AC代码

#include <cstdio>

int main() {
#ifdef ONLINE_JUDGE
#else
freopen("1.txt", "r", stdin);
#endif // ONLINE_JUDGE
char str[2][10] = {"false", "true"};
int n, tcase = 1;
scanf("%d", &n);
for(int i = 0; i < n; i++) {
int flag = 0;
long long a, b, c;
scanf("%lld%lld%lld", &a, &b, &c);
long long d = a + b;
//printf("%lld %lld %lld %lld\n", a, b, c, d);
/*if(c - b >= a) {
flag = 0;
printf("flag:%d\n", flag);
} else {
flag = 1;
printf("flag:%d\n", flag);
}*/
if(a > 0 && b > 0 && d < 0) flag = 1;
else if(a < 0 && b < 0 && d >= 0) flag = 0;
else if(d > c) flag = 1;
else flag = 0;
printf("Case #%d: %s\n", tcase++, str[flag]);
}
return 0;
}

PAT A1065 A+B and C (64bit) (20 分)的更多相关文章

  1. A1065 A+B and C (64bit) (20)(20 分)

    A1065 A+B and C (64bit) (20)(20 分) Given three integers A, B and C in [-2^63^, 2^63^], you are suppo ...

  2. PAT 甲级 1065 A+B and C (64bit) (20 分)(溢出判断)*

    1065 A+B and C (64bit) (20 分)   Given three integers A, B and C in [−], you are supposed to tell whe ...

  3. PAT (Advanced Level) Practice 1046 Shortest Distance (20 分) 凌宸1642

    PAT (Advanced Level) Practice 1046 Shortest Distance (20 分) 凌宸1642 题目描述: The task is really simple: ...

  4. PAT (Advanced Level) Practice 1042 Shuffling Machine (20 分) 凌宸1642

    PAT (Advanced Level) Practice 1042 Shuffling Machine (20 分) 凌宸1642 题目描述: Shuffling is a procedure us ...

  5. PAT (Advanced Level) Practice 1041 Be Unique (20 分) 凌宸1642

    PAT (Advanced Level) Practice 1041 Be Unique (20 分) 凌宸1642 题目描述: Being unique is so important to peo ...

  6. PAT (Advanced Level) Practice 1015 Reversible Primes (20 分) 凌宸1642

    PAT (Advanced Level) Practice 1015 Reversible Primes (20 分) 凌宸1642 题目描述: A reversible prime in any n ...

  7. PAT甲级:1136 A Delayed Palindrome (20分)

    PAT甲级:1136 A Delayed Palindrome (20分) 题干 Look-and-say sequence is a sequence of integers as the foll ...

  8. PAT乙级:1094 谷歌的招聘 (20分)

    PAT乙级:1094 谷歌的招聘 (20分) 题干 2004 年 7 月,谷歌在硅谷的 101 号公路边竖立了一块巨大的广告牌(如下图)用于招聘.内容超级简单,就是一个以 .com 结尾的网址,而前面 ...

  9. PAT乙级:1053 住房空置率 (20分)

    PAT乙级:1053 住房空置率 (20分) 题干 在不打扰居民的前提下,统计住房空置率的一种方法是根据每户用电量的连续变化规律进行判断.判断方法如下: 在观察期内,若存在超过一半的日子用电量低于某给 ...

随机推荐

  1. Linux创建删除文件和文件夹

    要想删除和创建,需要有root权限 [xwg@bogon ~]$ su root密码:[root@bogon xwg]# cd /home/a      切换到目录a[root@bogon a]# t ...

  2. Linux之GDB调试命令

    gdb启动 gdb 程序名 l 查看源代码(默认显示十行) l 文件名:行数 l 文件名:函数名 添加断点 break + 行数 (b 也行) b 15 if i == 15 条件断点 i b 查看断 ...

  3. 【转】Codeforces Round #406 (Div. 1) B. Legacy 线段树建图&&最短路

    B. Legacy 题目连接: http://codeforces.com/contest/786/problem/B Description Rick and his co-workers have ...

  4. Linux下MongoDB非正常关闭启动异常解决方法

    1.将配置信息写入一个文件中 vim mongo.conf 里面写如下内容: dbpath=/usr/local/mongodb/data/ logpath=/usr/local/mongodb/lo ...

  5. 6.RabbitMQ--事物

    RabbitMQ之消息确认机制 如何防止消息丢失? 如何防止消息是否正确送达? 有些业务场景需要我们对于消息的幂等性要求是比较高的,需要消息不能丢失,在使用RabbitMQ的时候,我们可以通过消息持久 ...

  6. 2018icpc 徐州h题

    题目大意: https://codeforces.com/gym/102012/problem/H?csrf_token=c9d0191a64a241166d54a565b1615125 区间[l , ...

  7. koa 实现上传文件

    项目目录: 1.上传单个文件 思路: (1)获取上传文件,使用 const file = ctx.request.files.file (2)我们使用 fs.createReadStream 来读取文 ...

  8. mac mysql重置root用户密码

    苹果机安装的MySQL后,设置初始密码 引子:.在苹果机上安装的MySQL之后,通过MySQLWorkBench登录本地数据连接,发现没有密码,而在安装MySQL的过程中,是没有设置过密码的其实,刚刚 ...

  9. Mysql查询某字段重复值并删除重复值

    1.查询重复值: select code,count(*) as count from hospital group by code having count>1; 该语句查询code重复值大于 ...

  10. LC 934. Shortest Bridge

    In a given 2D binary array A, there are two islands.  (An island is a 4-directionally connected grou ...