类型相同.   2.C#支持多重继承么? 类之间不支持,接口之间支持.类对接口叫做实现,不叫继承. 3.C#中所 ...

  10. 给定中序和后序遍历,求前序序列(C++递归方式实现)

    问题: 输入后序和中序,求中序遍历. 算法: void f2(string &pre,string in, string post) { ) //序列为空结束 return; ; //根节点 ...