Binary Search Tree-530. Minimum Absolute Difference in BST
Given a binary search tree with non-negative values, find the minimum absolute difference between values of any two nodes.
Example:
Input: 1
\
3
/
2 Output:
1 Explanation:
The minimum absolute difference is 1, which is the difference between 2 and 1 (or between 2 and 3).
Note: There are at least two nodes in this BST.
#include <iostream>
#include <vector>
#include <limits.h>
using namespace std; class Solution {
public:
int getMinimumDifference(TreeNode* root) {
if(!root)
return ;
vector<int> InOrderArray;
getInOrderArray(InOrderArray, root);
//INT_MAX定义
//zhidao.baidu.com/question/294243885.html
int res = INT_MAX;
for(int i=; i<InOrderArray.size(); i++){//遍历数组得到相邻两个元素最小的差
if(InOrderArray[i] - InOrderArray[i-] < res)
res = InOrderArray[i] - InOrderArray[i-];
}
return res;
}
void getInOrderArray(vector<int> &InOrderArray, TreeNode* root){//通过中序遍历得到一个升序数组
if(!root)
return;
getInOrderArray(InOrderArray, root->left);
InOrderArray.push_back(root->val);
getInOrderArray(InOrderArray, root->right);
} };
int main()
{
cout << "Hello world!" << endl;
return ;
}
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