Just a Hook

Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 15129    Accepted Submission(s): 7506

Problem Description
In the game of DotA, Pudge’s meat hook is actually the most horrible thing for most of the heroes. The hook is made up of several consecutive metallic sticks which are of the same length.

Now Pudge wants to do some operations on the hook.

Let us number the consecutive metallic sticks of the hook from 1 to N. For each operation, Pudge can change the consecutive metallic sticks, numbered from X to Y, into cupreous sticks, silver sticks or golden sticks.
The total value of the hook is calculated as the sum of values of N metallic sticks. More precisely, the value for each kind of stick is calculated as follows:

For each cupreous stick, the value is 1.
For each silver stick, the value is 2.
For each golden stick, the value is 3.

Pudge wants to know the total value of the hook after performing the operations.
You may consider the original hook is made up of cupreous sticks.

 
Input
The input consists of several test cases. The first line of the input is the number of the cases. There are no more than 10 cases.
For each case, the first line contains an integer N, 1<=N<=100,000, which is the number of the sticks of Pudge’s meat hook and the second line contains an integer Q, 0<=Q<=100,000, which is the number of the operations.
Next Q lines, each line contains three integers X, Y, 1<=X<=Y<=N, Z, 1<=Z<=3, which defines an operation: change the sticks numbered from X to Y into the metal kind Z, where Z=1 represents the cupreous kind, Z=2 represents the silver kind and Z=3 represents the golden kind.
 
Output
For each case, print a number in a line representing the total value of the hook after the operations. Use the format in the example.
 
Sample Input
1
10
2
1 5 2
5 9 3
 
Sample Output
Case 1: The total value of the hook is 24.
 
Source
 
Recommend
wangye   |   We have carefully selected several similar problems for you:  1542 1394 2795 1255 1828 

 
  线段树,区间更新
  与点更新不同的是,这是对某一区间的值进行更新。线段树每一个节点代表一个区间,节点中存储的值代表这个区间的金属成色(1-铜,2-银,3-金),如果这个区间还有其它成色,即杂色金属,则值为-1。
  代码
 #include <stdio.h>
#define MAXSIZE 100000
struct Node{
int left,right;
int n;
};
Node a[MAXSIZE*+];
void Init(Node a[],int L,int R,int d) //初始化线段树
{
if(L==R){ //当前节点没有儿子节点,即递归到叶子节点。递归出口
a[d].left = L;
a[d].right = R;
a[d].n = ;
return ;
} int mid = (L+R)/; //初始化当前节点
a[d].left = L;
a[d].right = R;
a[d].n = ; Init(a,L,mid,d*); //递归初始化当前节点的儿子节点
Init(a,mid+,R,d*+); }
void Update(Node a[],int L,int R,int d,int x) //对区间[L,R]插入值x,从节点d开始更新。
{
if(a[d].n==x) //颜色相符,直接返回
return ;
if(L==a[d].left && R==a[d].right){ //插入的区间匹配,则直接修改该区间值
a[d].n = x;
return ;
}
if(a[d].n!=-){ //是纯色
a[*d].n=a[*d+].n=a[d].n;
a[d].n=-;
}
int mid = (a[d].left + a[d].right)/;
if(R<=mid){ //中点在右边界R的右边,则应该插入到左儿子
Update(a,L,R,d*,x);
}
else if(mid<L){ //中点在左边界L的左边,则应该插入到右儿子
Update(a,L,R,d*+,x);
}
else { //否则,中点在待插入区间的中间
Update(a,L,mid,d*,x);
Update(a,mid+,R,d*+,x);
}
}
int Query(Node a[],int L,int R,int d) //查询区间[L,R]的值,从节点d开始查询
{
if(a[d].n==-) //杂色
return Query(a,L,R,*d) + Query(a,L,R,*d+);
else
return (a[d].right - a[d].left + )*a[d].n;
}
int main()
{
int Case,i,T,n,q,A,B,x;
scanf("%d",&T); for(Case=;Case<=T;Case++){
scanf("%d%d",&n,&q); Init(a,,n,); //初始化 //for(i=1;i<=n;i++){ //输入
// Update(a,i,i,1,1);
//} for(i=;i<=q;i++){
scanf("%d%d%d",&A,&B,&x);
Update(a,A,B,,x);
}
printf("Case %d: The total value of the hook is %d.\n",Case,Query(a,,n,));
}
return ;
}

Freecode : www.cnblogs.com/yym2013

hdu 1698:Just a Hook(线段树,区间更新)的更多相关文章

  1. (简单) HDU 1698 Just a Hook , 线段树+区间更新。

    Description: In the game of DotA, Pudge’s meat hook is actually the most horrible thing for most of ...

  2. HDU 1698 Just a Hook(线段树区间更新查询)

    描述 In the game of DotA, Pudge’s meat hook is actually the most horrible thing for most of the heroes ...

  3. HDU 1698 Just a Hook 线段树区间更新、

    来谈谈自己对延迟标记(lazy标记)的理解吧. lazy标记的主要作用是尽可能的降低时间复杂度. 这样说吧. 如果你不用lazy标记,那么你对于一个区间更新的话是要对其所有的子区间都更新一次,但如果用 ...

  4. HDU 1698 Just a Hook(线段树 区间替换)

    Just a Hook [题目链接]Just a Hook [题目类型]线段树 区间替换 &题解: 线段树 区间替换 和区间求和 模板题 只不过不需要查询 题里只问了全部区间的和,所以seg[ ...

  5. [HDU] 1698 Just a Hook [线段树区间替换]

    Just a Hook Time Limit: 4000/2000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Total ...

  6. HDU 1698 Just a Hook(线段树区间替换)

    题目地址:pid=1698">HDU 1698 区间替换裸题.相同利用lazy延迟标记数组,这里仅仅是当lazy下放的时候把以下的lazy也所有改成lazy就好了. 代码例如以下: # ...

  7. hdu - 1689 Just a Hook (线段树区间更新)

    http://acm.hdu.edu.cn/showproblem.php?pid=1698 n个数初始每个数的价值为1,接下来有m个更新,每次x,y,z 把x,y区间的数的价值更新为z(1<= ...

  8. HDU.1689 Just a Hook (线段树 区间替换 区间总和)

    HDU.1689 Just a Hook (线段树 区间替换 区间总和) 题意分析 一开始叶子节点均为1,操作为将[L,R]区间全部替换成C,求总区间[1,N]和 线段树维护区间和 . 建树的时候初始 ...

  9. HDU.1556 Color the ball (线段树 区间更新 单点查询)

    HDU.1556 Color the ball (线段树 区间更新 单点查询) 题意分析 注意一下pushdown 和 pushup 模板类的题还真不能自己套啊,手写一遍才行 代码总览 #includ ...

  10. Just a Hook 线段树 区间更新

    Just a Hook In the game of DotA, Pudge’s meat hook is actually the most horrible thing for most of t ...

随机推荐

  1. idea 排除编译文件,恢复编译

  2. php返回json数组

    1.后端 //处理json数组中文问题 function arrayRecursive(&$array, $function, $apply_to_keys_also = false) { s ...

  3. 一个iOS 框架介绍:MKNetworkKit

    http://blog.csdn.net/kmyhy/article/details/12276287 http://blog.csdn.net/mobailwang/article/details/ ...

  4. MapReduce 程序运行报错 java.lang.ClassNotFoundException解决方法

    在创建自定义的Mapper时候,编译正确,但上传到集群执行时出现错误: 11/16/05 22:53:16 INFO mapred.JobClient: Task Id : attempt_20111 ...

  5. ACM/ICPC 之 DP-整数划分问题初探 (POJ1221)

    写下这道题的原因很简单= =,因为这一题的状态转移方程不好找,另一方面,我看到很多针对这一题写的解题报告都把累加状态说得模棱两可,甚至直接说成了一个单一状态,弄得本是菜鸟的我硬生生折磨了一上午画了几个 ...

  6. markdown 基本语法

    代码块: ```console.log(1);```--- 标题: # h1## h2### h3 --- 粗斜体: *斜体***粗体*****粗斜体*** --- 强调:`强调` --- 链接:[百 ...

  7. gtk+-3.21.4 static build step in windows XP

    In recent days the weather is very hot Unable to sleep properly Under the state of daze research gtk ...

  8. ffmpeg-20160515-git-bin

    ESC 退出 0 进度条开关 1 屏幕原始大小 2 屏幕1/2大小 3 屏幕1/3大小 4 屏幕1/4大小 S 下一帧 [ -2秒 ] +2秒 ; -1秒 ' +1秒 下一个帧 -> -5秒 f ...

  9. winrt反射

    第一步引用扩展类. using System.Reflection.IntrospectionExtensions; 第二步反射. gridView是我定义的GridView控件.ItemClick是 ...

  10. .NET中的CTS、CLS和CLR

    在学习.NET的过程中,都会不可避免地接触到这三个概念,那么这三个东西是什么以及它们之间的关系是怎样的呢?我们在学习的过程中可能比较过多的会去关注CLR,因为CLR是.NET Framework的核心 ...