习题6-4 使用函数输出指定范围内的Fibonacci数

 #include<stdio.h>

 int fib(int n);
 void PrintFN(int m, int n);
 int main(void)
 {
     int m, n, t;

     scanf_s("%d %d %d", &m, &n, &t);
     printf("fib(%d) = %d\n", t, fib(t));
     PrintFN(m, n);

     return ;
 }

 int fib(int n)
 {
     int a, b, t;
     a = ;
     b = ;
     /*
         斐波拉契数列
     */
     for (int i = ; i <= n; i++)
     {
         t = a + b;
         a = b;
         b = t;
     }

     return b;
 }
 void PrintFN(int m, int n)
 {
     int i = ;
     int count = ;            //对符合条件的斐波拉契数进行统计
     while (fib(i) <= n)
     {
         if (fib(i) >= m)
         {
             count++;
             if (count == )
             {
                 printf("%d", fib(i));
             }
             else
             {
                 printf(" %d", fib(i));
             }
         }
         i++;
     }
     if (count == )
     {
         printf("No Fibonacci number\n");
     }
 }