Given numRows, generate the first numRows of Pascal's triangle.

For example, given numRows = 5,
Return

[
[1],
[1,1],
[1,2,1],
[1,3,3,1],
[1,4,6,4,1]
] 产生杨辉三角,比较简单,注意几个边界条件:
 class Solution {
public:
vector<vector<int> > generate(int numRows) {
vector<int> vi;
vector<vector<int> > ans;
int i,j;
vi.push_back();
ans.clear(); // 注意初始化
9 if(numRows<=0) return ans;
10 if(1==numRows)
11 {
12 ans.push_back(vi);
13 return ans;
14 }
15 if(2==numRows)
16 {
17 ans.push_back(vi);
18 vi.push_back(1);
19 ans.push_back(vi);
20 return ans;
21 } ans.push_back(vi);
vi.push_back();
ans.push_back(vi);
for(i=;i<numRows;i++)
{
vi.clear();
vi.push_back();
for(j=;j<i;j++)
{
vi.push_back(ans[i-][j-]+ans[i-][j]);
}
vi.push_back();
ans.push_back(vi);
}
return ans;
}
};

转载请注明出处: http://www.cnblogs.com/double-win/ 谢谢!

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