Given a binary tree, determine if it is height-balanced.

For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.

判断一棵树是否是平衡二叉树

利用高度的答案,递归求解。

/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public boolean isBalanced(TreeNode root) { if( root == null)
return true; int left = maxDepth(root.left);
int right = maxDepth(root.right); if( left - right > 1 || right - left > 1)
return false;
return isBalanced(root.left)&&isBalanced(root.right); } public int maxDepth(TreeNode root) {
if( root == null )
return 0;
if( root.left == null && root.right == null)
return 1;
if( root.left == null)
return maxDepth(root.right)+1;
if( root.right == null)
return maxDepth(root.left)+1;
return Math.max(maxDepth(root.left),maxDepth(root.right))+1;}
}

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