PAT_A1154#Vertex Coloring
Source:
Description:
A proper vertex coloring is a labeling of the graph's vertices with colors such that no two vertices sharing the same edge have the same color. A coloring using at most k colors is called a (proper) k-coloring.
Now you are supposed to tell if a given coloring is a proper k-coloring.
Input Specification:
Each input file contains one test case. For each case, the first line gives two positive integers N and M(both no more than 1), being the total numbers of vertices and edges, respectively. Then M lines follow, each describes an edge by giving the indices (from 0 to N−1) of the two ends of the edge.
After the graph, a positive integer K (≤ 100) is given, which is the number of colorings you are supposed to check. Then K lines follow, each contains N colors which are represented by non-negative integers in the range of int. The i-th color is the color of the i-th vertex.
Output Specification:
For each coloring, print in a line
k-coloring
if it is a properk
-coloring for some positivek
, orNo
if not.
Sample Input:
10 11
8 7
6 8
4 5
8 4
8 1
1 2
1 4
9 8
9 1
1 0
2 4
4
0 1 0 1 4 1 0 1 3 0
0 1 0 1 4 1 0 1 0 0
8 1 0 1 4 1 0 5 3 0
1 2 3 4 5 6 7 8 8 9
Sample Output:
4-coloring
No
6-coloring
No
Keys:
- 图的存储和遍历
- set(C++ STL)
- 散列(Hash)
Attenrion:
- 矩阵存储图,规模小于10^3
- 对于多组测试用例的输入,要注意统计值和哈希函数的初始化(出题老师太坏了,测试用例即使不初始化也是对的-,-)
Code:
/*
Data: 2019-08-02 21:08:29
Problem: PAT_A1154#Vertex Coloring
AC: 17:39 题目大意:
判断图中相连的顶点是否共色
*/
#include<cstdio>
#include<set>
using namespace std;
const int M=1e4+;
struct node
{
int u,v;
}grap[M];
int color[M]; int main()
{
#ifdef ONLINE_JUDGE
#else
freopen("Test.txt", "r", stdin);
#endif // ONLINE_JUDGE int n,m,k;
scanf("%d%d", &m,&n);
for(int i=; i<n; i++)
scanf("%d%d", &grap[i].u,&grap[i].v);
scanf("%d", &k);
while(k--)
{
set<int> mp;
for(int i=; i<m; i++)
{
scanf("%d", &color[i]);
mp.insert(color[i]);
}
for(int i=; i<n; i++)
{
if(color[grap[i].u] == color[grap[i].v])
{
mp.clear();
break;
}
}
if(mp.size())
printf("%d-coloring\n", mp.size());
else
printf("No\n");
} return ;
}
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