CF #374 (Div. 2) D. 贪心，优先队列或set

1、CF #374 (Div. 2)   D. Maxim and Array

2、总结：按绝对值最小贪心下去即可

3、题意：对n个数进行+x或-x的k次操作，要使操作之后的n个数乘积最小。

（1）优先队列

#include<bits/stdc++.h>
#define F(i,a,b) for (int i=a;i<b;i++)
#define FF(i,a,b) for (int i=a;i<=b;i++)
#define mes(a,b) memset(a,b,sizeof(a))
#define INF 0x3f3f3f3f
#define LL long long
using namespace std;
const int N=,MAX=;
 
struct Num
{
    int i;
    LL val;     //一开始用int，一直挖9
    bool operator <(const Num &a1)const {
        return abs(val)>abs(a1.val);
    }
}a[N];
 
int main()
{
    int n,k,num1;
    LL x;
    while(~scanf("%d%d%lld",&n,&k,&x))
    {
        priority_queue<Num>Q;
        num1=;
        F(i,,n){
            scanf("%lld",&a[i].val);
            a[i].i=i;
            Q.push(a[i]);
            if(a[i].val<)num1++;
        }
        Num ans;
        while(k--){
            ans=Q.top();Q.pop();
            if(num1%) {
                if(ans.val==){
                    ans.val+=x;
                }else if(ans.val>){
                    ans.val+=x;
                }else {
                    ans.val-=x;
                }
            }else {
                if(ans.val==){
                    ans.val-=x;
                    if(ans.val<)num1++;
                }else if(ans.val>){
                    ans.val-=x;
                    if(ans.val<)num1++;
                }else {
                    ans.val+=x;
                    if(ans.val>=)num1--;
                }
 
            }
            a[ans.i]=ans;
            Q.push(ans);
        }
        printf("%lld",a[].val);
        F(i,,n)printf(" %lld",a[i].val);
        puts("");
 
    }
 
    return ;
}

（2）set

#include<bits/stdc++.h>
#define F(i,a,b) for (int i=a;i<b;i++)
#define FF(i,a,b) for (int i=a;i<=b;i++)
#define mes(a,b) memset(a,b,sizeof(a))
#define INF 0x3f3f3f3f
#define LL long long
using namespace std;
const int N=,MAX=;
 
int main()
{
    int n,k,flag;
    LL x,a[N];
    while(~scanf("%d%d%lld",&n,&k,&x))
    {
        flag=;
        set<pair<LL,int> >S;
        F(i,,n){
            scanf("%lld",&a[i]);
            if(a[i]<)flag^=;
            S.insert(make_pair(abs(a[i]),i));
 
        }
        while(k--){
            int pos=S.begin()->second;S.erase(S.begin());
            if(flag){
                if(a[pos]>=)a[pos]+=x;
                else a[pos]-=x;
            }else {
                if(a[pos]>=){
                    a[pos]-=x;
                    if(a[pos]<)flag^=;
                }
                else {
                    a[pos]+=x;
                    if(a[pos]>=)flag^=;
                }
            }
            S.insert(make_pair(abs(a[pos]),pos));
        }
        cout<<a[];
        F(i,,n)printf(" %lld",a[i]);
        cout<<endl;
 
    }
 
    return ;
}