LeetCode "Design Tic-Tac-Toe"

We don't have to keep a complete chess board.. just counters!

class TicTacToe {
    vector<int> cntVer;
    vector<int> cntHor;
    int cntDiag0;
    int cntDiag1;
    int _n;
public:
    /** Initialize your data structure here. */
    TicTacToe(int n) {
        cntVer.assign(n, );
        cntHor.assign(n, );
        cntDiag0 = cntDiag1 = ;
        _n = n;
    }

    /** Player {player} makes a move at ({row}, {col}).
        @param row The row of the board.
        @param col The column of the board.
        @param player The player, can be either 1 or 2.
        @return The current winning condition, can be either:
                0: No one wins.
                1: Player 1 wins.
                2: Player 2 wins. */
    int move(int row, int col, int player)
    {
        int d = player ==  ?  : -;

        cntVer[col] += d;
        if(abs(cntVer[col]) == _n) return player;

        cntHor[row] += d;
        if(abs(cntHor[row]) == _n) return player;

        if(col== row)
        {
            cntDiag0 += d;
            if(abs(cntDiag0) == _n) return player;
        }
        if ((col + row) == _n - )
        {
            cntDiag1 += d;
            if(abs(cntDiag1) == _n) return player;
        }

        return ;
    }
};