22. Generate Parentheses

 . Generate Parentheses
Given n pairs of parentheses, write a function to generate all combinations of well-formed parentheses.

For example, given n = , a solution set is:

[
  "((()))",
  "(()())",
  "(())()",
  "()(())",
  "()()()"
]
class Solution(object):
    def generateParenthesis(self, n):
        """
        :type n: int
        :rtype: List[str]
        """
        if n == 0: return ['']
        ans = []
        for c in xrange(n):
            for left in self.generateParenthesis(c):
                for right in self.generateParenthesis(n-1-c):
                    ans.append('({}){}'.format(left, right))
        return ans
class Solution(object):
    # Brute Force
    def generateParenthesis(self, n):
        def generate(A=[]):
            if len(A) == 2 * n:
                if valid(A):
                    ans.append("".join(A))
            else:
                A.append('(')
                generate(A)
                A.pop()
                A.append(')')
                generate(A)
                A.pop()

        def valid(A):
            bal = 0
            for c in A:
                if c == '(':
                    bal += 1
                else:
                    bal -= 1
                if bal < 0: return False
            return bal == 0

        ans = []
        generate()
        return ans

# Backtracking
    def generateParenthesis2(self, N):
        ans = []

        def backtrack(S='', left=0, right=0):
            if len(S) == 2 * N:
                ans.append(S)
                return
            if left < N:
                backtrack(S + '(', left + 1, right)
            if right < left:
                backtrack(S + ')', left, right + 1)

        backtrack()
        return ans

# Closure Number
    def generateParenthesis3(self, N):
        if N == 0: return ['']
        ans = []
        for c in range(N):
        # for c in xrange(N):
            for left in self.generateParenthesis(c):
                for right in self.generateParenthesis(N - 1 - c):
                    ans.append('({}){}'.format(left, right))
        return ans

sn = Solution()
print(sn.generateParenthesis(3))

print(sn.generateParenthesis2(3))

print(sn.generateParenthesis3(3))

xrange and format

22. Generate Parentheses(ML)的更多相关文章

  1. [Leetcode][Python]22: Generate Parentheses

    # -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 22: Generate Parentheseshttps://oj.leet ...

  2. 刷题22. Generate Parentheses

    一.题目说明 这个题目是22. Generate Parentheses,简单来说,输入一个数字n,输出n对匹配的小括号. 简单考虑了一下,n=0,输出"";n=1,输出" ...

  3. 【LeetCode】22. Generate Parentheses (2 solutions)

    Generate Parentheses Given n pairs of parentheses, write a function to generate all combinations of ...

  4. 22. Generate Parentheses (recursion algorithm)

    Given n pairs of parentheses, write a function to generate all combinations of well-formed parenthes ...

  5. [LeetCode] 22. Generate Parentheses 生成括号

    Given n pairs of parentheses, write a function to generate all combinations of well-formed parenthes ...

  6. LeetCode 22. Generate Parentheses

    Given n pairs of parentheses, write a function to generate all combinations of well-formed parenthes ...

  7. 22. Generate Parentheses——本质:树,DFS求解可能的path

    Given n pairs of parentheses, write a function to generate all combinations of well-formed parenthes ...

  8. Java [leetcode 22]Generate Parentheses

    题目描述: Given n pairs of parentheses, write a function to generate all combinations of well-formed par ...

  9. leetcode@ [22]Generate Parentheses (递归 + 卡特兰数)

    https://leetcode.com/problems/generate-parentheses/ Given n pairs of parentheses, write a function t ...

随机推荐

  1. python之if使用方法举例

    if使用方法举例: import random #随机生成1-100的整数 n = random.randint(1, 100) if n > 50: print(n, "> 5 ...

  2. How to split DMG on macOS

    hdiutil segment /users/test/test1.dmg -segmentsize 4000m -o /users/test/test2.dmg

  3. 使用 Travis CI 自动部署 Hexo 站点至 GitHub Pages

    Hexo 与 GitHub Pages 安装配置请参考:Hexo 与 GitHub Pages 本文源码与生成的静态文件在同一项目下,源码在 source 分支,静态文件在 master 分支 新增 ...

  4. axis函数

    axis函数 axis([xmin xmax ymin ymax]) 用来标注输出的图线的最大值最小值. MATLAB中坐标系的设置函数   MATLAB 函数 axis([XMIN XMAX YMI ...

  5. User Authentication with Angular and ASP.NET Core

    User authentication is a fundamental part of any meaningful application. Unfortunately, implementing ...

  6. bzoj2152-[国家集训队]聪聪可可

    Description 聪聪和可可是兄弟俩,他们俩经常为了一些琐事打起来,例如家中只剩下最后一根冰棍而两人都想吃.两个人都想玩儿电脑(可是他们家只有一台电脑)--遇到这种问题,一般情况下石头剪刀布就好 ...

  7. Mysql(Mariadb)数据库主从复制

    Mysql主从复制的实现原理图大致如下: MySQL之间数据复制的基础是以二进制日志文件(binary log file)来实现的,一台MySQL数据库一旦启用二进制日志后,其作为master,它数据 ...

  8. memcached安装报错 error while loading shared libraries: libevent-2.0.so.5: cannot open shared object file: No such file or directory解决

    我是从其他服务器scp来的memcached(~~~整个文件夹的那种,windows用多了的后遗症) 在准备运行 ./memcached -d -u root -l localhost -m 800 ...

  9. Luogu5205 【模板】多项式开根(NTT+多项式求逆)

    https://www.cnblogs.com/HocRiser/p/8207295.html 安利! 写NTT把i<<=1写成了i<<=2,又调了一年.发现我的日常就是数组开 ...

  10. 三:C#对象转换Json时的一些高级(特殊)设置;

    导航目录: Newtonsoft.Json 概述 一:Newtonsoft.Json 支持序列化与反序列化的.net 对象类型:    二:C#对象.集合.DataTable与Json内容互转示例: ...