半平面的交,二分的方法;

 #include<cstdio>
#include<algorithm>
#include<cmath>
#define eps 1e-6
using namespace std; int dcmp(double x)
{
return fabs(x) < eps ? : (x > ? : -);
} struct Point
{
double x;
double y;
Point(double x = , double y = ):x(x), y(y) {}
};
typedef Point Vector; Vector operator + (Point A, Point B)
{
return Vector(A.x + B.x, A.y + B.y);
} Vector operator - (Point A, Point B)
{
return Vector(A.x - B.x, A.y - B.y);
} Vector operator * (Point A, double p)
{
return Vector(A.x * p, A.y * p);
} Vector operator / (Point A, double p)
{
return Vector(A.x / p, A.y / p);
}
double dot(Point a,Point b)
{
return a.x*b.x+a.y*b.y;
}
double cross(Point a,Point b)
{
return a.x*b.y-a.y*b.x;
} Vector nomal(Vector a)
{
double l=sqrt(dot(a,a));
return Vector(-a.y/l,a.x/l);
} struct line
{
Point p;
Vector v;
double ang;
line() {}
line(Point p,Vector v):p(p),v(v)
{
ang=atan2(v.y,v.x);
}
bool operator<(const line &t)const
{
return ang<t.ang;
}
}; bool onleft(line l,Point p)
{
return (cross(l.v,p-l.p)>);
} Point getintersection(line a,line b)
{
Vector u=a.p-b.p;
double t=cross(b.v,u)/cross(a.v,b.v);
return a.p+a.v*t;
} int halfplanintersection(line *l,int n,Point *poly)
{
sort(l,l+n);
int first,last;
Point *p=new Point[n];
line *q=new line[n];
q[first=last=]=l[];
for(int i=; i<n; i++)
{
while(first<last && !onleft(l[i],p[last-]))last--;
while(first<last && !onleft(l[i],p[first]))first++;
q[++last]=l[i];
if(fabs(cross(q[last].v,q[last-].v))<eps)
{
last--;
if(onleft(q[last],l[i].p))q[last]=l[i];
}
if(first<last)p[last-]=getintersection(q[last-],q[last]);
}
while(first<last && !onleft(q[first],p[last-]))last--;
if((last-first )<=)return ;
p[last]=getintersection(q[last],q[first]);
int m=;
for(int i=first; i<=last; i++)poly[m++]=p[i];
return m;
} Point p[],poly[];
line l[];
Point v[],v2[];
int main()
{
int n,m;
double x,y;
while(scanf("%d",&n)&&n)
{
for(int i=; i<n; i++)
{
scanf("%lf%lf",&x,&y);
p[i]=Point(x,y);
}
for(int i=; i<n; i++)
{
v[i]=p[(i+)%n]-p[i];
v2[i]=nomal(v[i]);
}
double left=0.0,right=20000.0;
while(right-left>eps)
{
double mid=(left+right)/;
for(int i=; i<n; i++)
l[i]=line(p[i]+v2[i]*mid,v[i]);
m=halfplanintersection(l,n,poly);
if(!m)right=mid;
else left=mid;
}
printf("%.6lf\n",left);
}
return ;
}

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