HDU 5154 Harry and Magical Computer bfs
Harry and Magical Computer
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 499 Accepted Submission(s): 233
reward of being yearly outstanding magic student, Harry gets a magical
computer. When the computer begins to deal with a process, it will work
until the ending of the processes. One day the computer got n processes
to deal with. We number the processes from 1 to n. However there are
some dependencies between some processes. When there exists a
dependencies (a, b), it means process b must be finished before process
a. By knowing all the m dependencies, Harry wants to know if the
computer can finish all the n processes.
For each test case, there are two numbers n m on the first line, indicates the number processes and the number of dependencies. 1≤n≤100,1≤m≤10000
The next following m lines, each line contains two numbers a b, indicates a dependencies (a, b). 1≤a,b≤n
If the computer can finish all the process print "YES" (Without quotes).
Else print "NO" (Without quotes).
3 1
2 1
3 3
3 2
2 1
1 3
NO
#include <cstdio>
#include <cmath>
#include <cstring>
#include <ctime>
#include <iostream>
#include <algorithm>
#include <set>
#include <vector>
#include <sstream>
#include <queue>
#include <typeinfo>
#include <fstream>
typedef long long ll;
using namespace std;
//freopen("D.in","r",stdin);
//freopen("D.out","w",stdout);
#define sspeed ios_base::sync_with_stdio(0);cin.tie(0)
#define maxn 100001
const int inf=0x7fffffff; //无限大
int map[][];
int vis[];
int flag[];
int main()
{
int n,m;
while(cin>>n>>m)
{
memset(map,,sizeof(map));
memset(vis,,sizeof(vis));
memset(flag,,sizeof(flag));
int a,b;
for(int i=;i<m;i++)
{
cin>>a>>b;
map[b-][a-]=;
flag[a-]=;
}
queue<int> q;
for(int i=;i<n;i++)
{
if(flag[i]==)
{
q.push(i);
vis[i]=;
}
}
int now;
int next;
while(!q.empty())
{
now=q.front();
for(int i=;i<n;i++)
{
if(map[now][i]==)
{
if(vis[i]==)
continue;
q.push(i);
vis[i]=;
}
}
q.pop();
}
int flag1=;
for(int i=;i<n;i++)
{
if(vis[i]==)
{
flag1=;
break;
}
}
if(flag1==)
cout<<"NO"<<endl;
else
cout<<"YES"<<endl;
}
}
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