[LC] 243. Shortest Word Distance
Given a list of words and two words word1 and word2, return the shortest distance between these two words in the list.
Example:
Assume that words = ["practice", "makes", "perfect", "coding", "makes"].
Input: word1 =“coding”, word2 =“practice”
Output: 3
Input: word1 ="makes", word2 ="coding"
Output: 1
Note:
You may assume that word1 does not equal to word2, and word1 and word2 are both in the list.
Solution1:
O(N^2)
class Solution {
public int shortestDistance(String[] words, String word1, String word2) {
int res = words.length;
for (int i = 0; i < words.length; i++) {
if (words[i].equals(word1)) {
for (int j = 0; j < words.length; j++) {
if (words[j].equals(word2)) {
res = Math.min(res, Math.abs(i - j));
}
}
}
}
return res;
}
}
Solution2:
O(N)
class Solution {
public int shortestDistance(String[] words, String word1, String word2) {
int res = words.length;
int s1 = -1, s2 = -1;
for (int i = 0; i < words.length; i++) {
String cur = words[i];
if (cur.equals(word1)) {
s1 = i;
} else if (cur.equals(word2)) {
s2 = i;
}
if (s1 != -1 && s2 != -1) {
res = Math.min(res, Math.abs(s1 - s2));
}
}
return res;
}
}
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