一、题目

  The Triangle

二、分析

  动态规划入门题。

  状态转移方程$$DP[i][j] = A[i][j] + max(DP[i-1][j], DP[i][j])$$

三、AC代码

 1 #include <cstdio>
2 #include <cstring>
3 #include <iostream>
4 #include <algorithm>
5 #include <vector>
6 #include <cmath>
7
8 using namespace std;
9 #define ll long long
10 #define Min(a,b) ((a)>(b)?(b):(a))
11 #define Max(a,b) ((a)>(b)?(a):(b))
12 const int MAXN = 100;
13 int A[MAXN + 13][MAXN + 13];
14 int Ans[2][MAXN + 13];
15
16 int main()
17 {
18 int N;
19 while(scanf("%d", &N) != EOF) {
20 memset(A, 0, sizeof(A));
21 memset(Ans, 0, sizeof(Ans));
22 for(int i = 1; i <= N; i++) {
23 for(int j = 1; j <= i; j++) {
24 scanf("%d", &A[i][j]);
25 }
26 }
27 for(int i = 1; i <= N; i++) {
28 for(int j = 1; j <= i; j++) {
29 Ans[i&1][j] = A[i][j] + Max(Ans[(i-1)&1][j-1], Ans[(i-1)&1][j]);
30 }
31 }
32 int ans = 0;
33 for(int i = 1; i <= N; i++) {
34 ans = Max(ans, Ans[N&1][i]);
35 }
36 printf("%d\n", ans);
37 }
38 return 0;
39 }

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