题目链接

题意 : 就是把n个数安排在环上,要求每两个相邻的数之和一定是素数,第一个数一定是1。输出所有可能的排列。

思路 : 先打个素数表。然后循环去搜。。。。。

 //
#include <cstdio>
#include <cstring>
#include <iostream> using namespace std ; bool vis[];
int prime[] ,cs[];
int n ; void get_prime()
{
memset(prime,,sizeof(prime));
prime[] = ;
for(int i = ; i < ; i ++)
{
if(prime[i] == )
{
for(int j = i*i ; j < ; j += i)
prime[j] = ;
}
}
} void DFS(int s,int cnt)
{
if(cnt == n)
{
if(prime[cs[n]+]) return ;
for(int i = ; i <= n - ; i++)
cout << cs[i] <<" " ;
cout << cs[ n ]<<endl ;
return ;
}
for(int i = ; i <= n ; i++)
{
if(!vis[i] && !prime[s+i])
{
cs[++cnt] = i ;
vis[i] = true ;
DFS(i,cnt) ;
cnt -- ;
vis[i] = false ;
}
}
}
int main()
{
int casee = ;
get_prime() ;
while( cin >> n )
{
memset(vis,false,sizeof(vis)) ;
cout << "Case "<<casee++ <<":" << endl ;
vis[] = true ;
cs[] = ;
DFS(,) ;
cout << endl ;
}
return ;
}

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