pid=4775" target="_blank" style="">题目链接:hdu 4775 Infinite Go

题目大意:两个人下围棋,总共走了n步。黑棋和白棋交替走,假设一片棋的上下左右被封死,那么该片棋子就会被吃掉,问说最后黑白棋各剩多少个。

解题思路:比較恶心的模拟题,相邻同样色的棋子要用并查集连接。而且要记录每片棋子还剩的空格数。假设空格数为0的话说明该片棋子被其它颜色围住,则要剔除掉,不且将相邻的位置不同色的棋空格数加1。主要是细节上的问题。

例子

8

7

5 5

4 5

3 5

3 4

4 4

3 3

4 6

18

1 3

1 4

2 2

1 5

2 4

2 3

3 1

3 2

3 5

3 4

4 2

4 3

4 4

1 6

5 3

3 3

1 10

3 3

12

1 2

1 1

2 1

2 2

1 3

3 1

2 3

1 4

3 2

3 3

4 2

2 4

4

1 1

1 2

2 2

2 1

4

2000000000 2000000000

2000000000 1999999999

1999999999 1999999999

1999999999 2000000000

8

1 2

4 1

2 1

4 2

2 3

4 3

3 2

2 2

17

1 3

1 4

2 2

1 5

2 4

2 3

3 1

3 2

3 5

3 4

4 2

4 3

4 4

1 6

5 3

30 30

3 3

17

1 3

1 4

2 2

1 5

2 4

2 3

3 1

3 2

3 5

3 4

4 2

3 3

4 4

1 6

5 3

4 3

100 100

答案

4 2

9 4

6 4

1 2

2 2

4 3

9 4

9 3

#include <cstdio>
#include <cstring>
#include <vector>
#include <map>
#include <queue>
#include <algorithm> using namespace std;
const int maxn = 1e4;
const int INF = 2*1e9+10;
const int dir[4][2] = { {0, 1}, {0, -1}, {1, 0}, {-1, 0} };
typedef pair<int, int> pii; int N, Nw, Nb, X[maxn+5], Y[maxn+5], f[maxn+5], c[maxn+5];
map<pii, int> R; void init () {
scanf("%d", &N); Nw = N / 2;
Nb = N - Nw; R.clear();
for (int i = 0; i < N; i++) {
f[i] = i;
c[i] = 0;
}
} inline int bit (int x) {
return x&1;
} int getfar (int x) {
return f[x] == x ? x : f[x] = getfar(f[x]);
} inline bool isEmpty (int x, int y) {
if (x <= 0 || y <= 0 || x >= INF || y >= INF)
return false;
if (R.count(make_pair(x, y)))
return false;
return true;
} inline int count_empty (pii u) {
int cnt = 0;
for (int i = 0; i < 4; i++) {
int x = u.first + dir[i][0];
int y = u.second + dir[i][1];
if (isEmpty(x, y))
cnt++;
}
return cnt;
} inline void link_board (int x, int y) {
int fx = getfar(x);
int fy = getfar(y); f[fy] = fx;
c[fx] += c[fy];
/**/
c[fx]--;
} int del_board (int col, int x, int y) {
int cnt = 1;
pii u = make_pair(x, y);
queue<pii> que;
que.push(u); f[R[u]] = R[u];
R.erase(u); while (!que.empty()) {
u = que.front();
que.pop(); for (int i = 0; i < 4; i++) {
int p = u.first + dir[i][0];
int q = u.second + dir[i][1]; if (p <= 0 || p >= INF || q <= 0 || q >= INF)
continue; pii v = make_pair(p, q);
if (!R.count(v))
continue; int set = R[v]; if (bit(set) != col) {
int k = getfar(set);
c[k]++;
continue;
} f[R[v]] = R[v];
R.erase(v);
cnt++;
que.push(v);
}
}
return cnt;
} void del_empty (int k) {
int fk = getfar(k);
c[fk]--; if (c[fk] == 0) {
int set = bit(fk);
int cnt = del_board(set, X[fk], Y[fk]);
if (set)
Nw -= cnt;
else
Nb -= cnt;
}
} void solve () { for (int i = 0; i < N; i++) {
scanf("%d%d", &X[i], &Y[i]);
pii v = make_pair(X[i], Y[i]);
c[i] = count_empty(v);
R[v] = i; for (int j = 0; j < 4; j++) {
int p = X[i] + dir[j][0];
int q = Y[i] + dir[j][1]; if (p <= 0 || q <= 0 || p >= INF || q >= INF)
continue; pii u = make_pair(p, q);
if (!R.count(u))
continue; int k = R[u];
if (bit(i) == bit(k))
link_board(i, k);
else
del_empty(k);
} int fi = getfar(i);
if (c[fi] == 0) {
int cnt = del_board(bit(fi), X[fi], Y[fi]);
if (bit(fi))
Nw -= cnt;
else
Nb -= cnt;
}
}
printf("%d %d\n", Nb, Nw);
} int main () {
int cas;
scanf("%d", &cas);
while (cas--) {
init();
solve();
}
return 0;
}

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