classnull100 - The 3n + 1 problem

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 The 3n + 1 problem 

Background

Problems in Computer Science are often classified as belonging to acertain class of problems (e.g., NP, Unsolvable, Recursive). In thisproblem you will be analyzing a property of an algorithm whoseclassification is not known for all possible inputs.

The Problem

Consider the following algorithm:

1. input

n

2. print n

3. if n = 1 then STOP

4. if n is odd then

5. else

6. GOTO 2

Given the input 22, the following sequence of numbers will be printed22 11 34 17 52 26 13 40 20 10 5 16 8 4 2 1

It is conjectured that the algorithm above will terminate (when a 1 isprinted) for any integralinput value. Despite the simplicity of the algorithm,it is unknown whether this conjecture is true. It has been verified,however, for all integersn such that 0 < n < 1,000,000 (and, in fact,for many more numbers than this.)

Given an input n, it is possible to determinethe number of numbers printed (including the 1). For a givenn this iscalled thecycle-length of n. In the example above, the cyclelength of 22 is 16.

For any two numbers i and j you are to determine the maximum cyclelength over all numbers betweeni andj.

    每日一道理
记不清有多少个夜晚，在我翻阅纸张的指间滑落；记不清有多少支蜡烛，在我的凝视中化为灰烬。逝者如斯，我时时刻刻会听见自己对生命承诺的余音，感到岁月的流转在渐渐稀释我的年少无知，我愿自己是一只上足了发条的时钟，在昼夜不停的流转中留下自己充实的每一刻。

The Input

The input will consist of a series of pairs of integers i and j, one pair ofintegers per line. All integers will be less than 1,000,000 and greaterthan 0.

You should process all pairs of integers and for eachpair determine the maximum cycle length over all integers between andincludingi andj.

You can assume that no operation overflows a 32-bit integer.

The Output

For each pair of input integers i and j you should output i, j,and the maximum cycle length for integers between and includingi andj. These three numbersshould be separated by at least one space with all three numbers on oneline and with one line of output for each line of input. The integersi andj must appear in the output in the same order in which theyappeared in the input and should befollowed by the maximum cycle length (on the same line).

Sample Input

1 10
100 200
201 210
900 1000

Sample Output

1 10 20
100 200 125
201 210 89
900 1000 174

#include<stdio.h>
int test(int n)
{
	int t=1;
	while(n!=1){
		if(n%2)
		{n=3*n+1;t++;}
		else
		{n/=2;t++;}
	}
	return t;
}
 
int main(void)
{
	int i,j,n;
	while(scanf("%d%d",&i,&j)==2)
	{
		int max=0;
	if(i<j){
		for(n=i;n<=j;n++)
		{
			if(test(n)>max)
				max=test(n);
		}}
	if(j<i){
		for(n=j;n<=i;n++)
		{if(test(n)>max)
		max=test(n);}
	}
	if(j==i){
		max=test(i);
				}
	printf("%d %d %d\n",i,j,max);
	}
	return 0;}

文章结束给大家分享下程序员的一些笑话语录： 话剧：程序员过沟
　　本剧内容纯属虚构，如有雷同……HEHE……俺也没办法了。
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　　这时钱某和李某也分别找到了合适的东东。钱某找到的是“钢丝绳.ocx”，安装简单，使用方便，拉出一头，对孙某说“大虾，顺手拉兄弟一把……”，于是把绳子系在沟两边的绿化树木上，踩着钢丝就过了沟。刚刚站稳就四方作揖，“小生这里有礼了”。这时一戴着黄袖圈的老太太跳了出来，抓住钱某，“破坏绿化树木，罚款XXXX元，交钱，交钱,交钱!”（老人家作双枪老太婆怒视伪军状
……钱某被逼无奈，只好边掏钱，边对着后台叫道“导演，我这可是因公牺牲，不给个烈士称号也得报销”，后台一个臭鸡蛋飞出，“叫什么叫，我这个月的粮饷还不知哪里去领呢，都什么时代了，你不下岗都不错了……”）
　　李某看着刚刚好不容易从台湾拖回来的“铝条.ZIP”

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原创文章 By
class和null
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