Perl monks 的 快速回复
| on Jun 20, 2019 at 11:39 UTC ( #11101620=perlquestion: print w/replies, xml ) | Need Help?? |
jimyokl has asked for the wisdom of the Perl Monks concerning the following question:
I just started learning Perl for several days.I sow some codes below, what is the type of $data, is it array or a hash? There are so many nests. Thanks.
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| Re: what is the variable type of $data = { by Anonymous Monk on Jun 20, 2019 at 12:06 UTC |
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In this piece of code, { There are two syntactically different ways to access a hash by reference: $data->{$key} (the arrow operator, ->) and ${$data}{$key} (wrap the reference in {} - where you could also put the name of the hash if it had a name). Both ways take $data, try to dereference it, access the underlying hash and return the scalar value referenced by key $key. If $data does not contain a hash reference, an exception will be raised (but if $data is undef, an anonymous hash may be created automatically and a reference to it may be stored inside $data - see autovivification). See perlreftut and perldsc for more info. |
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Re^2: what is the variable type of $data = { by you!!! on Jun 20, 2019 at 12:14 UTC |
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Reputation: 1
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Re: what is the variable type of $data = { |
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++ To AnonyMonk, $data is a reference to a hash, that itself contains hashrefs (eg the value at a10 is a hashref). One way to test for that is to use ref, that will return 'HASH' in this case, or Scalar::Util's reftype, that is guarranted to always return 'HASH' even if the reference is blessed (turned into an object). So you can check that ref $data eq 'HASH' |
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Re^2: what is the variable type of $data = { by you!!! on Jun 20, 2019 at 12:21 UTC |
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Reputation: 0
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Re: what is the variable type of $data = { |
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You might be confused because hashes and arrays have to incarnations in Perl
Hashes consist of key => value "string" => scalar
To realize nested hashes you need to put a hash reference into the value slot. That's what's happening here. See perldsc for more examples. HTH :) Cheers Rolf °) my wording |
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what is the variable type of $data = {by you!!! |
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