[React Router v4] Render Catch-All Routes with the Switch Component
There are many cases where we will need a catch-all route in our web applications. This can include 404-style routes when nothing is match or other use cases where where we receive an invalid route in React Router v4.
We can use 'Switch' from 'react-router-dom', what 'Switch' will do is only render the first route that matches.
To make a fallback Route, all we need to do is define a Route without any path.
<Route render={() => <h1>Page not found</h1>} />
import React from 'react';
import {
BrowserRouter as Router,
Route,
Link,
Switch,
} from 'react-router-dom'; const Links = () =>
<nav>
<Link to="/">Home</Link>
<Link to="/about">About</Link>
<Link to="/contact/xxx/xxx/xxxx/x">Contact</Link>
</nav> const App = (props) => (
<Router basename={props.path}>
<div>
<Links />
<Switch>
<Route exact path="/" render={() => <h1>Home</h1>} />
<Route path="/about" render={() => <h1>About</h1>} />
<Route render={() => <h1>Page not found</h1>} />
</Switch>
</div>
</Router>
) export default App
[React Router v4] Render Catch-All Routes with the Switch Component的更多相关文章
- [React Router v4] Render Nested Routes
With React Router v4 the entire library is built as a series of React components. That means that cr ...
- [React Router v4] Render Multiple Components for the Same Route
React Router v4 allows us to render Routes as components wherever we like in our components. This ca ...
- [React Router v4] Conditionally Render a Route with the Switch Component
We often want to render a Route conditionally within our application. In React Router v4, the Route ...
- [React Router v4] Use Regular Expressions with Routes
We can use regular expressions to more precisely define the paths to our routes in React Router v4. ...
- [Web 前端] React Router v4 入坑指南
cp from : https://www.jianshu.com/p/6a45e2dfc9d9 万恶的根源 距离React Router v4 正式发布也已经过去三个月了,这周把一个React的架子 ...
- [React Router v4] Intercept Route Changes
If a user has entered some input, or the current Route is in a “dirty” state and we want to confirm ...
- [React Router v4] Redirect to Another Page
Overriding a browser's current location without breaking the back button or causing an infinite redi ...
- [React Router v4] Parse Query Parameters
React Router v4 ignores query parameters entirely. That means that it is up to you to parse them so ...
- React Router V4发布
React Router V4 正式版发布,该版本相较于前面三个版本有根本性变化,遵循 Just Component 的 API 设计理念. 本次升级的主要变更有: 声明式 Declarative 可 ...
随机推荐
- 【Codeforces Round #451 (Div. 2) D】Alarm Clock
[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 尺取法+二分. 类似滑动窗口. 即左端点为l,右端点为r. 维护a[r]-a[l]+1总是小于等于m的就好. (大于m就右移左端点) ...
- 洛谷——P1042 乒乓球
https://www.luogu.org/problem/show?pid=1042 题目背景 国际乒联现在主席沙拉拉自从上任以来就立志于推行一系列改革,以推动乒乓球运动在全球的普及.其中11分制改 ...
- ArcGIS 点要素新增点
IFeatureLayer layer = FrmMain.m_mapControl.get_Layer(0) as IFeatureLayer; IFeatureClass featureClass ...
- 1.1selenium 介绍
1.1selenium 介绍selenium 是一个 web 的自动化测试工具,不少学习功能自动化的同学开始首选 selenium , 相因为它相比 QTP 有诸多有点:* 免费,也不用再为破解 QT ...
- 洛谷 P1691 有重复元素的排列问题
P1691 有重复元素的排列问题 题目描述 设R={r1,r2,……,rn}是要进行排列的n个元素.其中元素r1,r2,……,rn可能相同.使设计一个算法,列出R的所有不同排列. 给定n以及待排列的n ...
- synchronized和ReentrantLock区别
一.什么是sychronized sychronized是java中最基本同步互斥的手段,可以修饰代码块,方法,类. 在修饰代码块的时候需要一个reference对象作为锁的对象. 在修饰方法的时候默 ...
- HTTP详解--请求、响应、缓存
1. HTTP请求格式 做过Socket编程的人都知道,当我们设计一个通信协议时,“消息头/消息体”的分割方式是很常用的,消息头告诉对方这个消息是干什么的,消息体告诉对方怎么干.HTTP协议传输的消息 ...
- [React Intl] Format a Date Relative to the Current Date Using react-intl FormattedRelative
Given a date, we’ll use the react-intl FormattedRelative component to render a date in a human reada ...
- easyui datagrid editor checkbox 单击事件
Easyui datagrid treegrid中能够为行追加checkbox元素.比如: $('#tt').treegrid({ url:'get_data.php', idField:'id', ...
- poj 3071 Football(线段树+概率)
Football Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 2801 Accepted: 1428 Descript ...