HDU 1228 字符串到数字的转化

一道水题，练练字符串的输入输出

 #include <cstdio>
 #include <cstring>
 
 using namespace std;
 char s1[] , s2[];
 
 int get_num(char *s)
 {
     if(s[] == 'z') return ;
     else if(s[] == 'o') return ;
     else if(s[] == 't' && s[] == 'w') return ;
     else if(s[] == 't' && s[] == 'h') return ;
     else if(s[] == 'f' && s[] == 'o') return ;
     else if(s[] == 'f' && s[] == 'i') return ;
     else if(s[] == 's' && s[] == 'i') return ;
     else if(s[] == 's' && s[] == 'e') return ;
     else if(s[] == 'e') return ;
     else if(s[] == 'n') return ;
 }
 
 int main()
 {
   //  freopen("a.in" , "r" , stdin);
     while()
     {
         int n1 = ;
         while(scanf("%s" , s1)){
             if(s1[] == '+') break;
             n1 = n1*+get_num(s1);
         }
         int n2 = ;
         while(scanf("%s" , s2)){
             if(s2[] == '=') break;
             n2 = n2*+get_num(s2);
         }
         if(n1 == n2 && n1 == )
             break;
         printf("%d\n" , n1+n2);
     }
     return ;
 }