322. Coin Change
动态规划里例题,硬币问题。
p[i] = dp[i - coin[j]] + 1;
注意i < coin[j] dp[i-coin[j]]无解都要跳过。
public class Solution
{
public int coinChange(int[] coins, int amount)
{
int[] dp = new int[amount+1];
Arrays.fill(dp,Integer.MAX_VALUE);
//dp[i] = dp[i - coin[j]] + 1;
dp[0] = 0;
for(int i = 0; i <= amount; i++)
{
for(int j = 0; j < coins.length;j++)
{
if(i < coins[j] || dp[i-coins[j]] == Integer.MAX_VALUE) continue;
dp[i] = Math.min(dp[i],dp[i - coins[j]]+1);
}
}
if(dp[amount] == Integer.MAX_VALUE) return -1;
else return dp[amount];
}
}
第一次看到动态规划觉得好神奇。。
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