leetcode面试准备: Substring with Concatenation of All Words

1 题目

You are given a string, s, and a list of words, words, that are all of the same length. Find all starting indices of substring(s) in s that is a concatenation of each word in words exactly once and without any intervening characters.

For example, given:

s: "barfoothefoobarman"

words: ["foo", "bar"]

You should return the indices: [0,9].

(order does not matter).

接口:public List<Integer> findSubstring(String s, String[] words)

2 思路

题意

找出可以连接成words里面单词的组合，输出子字符串的起始位置。

复杂度: Time

leetcode面试准备: Substring with Concatenation of All Words的更多相关文章

  1. [Leetcode][Python]30: Substring with Concatenation of All Words

    # -*- coding: utf8 -*-'''__author__ = 'dabay.wang@gmail.com' 30: Substring with Concatenation of All ...

  2. LeetCode HashTable 30 Substring with Concatenation of All Words

    You are given a string, s, and a list of words, words, that are all of the same length. Find all sta ...

  3. leetcode@ [30/76] Substring with Concatenation of All Words & Minimum Window Substring (Hashtable, Two Pointers)

    https://leetcode.com/problems/substring-with-concatenation-of-all-words/ You are given a string, s, ...

  4. 【一天一道LeetCode】#30. Substring with Concatenation of All Words

    注:这道题之前跳过了,现在补回来 一天一道LeetCode系列 (一)题目 You are given a string, s, and a list of words, words, that ar ...

  5. 【LeetCode】30. Substring with Concatenation of All Words

    You are given a string, s, and a list of words, words, that are all of the same length. Find all sta ...

  6. leetcode python 030 Substring with Concatenation of All Words

    ## 您将获得一个字符串s,以及一个长度相同单词的列表.## 找到s中substring(s)的所有起始索引,它们只包含所有单词,## eg:s: "barfoothefoobarman&q ...

  7. LeetCode:Substring with Concatenation of All Words （summarize）

    题目链接 You are given a string, S, and a list of words, L, that are all of the same length. Find all st ...

  8. [LeetCode] 30. Substring with Concatenation of All Words 解题思路 - Java

    You are given a string, s, and a list of words, words, that are all of the same length. Find all sta ...

  9. leetCode 30.Substring with Concatenation of All Words (words中全部子串相连) 解题思路和方法

    Substring with Concatenation of All Words You are given a string, s, and a list of words, words, tha ...

随机推荐

  1. java 静态方法

    在使用java的时候,你会发现,有些对象,需要new ,有些则不需要时,比如Math类 ); 如果你查看源码就会大致的发现,里面的属性和方法都是静态的: public static double si ...

  2. webrtc学习——RTCPeerConnection

    The RTCPeerConnection interface represents a WebRTC connection and handles efficient streaming of da ...

  3. JavaScript之Function类型

    1. 创建方式 //1.函数声明 function sum(num1,num2){ return num1+num2; } //2.函数表达式 var sum = function(num1,num2 ...

  4. OpenGL_Qt学习笔记之_05(纹理映射)（转）

    转自:http://www.cnblogs.com/tornadomeet/archive/2012/08/24/2654719.html 纹理映射基础知识 什么叫纹理映射,一开始我也不明白,感觉这个 ...

  5. Gradle实战教程之依赖管理

    这是从我个人网站中复制过来的,原文地址:http://coolshell.info/blog/2015/05/gradle-dependency-management.html,转载请注明出处. 简要 ...

  6. 九度OJ 1373 整数中1出现的次数（从1到n整数中1出现的次数）

    题目地址:http://ac.jobdu.com/problem.php?pid=1373 题目描述: 亲们!!我们的外国友人YZ这几天总是睡不好,初中奥数里有一个题目一直困扰着他,特此他向JOBDU ...

  7. .net日志专用

    一个简单的.net写日志方法 - 可能的改进点 昨天有个朋友在评论的时候问我如下代码在web开发中有什么问题 public void Log(string msg) { System.IO.File. ...

  8. 7种基本排序算法的Java实现

    7种基本排序算法的Java实现 转自我的Github 以下为7种基本排序算法的Java实现,以及复杂度和稳定性的相关信息. 以下为代码片段,完整的代码见Sort.java 插入排序 /** * 直接插 ...

  9. ES6笔记-字符串方法

    字符串检索方法,indexOf(searchValue,fromIndex)//参数1必需,检索查询的字符串或者值,参数2选题,规定检索的起始位置,不设置默认从0开始 indexOf()方法返回检索字 ...

  10. Spring Cloud App(Service) Pom示例

    都配对了才能找到jar包(无法访问外网时是如何配的?) parent dependencyManageMent repositories plugInRepositories <groupId& ...