基于最大间隔分隔数据

import matplotlib
import matplotlib.pyplot as plt from numpy import * xcord0 = []
ycord0 = []
xcord1 = []
ycord1 = []
markers =[]
colors =[]
fr = open('F:\\machinelearninginaction\\Ch06\\testSet.txt')#this file was generated by 2normalGen.py
for line in fr.readlines():
lineSplit = line.strip().split('\t')
xPt = float(lineSplit[0])
yPt = float(lineSplit[1])
label = int(lineSplit[2])
if (label == 0):
xcord0.append(xPt)
ycord0.append(yPt)
else:
xcord1.append(xPt)
ycord1.append(yPt) fr.close()
fig = plt.figure()
ax = fig.add_subplot(221)
xcord0 = []; ycord0 = []; xcord1 = []; ycord1 = []
for i in range(300):
[x,y] = random.uniform(0,1,2)
if ((x > 0.5) and (y < 0.5)) or ((x < 0.5) and (y > 0.5)):
xcord0.append(x); ycord0.append(y)
else:
xcord1.append(x); ycord1.append(y)
ax.scatter(xcord0,ycord0, marker='s', s=90)
ax.scatter(xcord1,ycord1, marker='o', s=50, c='red')
plt.title('A')
ax = fig.add_subplot(222)
xcord0 = random.standard_normal(150); ycord0 = random.standard_normal(150)
xcord1 = random.standard_normal(150)+2.0; ycord1 = random.standard_normal(150)+2.0
ax.scatter(xcord0,ycord0, marker='s', s=90)
ax.scatter(xcord1,ycord1, marker='o', s=50, c='red')
plt.title('B')
ax = fig.add_subplot(223)
xcord0 = []
ycord0 = []
xcord1 = []
ycord1 = []
for i in range(300):
[x,y] = random.uniform(0,1,2)
if (x > 0.5):
xcord0.append(x*cos(2.0*pi*y)); ycord0.append(x*sin(2.0*pi*y))
else:
xcord1.append(x*cos(2.0*pi*y)); ycord1.append(x*sin(2.0*pi*y))
ax.scatter(xcord0,ycord0, marker='s', s=90)
ax.scatter(xcord1,ycord1, marker='o', s=50, c='red')
plt.title('C')
ax = fig.add_subplot(224)
xcord1 = zeros(150); ycord1 = zeros(150)
xcord0 = random.uniform(-3,3,350); ycord0 = random.uniform(-3,3,350);
xcord1[0:50] = 0.3*random.standard_normal(50)+2.0; ycord1[0:50] = 0.3*random.standard_normal(50)+2.0 xcord1[50:100] = 0.3*random.standard_normal(50)-2.0; ycord1[50:100] = 0.3*random.standard_normal(50)-3.0 xcord1[100:150] = 0.3*random.standard_normal(50)+1.0; ycord1[100:150] = 0.3*random.standard_normal(50)
ax.scatter(xcord0,ycord0, marker='s', s=90)
ax.scatter(xcord1,ycord1, marker='o', s=50, c='red')
plt.title('D')
plt.show()

寻找最大间隔

分类器求解的优化问题

这里的类别标签为什么采用-1和+1,而不是0和 1呢?这是由于-1和+1仅仅相差一个符号,
方便数学上的处理。我们可以通过一个统一公式来表示间隔或者数据点到分隔超平面的距离,同
时不必担心数据到底是属于-1还是+1类。

S V M 应用的一般框架

from numpy import *
from time import sleep def loadDataSet(fileName):
dataMat = []; labelMat = []
fr = open(fileName)
for line in fr.readlines():
lineArr = line.strip().split('\t')
dataMat.append([float(lineArr[0]), float(lineArr[1])])
labelMat.append(float(lineArr[2]))
return dataMat,labelMat def selectJrand(i,m):
j=i #we want to select any J not equal to i
while (j==i):
j = int(random.uniform(0,m))
return j def clipAlpha(aj,H,L):
if aj > H:
aj = H
if L > aj:
aj = L
return aj
dataMat,labelMat = loadDataSet('F:\\machinelearninginaction\\Ch06\\testSet.txt')
print(labelMat)

可以看得出来,这里采用的类别标签是-1和1

def smoSimple(dataMatIn, classLabels, C, toler, maxIter):
dataMatrix = mat(dataMatIn); labelMat = mat(classLabels).transpose()
b = 0; m,n = shape(dataMatrix)
alphas = mat(zeros((m,1)))
iter = 0
while (iter < maxIter):
alphaPairsChanged = 0
for i in range(m):
fXi = float(multiply(alphas,labelMat).T*(dataMatrix*dataMatrix[i,:].T)) + b
Ei = fXi - float(labelMat[i])#if checks if an example violates KKT conditions
if ((labelMat[i]*Ei < -toler) and (alphas[i] < C)) or ((labelMat[i]*Ei > toler) and (alphas[i] > 0)):
j = selectJrand(i,m)
fXj = float(multiply(alphas,labelMat).T*(dataMatrix*dataMatrix[j,:].T)) + b
Ej = fXj - float(labelMat[j])
alphaIold = alphas[i].copy()
alphaJold = alphas[j].copy()
if (labelMat[i] != labelMat[j]):
L = max(0, alphas[j] - alphas[i])
H = min(C, C + alphas[j] - alphas[i])
else:
L = max(0, alphas[j] + alphas[i] - C)
H = min(C, alphas[j] + alphas[i])
if L==H:
print("L==H")
continue
eta = 2.0 * dataMatrix[i,:]*dataMatrix[j,:].T - dataMatrix[i,:]*dataMatrix[i,:].T - dataMatrix[j,:]*dataMatrix[j,:].T
if eta >= 0:
print("eta>=0")
continue
alphas[j] -= labelMat[j]*(Ei - Ej)/eta
alphas[j] = clipAlpha(alphas[j],H,L)
if (abs(alphas[j] - alphaJold) < 0.00001):
print("j not moving enough")
continue
alphas[i] += labelMat[j]*labelMat[i]*(alphaJold - alphas[j])#update i by the same amount as j
#the update is in the oppostie direction
b1 = b - Ei- labelMat[i]*(alphas[i]-alphaIold)*dataMatrix[i,:]*dataMatrix[i,:].T - labelMat[j]*(alphas[j]-alphaJold)*dataMatrix[i,:]*dataMatrix[j,:].T
b2 = b - Ej- labelMat[i]*(alphas[i]-alphaIold)*dataMatrix[i,:]*dataMatrix[j,:].T - labelMat[j]*(alphas[j]-alphaJold)*dataMatrix[j,:]*dataMatrix[j,:].T
if (0 < alphas[i]) and (C > alphas[i]):
b = b1
elif (0 < alphas[j]) and (C > alphas[j]):
b = b2
else:
b = (b1 + b2)/2.0
alphaPairsChanged += 1
print("iter: %d i:%d, pairs changed %d" % (iter,i,alphaPairsChanged))
if (alphaPairsChanged == 0): iter += 1
else: iter = 0
print("iteration number: %d" % iter)
return b,alphas

该函数有5个输人参数,分别
是:数据集、类别标签、常数C 、容错率和取消前最大的循环次数。

b,alphas = smoSimple(dataMat,labelMat, 0.6, 0.001, 40)
print(b)
print(alphas[alphas>0])

在原始数据集上对这些支持向量画圈之后的结果

import matplotlib
import matplotlib.pyplot as plt from numpy import *
from matplotlib.patches import Circle xcord0 = []
ycord0 = []
xcord1 = []
ycord1 = []
markers =[]
colors =[]
fr = open('F:\\machinelearninginaction\\Ch06\\testSet.txt')#this file was generated by 2normalGen.py
for line in fr.readlines():
lineSplit = line.strip().split('\t')
xPt = float(lineSplit[0])
yPt = float(lineSplit[1])
label = int(lineSplit[2])
if (label == -1):
xcord0.append(xPt)
ycord0.append(yPt)
else:
xcord1.append(xPt)
ycord1.append(yPt) fr.close()
fig = plt.figure()
ax = fig.add_subplot(111)
ax.scatter(xcord0,ycord0, marker='s', s=90)
ax.scatter(xcord1,ycord1, marker='o', s=50, c='red')
plt.title('Support Vectors Circled')
circle = Circle((4.6581910000000004, 3.507396), 0.5, facecolor='none', edgecolor=(0,0.8,0.8), linewidth=3, alpha=0.5)
ax.add_patch(circle)
circle = Circle((3.4570959999999999, -0.082215999999999997), 0.5, facecolor='none', edgecolor=(0,0.8,0.8), linewidth=3, alpha=0.5)
ax.add_patch(circle)
circle = Circle((6.0805730000000002, 0.41888599999999998), 0.5, facecolor='none', edgecolor=(0,0.8,0.8), linewidth=3, alpha=0.5)
ax.add_patch(circle)
#plt.plot([2.3,8.5], [-6,6]) #seperating hyperplane
b = -3.75567
w0=0.8065
w1=-0.2761
x = arange(-2.0, 12.0, 0.1)
y = (-w0*x - b)/w1
ax.plot(x,y)
ax.axis([-2,12,-8,6])
plt.show()

def kernelTrans(X, A, kTup): #calc the kernel or transform data to a higher dimensional space
m,n = shape(X)
K = mat(zeros((m,1)))
if kTup[0]=='lin':
K = X * A.T #linear kernel
elif kTup[0]=='rbf':
for j in range(m):
deltaRow = X[j,:] - A
K[j] = deltaRow*deltaRow.T
K = exp(K/(-1*kTup[1]**2)) #divide in NumPy is element-wise not matrix like Matlab
else: raise NameError('Houston We Have a Problem -- That Kernel is not recognized')
return K
class optStruct:
def __init__(self,dataMatIn, classLabels, C, toler, kTup): # Initialize the structure with the parameters
self.X = dataMatIn
self.labelMat = classLabels
self.C = C
self.tol = toler
self.m = shape(dataMatIn)[0]
self.alphas = mat(zeros((self.m,1)))
self.b = 0
self.eCache = mat(zeros((self.m,2))) #first column is valid flag
self.K = mat(zeros((self.m,self.m)))
for i in range(self.m):
self.K[:,i] = kernelTrans(self.X, self.X[i,:], kTup) def calcEk(oS, k):
fXk = float(multiply(oS.alphas,oS.labelMat).T*oS.K[:,k] + oS.b)
Ek = fXk - float(oS.labelMat[k])
return Ek def selectJ(i, oS, Ei): #this is the second choice -heurstic, and calcs Ej
maxK = -1; maxDeltaE = 0; Ej = 0
oS.eCache[i] = [1,Ei] #set valid #choose the alpha that gives the maximum delta E
validEcacheList = nonzero(oS.eCache[:,0].A)[0]
if (len(validEcacheList)) > 1:
for k in validEcacheList: #loop through valid Ecache values and find the one that maximizes delta E
if k == i: continue #don't calc for i, waste of time
Ek = calcEk(oS, k)
deltaE = abs(Ei - Ek)
if (deltaE > maxDeltaE):
maxK = k; maxDeltaE = deltaE; Ej = Ek
return maxK, Ej
else: #in this case (first time around) we don't have any valid eCache values
j = selectJrand(i, oS.m)
Ej = calcEk(oS, j)
return j, Ej def updateEk(oS, k):#after any alpha has changed update the new value in the cache
Ek = calcEk(oS, k)
oS.eCache[k] = [1,Ek]

def innerL(i, oS):
Ei = calcEk(oS, i)
if ((oS.labelMat[i]*Ei < -oS.tol) and (oS.alphas[i] < oS.C)) or ((oS.labelMat[i]*Ei > oS.tol) and (oS.alphas[i] > 0)):
j,Ej = selectJ(i, oS, Ei) #this has been changed from selectJrand
alphaIold = oS.alphas[i].copy(); alphaJold = oS.alphas[j].copy();
if (oS.labelMat[i] != oS.labelMat[j]):
L = max(0, oS.alphas[j] - oS.alphas[i])
H = min(oS.C, oS.C + oS.alphas[j] - oS.alphas[i])
else:
L = max(0, oS.alphas[j] + oS.alphas[i] - oS.C)
H = min(oS.C, oS.alphas[j] + oS.alphas[i])
if L==H:
print("L==H")
return 0
eta = 2.0 * oS.K[i,j] - oS.K[i,i] - oS.K[j,j] #changed for kernel
if eta >= 0:
print("eta>=0")
return 0
oS.alphas[j] -= oS.labelMat[j]*(Ei - Ej)/eta
oS.alphas[j] = clipAlpha(oS.alphas[j],H,L)
updateEk(oS, j) #added this for the Ecache
if (abs(oS.alphas[j] - alphaJold) < 0.00001):
print("j not moving enough")
return 0
oS.alphas[i] += oS.labelMat[j]*oS.labelMat[i]*(alphaJold - oS.alphas[j])#update i by the same amount as j
updateEk(oS, i) #added this for the Ecache #the update is in the oppostie direction
b1 = oS.b - Ei- oS.labelMat[i]*(oS.alphas[i]-alphaIold)*oS.K[i,i] - oS.labelMat[j]*(oS.alphas[j]-alphaJold)*oS.K[i,j]
b2 = oS.b - Ej- oS.labelMat[i]*(oS.alphas[i]-alphaIold)*oS.K[i,j]- oS.labelMat[j]*(oS.alphas[j]-alphaJold)*oS.K[j,j]
if (0 < oS.alphas[i]) and (oS.C > oS.alphas[i]): oS.b = b1
elif (0 < oS.alphas[j]) and (oS.C > oS.alphas[j]): oS.b = b2
else: oS.b = (b1 + b2)/2.0
return 1
else:
return 0

def smoP(dataMatIn, classLabels, C, toler, maxIter,kTup=('lin', 0)):    #full Platt SMO
oS = optStruct(mat(dataMatIn),mat(classLabels).transpose(),C,toler, kTup)
iter = 0
entireSet = True
alphaPairsChanged = 0
while (iter < maxIter) and ((alphaPairsChanged > 0) or (entireSet)):
alphaPairsChanged = 0
if entireSet: #go over all
for i in range(oS.m):
alphaPairsChanged += innerL(i,oS)
print("fullSet, iter: %d i:%d, pairs changed %d" % (iter,i,alphaPairsChanged))
iter += 1
else:#go over non-bound (railed) alphas
nonBoundIs = nonzero((oS.alphas.A > 0) * (oS.alphas.A < C))[0]
for i in nonBoundIs:
alphaPairsChanged += innerL(i,oS)
print("non-bound, iter: %d i:%d, pairs changed %d" % (iter,i,alphaPairsChanged))
iter += 1
if entireSet: entireSet = False #toggle entire set loop
elif (alphaPairsChanged == 0): entireSet = True
print("iteration number: %d" % iter)
return oS.b,oS.alphas
b,alphas = smoP(dataMat,labelMat, 0.6, 0.001, 40)
print(b)
print(alphas[alphas>0])

下面列出的一个小函数可
以用于实现上述任务:

def calcWs(alphas,dataArr,classLabels):
X = mat(dataArr); labelMat = mat(classLabels).transpose()
m,n = shape(X)
w = zeros((n,1))
for i in range(m):
w += multiply(alphas[i]*labelMat[i],X[i,:].T)
return w
w = calcWs(alphas,dataMat,labelMat)
print(w)

r = mat(dataMat[0])*w+b
print(r)

print(labelMat[0])

利用核函数将数据映射到高维空间

数据点处于一个圆中,人类的大脑能够意识到这一点。然而,对于分类器而言,
它只能识别分类器的结果是大于0还是小于0。如果只在1和^轴构成的坐标系中插人直线进行分类
的话,我们并不会得到理想的结果。我们或许可以对圆中的数据进行某种形式的转换,从而得到
某些新的变量来表示数据。在这种表示情况下,我们就更容易得到大于0或者小于0的测试结果。
在这个例子中,我们将数据从一个特征空间转换到另一个特征空间。在新空间下,我们可以很容
易利用巳有的工具对数据进行处理。数学家们喜欢将这个过程称之为从一个特征空间到另一个特
择空间的映射。在通常情况下,这种映射会将低维特征空间映射到高维空间。

这种从某个特征空间到另一个特征空间的映射是通过核函数来实现的。

核函数并不仅仅应用于支持向量机,很多其他的机器学习算法也都用到核函数。

径向基核函数

上述高斯核函数将数据从其特征空间映射到更高维的空间,具体来说这里是映射到一个无穷
维的空间。

高斯核函数只是一个常用的核函数,使用
者并不需要确切地理解数据到底是如何表现的,而且使用高斯核函数还会得到一个理想的结果。

def kernelTrans(X, A, kTup): #calc the kernel or transform data to a higher dimensional space
m,n = shape(X)
K = mat(zeros((m,1)))
if kTup[0]=='lin':
K = X * A.T #linear kernel
elif kTup[0]=='rbf':
for j in range(m):
deltaRow = X[j,:] - A
K[j] = deltaRow*deltaRow.T
K = exp(K/(-1*kTup[1]**2)) #divide in NumPy is element-wise not matrix like Matlab
else: raise NameError('Houston We Have a Problem -- That Kernel is not recognized')
return K

在测试中使用核函数

利用核函数进行分类的径向基测试函数

def testRbf(k1=1.3):
dataArr,labelArr = loadDataSet('F:\\machinelearninginaction\\Ch06\\testSetRBF.txt')
b,alphas = smoP(dataArr, labelArr, 200, 0.0001, 10000, ('rbf', k1)) #C=200 important
datMat=mat(dataArr); labelMat = mat(labelArr).transpose()
svInd=nonzero(alphas.A>0)[0]
sVs=datMat[svInd] #get matrix of only support vectors
labelSV = labelMat[svInd];
print("there are %d Support Vectors" % shape(sVs)[0])
m,n = shape(datMat)
errorCount = 0
for i in range(m):
kernelEval = kernelTrans(sVs,datMat[i,:],('rbf', k1))
predict=kernelEval.T * multiply(labelSV,alphas[svInd]) + b
if sign(predict)!=sign(labelArr[i]):
errorCount += 1
print("the training error rate is: %f" % (float(errorCount)/m))
dataArr,labelArr = loadDataSet('F:\\machinelearninginaction\\Ch06\\testSetRBF2.txt')
errorCount = 0
datMat=mat(dataArr)
labelMat = mat(labelArr).transpose()
m,n = shape(datMat)
for i in range(m):
kernelEval = kernelTrans(sVs,datMat[i,:],('rbf', k1))
predict=kernelEval.T * multiply(labelSV,alphas[svInd]) + b
if sign(predict)!=sign(labelArr[i]):
errorCount += 1
print("the test error rate is: %f" % (float(errorCount)/m))

吴裕雄--天生自然python机器学习:支持向量机SVM的更多相关文章

  1. 吴裕雄--天生自然python机器学习:基于支持向量机SVM的手写数字识别

    from numpy import * def img2vector(filename): returnVect = zeros((1,1024)) fr = open(filename) for i ...

  2. 吴裕雄--天生自然python机器学习实战:K-NN算法约会网站好友喜好预测以及手写数字预测分类实验

    实验设备与软件环境 硬件环境:内存ddr3 4G及以上的x86架构主机一部 系统环境:windows 软件环境:Anaconda2(64位),python3.5,jupyter 内核版本:window ...

  3. 吴裕雄--天生自然python机器学习:朴素贝叶斯算法

    分类器有时会产生错误结果,这时可以要求分类器给出一个最优的类别猜测结果,同 时给出这个猜测的概率估计值. 概率论是许多机器学习算法的基础 在计算 特征值取某个值的概率时涉及了一些概率知识,在那里我们先 ...

  4. 吴裕雄--天生自然python机器学习:决策树算法

    我们经常使用决策树处理分类问题’近来的调查表明决策树也是最经常使用的数据挖掘算法. 它之所以如此流行,一个很重要的原因就是使用者基本上不用了解机器学习算法,也不用深究它 是如何工作的. K-近邻算法可 ...

  5. 吴裕雄--天生自然python机器学习:使用K-近邻算法改进约会网站的配对效果

    在约会网站使用K-近邻算法 准备数据:从文本文件中解析数据 海伦收集约会数据巳经有了一段时间,她把这些数据存放在文本文件(1如1^及抓 比加 中,每 个样本数据占据一行,总共有1000行.海伦的样本主 ...

  6. 吴裕雄--天生自然python机器学习:机器学习简介

    除却一些无关紧要的情况,人们很难直接从原始数据本身获得所需信息.例如 ,对于垃圾邮 件的检测,侦测一个单词是否存在并没有太大的作用,然而当某几个特定单词同时出现时,再辅 以考察邮件长度及其他因素,人们 ...

  7. 吴裕雄--天生自然python机器学习:使用Logistic回归从疝气病症预测病马的死亡率

    ,除了部分指标主观和难以测量外,该数据还存在一个问题,数据集中有 30%的值是缺失的.下面将首先介绍如何处理数据集中的数据缺失问题,然 后 再 利 用 Logistic回 归 和随机梯度上升算法来预测 ...

  8. 吴裕雄--天生自然python机器学习:Logistic回归

    假设现在有一些数据点,我们用 一条直线对这些点进行拟合(该线称为最佳拟合直线),这个拟合过程就称作回归.利用Logistic回归进行分类的主要思想是:根据现有数据对分类边界线建立回归公式,以此进行分类 ...

  9. 吴裕雄--天生自然python机器学习:使用朴素贝叶斯过滤垃圾邮件

    使用朴素贝叶斯解决一些现实生活中 的问题时,需要先从文本内容得到字符串列表,然后生成词向量. 准备数据:切分文本 测试算法:使用朴素贝叶斯进行交叉验证 文件解析及完整的垃圾邮件测试函数 def cre ...

随机推荐

  1. springboot 启动时加载数据库数据到本地Map

    InitDataConfig.java import cn.hutool.core.collection.CollUtil; import cn.hutool.core.lang.Dict; impo ...

  2. C++ 模板练习1

    //特定的模板友元关系 #include "stdafx.h" #include <iostream> using namespace std; template< ...

  3. 洛谷 P1964 【mc生存】卖东西(多重背包)

    题目传送门 解题思路: 题目里有,多重背包. AC代码: #include<iostream> #include<cstdio> #include<map> usi ...

  4. Springboot前后端分离中,后端拦截器拦截后,前端没有对应的返回码可以判断

    项目登录流程如下 用户进入前端登录界面,输入账号密码等,输入完成之后前端发送请求到后端(拦截器不会拦截登录请求),后端验证账号密码等成功之后生成Token并存储到数据库,数据库中包含该Token过期时 ...

  5. 干货 | 京东技术中台的Flutter实践之路

    在 2019 年,Flutter 推出了多个正式版本,支持的终端越来越多,使用的项目也越来越多.Flutter 正在经历从小范围尝鲜到大面积应用的过程,越来越多的研发团队加入到 Flutter 的学习 ...

  6. mysql自关联和多表连接查询

    自关联操作         多表连接查询  inner  join 内查询   left  join  左查询   right  join  右查询                          ...

  7. VCPU的解释

    vCPU,顾名思义,是虚拟CPU. 创建虚拟机时,需要配置vCPU资源. 因此vCPU是虚拟机的部件. 因此脱离VM,谈论vCPU是没有意义的. 虚拟化管理系统如何调度vCPU,取决于系统内的虚拟机数 ...

  8. MVC——EF 回顾总结

    回顾一下MVC的知识点. 其实开始 我在学校的知识对MVC 还是很模糊的一个概念.只是记得结合EasyUI 增删改查 和分页,代码都是模糊的 进过这段时间的学习,让我对MVC 有了一个很清楚的认识. ...

  9. [CF百场计划]#2 Codeforces Round #618 (Div. 2)

    A. Non-zero Description: Guy-Manuel and Thomas have an array \(a\) of \(n\) integers [\(a_1, a_2, \d ...

  10. vue整合外部js

    vue引入外部jsimport { TrackLine } from "../../../../../static/js/trajectory.js";import { initM ...