Problem

A tree is a connected graph with no cycles.

A rooted tree is a tree in which one special vertex is called the root. If there is an edge between X and Y in a rooted tree, we say that Y is a child of X if X is closer to the root than Y (in other words, the shortest path from the root to X is shorter than the shortest path from the root to Y).

A full binary tree is a rooted tree where every node has either exactly 2 children or 0 children.

You are given a tree G with N nodes (numbered from 1 to N). You are allowed to delete some of the nodes. When a node is deleted, the edges connected to the deleted node are also deleted. Your task is to delete as few nodes as possible so that the remaining nodes form a full binary tree for some choice of the root from the remaining nodes.

Input

The first line of the input gives the number of test cases, TT test cases follow. The first line of each test case contains a single integer N, the number of nodes in the tree. The following N-1 lines each one will contain two space-separated integers: Xi Yi, indicating that G contains an undirected edge between Xi and Yi.

Output

For each test case, output one line containing "Case #xy", where x is the test case number (starting from 1) and y is the minimum number of nodes to delete from G to make a full binary tree.

Limits

1 ≤ T ≤ 100. 1 ≤ XiYi ≤ N Each test case will form a valid connected tree.

Small dataset

2 ≤ N ≤ 15.

Large dataset

2 ≤ N ≤ 1000.

Sample

Input    Output   
3
3
2 1
1 3
7
4 5
4 2
1 2
3 1
6 4
3 7
4
1 2
2 3
3 4
Case #1: 0
Case #2: 2
Case #3: 1

In the first case, G is already a full binary tree (if we consider node 1 as the root), so we don't need to do anything.

In the second case, we may delete nodes 3 and 7; then 2 can be the root of a full binary tree.

In the third case, we may delete node 1; then 3 will become the root of a full binary tree (we could also have deleted node 4; then we could have made 2 the root).

Google Code Jam 2014 Round 1 A:Problem B. Full Binary Tree的更多相关文章

  1. Google Code Jam 2014 Round 1 A:Problem C. Proper Shuffle

    Problem A permutation of size N is a sequence of N numbers, each between 0 and N-1, where each numbe ...

  2. Google Code Jam 2014 Round 1 A:Problem A Charging Chaos

    Problem Shota the farmer has a problem. He has just moved into his newly built farmhouse, but it tur ...

  3. Google Code Jam 2014 Round 1B Problem B

    二进制数位DP,涉及到数字的按位与操作. 查看官方解题报告 #include <cstdio> #include <cstdlib> #include <cstring& ...

  4. [C++]Store Credit——Google Code Jam Qualification Round Africa 2010

    Google Code Jam Qualification Round Africa 2010 的第一题,很简单. Problem You receive a credit C at a local ...

  5. Google Code Jam 2010 Round 1C Problem A. Rope Intranet

    Google Code Jam 2010 Round 1C Problem A. Rope Intranet https://code.google.com/codejam/contest/61910 ...

  6. [Google Code Jam (Qualification Round 2014) ] B. Cookie Clicker Alpha

    Problem B. Cookie Clicker Alpha   Introduction Cookie Clicker is a Javascript game by Orteil, where ...

  7. [Google Code Jam (Qualification Round 2014) ] A. Magic Trick

    Problem A. Magic Trick Small input6 points You have solved this input set.   Note: To advance to the ...

  8. Google Code Jam 2014 资格赛:Problem B. Cookie Clicker Alpha

    Introduction Cookie Clicker is a Javascript game by Orteil, where players click on a picture of a gi ...

  9. [C++]Saving the Universe——Google Code Jam Qualification Round 2008

    Google Code Jam 2008 资格赛的第一题:Saving the Universe. 问题描述如下: Problem The urban legend goes that if you ...

随机推荐

  1. (寒假集训)Roadblock(最短路)

    Roadblock 时间限制: 1 Sec  内存限制: 64 MB提交: 9  解决: 5[提交][状态][讨论版] 题目描述 Every morning, FJ wakes up and walk ...

  2. Qt如何学习(参考官方文档)

    Designers who are familiar with web development can start with QML 一共有四种安装工具 You have following opti ...

  3. linux下使用gcc/g++编译代码时gets函数有错误

    今天在linux中使用个g++编译一个名为myfirst.cpp的代码的时候,出现如下错误 myfirst.cpp: In function ‘int main()’:myfirst.cpp:11:2 ...

  4. 2.3多线程(java学习笔记)synchronized关键字

    一.为什么要用synchronized关键字 首先多线程中多个线程运行面临共享数据同步的问题. 多线程正常使用共享数据时需要经过以下步骤: 1.线程A从共享数据区中复制出数据副本,然后处理. 2.线程 ...

  5. Filter过滤器笔记1

    Filter:过滤器 Filter主要用于对用户请求进行预处理,也可以对HttpServletResponse进行后处理,是个典型的处理链.使用Filter的完整流程是:Filter对用户请求进行预处 ...

  6. 四. Java继承和多态4. 多态和动态绑定

    在Java中,父类的变量可以引用父类的实例,也可以引用子类的实例. 请读者先看一段代码: public class Demo { public static void main(String[] ar ...

  7. jqgrid postData setGridParam 调用多次时查询条件累加的问题--详情页查询导致的无法在新的页面中查询

    $("#btn_search").click(function () { url = "/AMEvents/GetGridJson?evtype=1"; var ...

  8. linux之openssh协议

    SSH的全称是Secure Shell,简单说来ssh是一种安全的外壳协议,用于两个计算机间安全的远程登陆,说它安全,是因为ssh采用公钥加密的机制.最开始时用作远程管理的工具是telnet,这个协议 ...

  9. DNX 概览

    来源https://docs.asp.net/en/latest/dnx/overview.html .NET Execution Environment是什么 .NET Execution Envi ...

  10. kubernetes社区项目生态概览

    原文  http://dockone.io/article/2075 作为容器集群管理技术的最流行的技术,kubernetes,自从2014在github上开源后,已经通过多个项目形成了一个生态,以下 ...