student(S#,Sname,Sage,Ssex) 学生表       S#:学号;





Sname:学生姓名;Sage:学生年龄;Ssex:学生性别

Course(C#,Cname,T#) 课程表                    C#,课





程编号;Cname:课程名字;T#:教师编号

SC(S#,C#,score) 成绩表                             





S#:学号;C#,课程编号;score:成绩

Teacher(T#,Tname) 教师表                        T#





:教师编号; Tname:教师名字

问题:

1、查询“001”课程比“002”课程成绩高的所有学生的学





号;

  select a.S# from (select s#,score from SC where 





C#='001') a,(select s#,score

  from SC where C#='002') b

  where a.score>b.score and a.s#=b.s#;

2、查询平均成绩大于60分的同学的学号和平均成绩;

    select S#,avg(score)

    from sc

    group by S# having avg(score) >60;

3、查询所有同学的学号、姓名、选课数、总成绩;

  select Student.S#,Student.Sname,count(SC.C#),sum





(score)

  from Student left Outer join SC on 





Student.S#=SC.S#

  group by Student.S#,Sname

4、查询姓“李”的老师的个数;

  select count(distinct(Tname))

  from Teacher

  where Tname like '李%';

5、查询没学过“叶平”老师课的同学的学号、姓名;

    select Student.S#,Student.Sname

    from Student 

    where S# not in (select distinct( SC.S#) from 





SC,Course,Teacher where  SC.C#=Course.C# and 





Teacher.T#=Course.T# and Teacher.Tname='叶平');

6、查询学过“001”并且也学过编号“002”课程的同学的





学号、姓名;

  select Student.S#,Student.Sname from Student,SC 





where Student.S#=SC.S# and SC.C#='001'and exists( 





Select * from SC as SC_2 where SC_2.S#=SC.S# and 





SC_2.C#='002');

7、查询学过“叶平”老师所教的所有课的同学的学号、姓





名;

  select S#,Sname

  from Student

  where S# in (select S# from SC ,Course ,Teacher 





where SC.C#=Course.C# and Teacher.T#=Course.T# and 





Teacher.Tname='叶平' group by S# having count





(SC.C#)=(select count(C#) from Course,Teacher  





where Teacher.T#=Course.T# and Tname='叶平'));

8、查询课程编号“002”的成绩比课程编号“001”课程低





的所有同学的学号、姓名;

  Select S#,Sname from (select 





Student.S#,Student.Sname,score ,(select score from 





SC SC_2 where SC_2.S#=Student.S# and SC_2.C#='002') 





score2

  from Student,SC where Student.S#=SC.S# and 





C#='001') S_2 where score2 <score;

9、查询所有课程成绩小于60分的同学的学号、姓名;

  select S#,Sname

  from Student

  where S# not in (select Student.S# from 





Student,SC where S.S#=SC.S# and score>60);

10、查询没有学全所有课的同学的学号、姓名;

    select Student.S#,Student.Sname

    from Student,SC

    where Student.S#=SC.S# group by  





Student.S#,Student.Sname having count(C#) <(select 





count(C#) from Course);

11、查询至少有一门课与学号为“1001”的同学所学相同





的同学的学号和姓名;

    select S#,Sname from Student,SC where 





Student.S#=SC.S# and C# in select C# from SC where 





S#='1001';

12、查询至少学过学号为“001”同学所有一门课的其他同





学学号和姓名;

    select distinct SC.S#,Sname

    from Student,SC

    where Student.S#=SC.S# and C# in (select C# 





from SC where S#='001');

13、把“SC”表中“叶平”老师教的课的成绩都更改为此





课程的平均成绩;

    update SC set score=(select avg(SC_2.score)

    from SC SC_2

    where SC_2.C#=SC.C# ) from Course,Teacher where 





Course.C#=SC.C# and Course.T#=Teacher.T# and 





Teacher.Tname='叶平');

14、查询和“1002”号的同学学习的课程完全相同的其他





同学学号和姓名;

    select S# from SC where C# in (select C# from 





SC where S#='1002')

    group by S# having count(*)=(select count(*) 





from SC where S#='1002');

15、删除学习“叶平”老师课的SC表记录;

    Delect SC

    from course ,Teacher 

    where Course.C#=SC.C# and Course.T#= Teacher.T# 





and Tname='叶平';

16、向SC表中插入一些记录,这些记录要求符合以下条件





:没有上过编号“003”课程的同学学号、2、

    号课的平均成绩;

    Insert SC select S#,'002',(Select avg(score)

    from SC where C#='002') from Student where S# 





not in (Select S# from SC where C#='002');

17、按平均成绩从高到低显示所有学生的“数据库”、“





企业管理”、“英语”三门的课程成绩,按如下形式显示





: 学生ID,,数据库,企业管理,英语,有效课程数,有效平均







    SELECT S# as 学生ID

        ,(SELECT score FROM SC WHERE SC.S#=t.S# AND 





C#='004') AS 数据库

        ,(SELECT score FROM SC WHERE SC.S#=t.S# AND 





C#='001') AS 企业管理

        ,(SELECT score FROM SC WHERE SC.S#=t.S# AND 





C#='006') AS 英语

        ,COUNT(*) AS 有效课程数, AVG(t.score) AS 平





均成绩

    FROM SC AS t

    GROUP BY S#

    ORDER BY avg(t.score) 

18、查询各科成绩最高和最低的分:以如下形式显示:课





程ID,最高分,最低分

    SELECT L.C# As 课程ID,L.score AS 最高分,R.score 





AS 最低分

    FROM SC L ,SC AS R

    WHERE L.C# = R.C# and

        L.score = (SELECT MAX(IL.score)

                      FROM SC AS IL,Student AS IM

                      WHERE L.C# = IL.C# and 





IM.S#=IL.S#

                      GROUP BY IL.C#)

        AND

        R.Score = (SELECT MIN(IR.score)

                      FROM SC AS IR

                      WHERE R.C# = IR.C#

                  GROUP BY IR.C#

                    );

19、按各科平均成绩从低到高和及格率的百分数从高到低





顺序

    SELECT t.C# AS 课程号,max(course.Cname)AS 课程





名,isnull(AVG(score),0) AS 平均成绩

        ,100 * SUM(CASE WHEN  isnull(score,0)>=60 





THEN 1 ELSE 0 END)/COUNT(*) AS 及格百分数

    FROM SC T,Course

    where t.C#=course.C#

    GROUP BY t.C#

    ORDER BY 100 * SUM(CASE WHEN  isnull(score,0)





>=60 THEN 1 ELSE 0 END)/COUNT(*) DESC

20、查询如下课程平均成绩和及格率的百分数(用"1行"显





示): 企业管理(001),马克思(002),OO&UML (003)





,数据库(004)

    SELECT SUM(CASE WHEN C# ='001' THEN score ELSE 





0 END)/SUM(CASE C# WHEN '001' THEN 1 ELSE 0 END) AS 





企业管理平均分

        ,100 * SUM(CASE WHEN C# = '001' AND score 





>= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '001' 





THEN 1 ELSE 0 END) AS 企业管理及格百分数

        ,SUM(CASE WHEN C# = '002' THEN score ELSE 0 





END)/SUM(CASE C# WHEN '002' THEN 1 ELSE 0 END) AS 





马克思平均分

        ,100 * SUM(CASE WHEN C# = '002' AND score 





>= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '002' 





THEN 1 ELSE 0 END) AS 马克思及格百分数

        ,SUM(CASE WHEN C# = '003' THEN score ELSE 0 





END)/SUM(CASE C# WHEN '003' THEN 1 ELSE 0 END) AS 





UML平均分

        ,100 * SUM(CASE WHEN C# = '003' AND score 





>= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '003' 





THEN 1 ELSE 0 END) AS UML及格百分数

        ,SUM(CASE WHEN C# = '004' THEN score ELSE 0 





END)/SUM(CASE C# WHEN '004' THEN 1 ELSE 0 END) AS 





数据库平均分

        ,100 * SUM(CASE WHEN C# = '004' AND score 





>= 60 THEN 1 ELSE 0 END)/SUM(CASE WHEN C# = '004' 





THEN 1 ELSE 0 END) AS 数据库及格百分数

  FROM SC

21、查询不同老师所教不同课程平均分从高到低显示

  SELECT max(Z.T#) AS 教师ID,MAX(Z.Tname) AS 教师姓





名,C.C# AS 课程ID,MAX(C.Cname) AS 课程名称,AVG





(Score) AS 平均成绩

    FROM SC AS T,Course AS C ,Teacher AS Z

    where T.C#=C.C# and C.T#=Z.T#

  GROUP BY C.C#

  ORDER BY AVG(Score) DESC

22、查询如下课程成绩第 3 名到第 6 名的学生成绩单:





企业管理(001),马克思(002),UML (003),数据库





(004)

    [学生ID],[学生姓名],企业管理,马克思,UML,数据库,





平均成绩

    SELECT  DISTINCT top 3

      SC.S# As 学生学号,

        Student.Sname AS 学生姓名 ,

      T1.score AS 企业管理,

      T2.score AS 马克思,

      T3.score AS UML,

      T4.score AS 数据库,

      ISNULL(T1.score,0) + ISNULL(T2.score,0) + 





ISNULL(T3.score,0) + ISNULL(T4.score,0) as 总分

      FROM Student,SC  LEFT JOIN SC AS T1

                      ON SC.S# = T1.S# AND T1.C# = 





'001'

            LEFT JOIN SC AS T2

                      ON SC.S# = T2.S# AND T2.C# = 





'002'

            LEFT JOIN SC AS T3

                      ON SC.S# = T3.S# AND T3.C# = 





'003'

            LEFT JOIN SC AS T4

                      ON SC.S# = T4.S# AND T4.C# = 





'004'

      WHERE student.S#=SC.S# and

      ISNULL(T1.score,0) + ISNULL(T2.score,0) + 





ISNULL(T3.score,0) + ISNULL(T4.score,0)

      NOT IN

      (SELECT

            DISTINCT

            TOP 15 WITH TIES

            ISNULL(T1.score,0) + ISNULL(T2.score,0) 





+ ISNULL(T3.score,0) + ISNULL(T4.score,0)

      FROM sc

            LEFT JOIN sc AS T1

                      ON sc.S# = T1.S# AND T1.C# = 





'k1'

            LEFT JOIN sc AS T2

                      ON sc.S# = T2.S# AND T2.C# = 





'k2'

            LEFT JOIN sc AS T3

                      ON sc.S# = T3.S# AND T3.C# = 





'k3'

            LEFT JOIN sc AS T4

                      ON sc.S# = T4.S# AND T4.C# = 





'k4'

      ORDER BY ISNULL(T1.score,0) + ISNULL





(T2.score,0) + ISNULL(T3.score,0) + ISNULL





(T4.score,0) DESC);

23、统计列印各科成绩,各分数段人数:课程ID,课程名称,





[100-85],[85-70],[70-60],[ <60]

    SELECT SC.C# as 课程ID, Cname as 课程名称

        ,SUM(CASE WHEN score BETWEEN 85 AND 100 





THEN 1 ELSE 0 END) AS [100 - 85]

        ,SUM(CASE WHEN score BETWEEN 70 AND 85 THEN 





1 ELSE 0 END) AS [85 - 70]

        ,SUM(CASE WHEN score BETWEEN 60 AND 70 THEN 





1 ELSE 0 END) AS [70 - 60]

        ,SUM(CASE WHEN score < 60 THEN 1 ELSE 0 





END) AS [60 -]

    FROM SC,Course

    where SC.C#=Course.C#

    GROUP BY SC.C#,Cname;

24、查询学生平均成绩及其名次

      SELECT 1+(SELECT COUNT( distinct 平均成绩)

              FROM (SELECT S#,AVG(score) AS 平均成







                      FROM SC

                  GROUP BY S#

                  ) AS T1

            WHERE 平均成绩 > T2.平均成绩) as 名次,

      S# as 学生学号,平均成绩

    FROM (SELECT S#,AVG(score) 平均成绩

            FROM SC

        GROUP BY S#

        ) AS T2

    ORDER BY 平均成绩 desc;

 

25、查询各科成绩前三名的记录:(不考虑成绩并列情况)

      SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score 





as 分数

      FROM SC t1

      WHERE score IN (SELECT TOP 3 score

              FROM SC

              WHERE t1.C#= C#

            ORDER BY score DESC

              )

      ORDER BY t1.C#;

26、查询每门课程被选修的学生数

  select c#,count(S#) from sc group by C#;

27、查询出只选修了一门课程的全部学生的学号和姓名

  select SC.S#,Student.Sname,count(C#) AS 选课数

  from SC ,Student

  where SC.S#=Student.S# group by SC.S# 





,Student.Sname having count(C#)=1;

28、查询男生、女生人数

    Select count(Ssex) as 男生人数 from Student 





group by Ssex having Ssex='男';

    Select count(Ssex) as 女生人数 from Student 





group by Ssex having Ssex='女';

29、查询姓“张”的学生名单

    SELECT Sname FROM Student WHERE Sname like 





'张%';

30、查询同名同性学生名单,并统计同名人数

  select Sname,count(*) from Student group by Sname 





having  count(*)>1;;

31、1981年出生的学生名单(注:Student表中Sage列的类





型是datetime)

    select Sname,  CONVERT(char (11),DATEPART





(year,Sage)) as age

    from student

    where  CONVERT(char(11),DATEPART(year,Sage))





='1981';

32、查询每门课程的平均成绩,结果按平均成绩升序排列





,平均成绩相同时,按课程号降序排列

    Select C#,Avg(score) from SC group by C# order 





by Avg(score),C# DESC ;

33、查询平均成绩大于85的所有学生的学号、姓名和平均





成绩

    select Sname,SC.S# ,avg(score)

    from Student,SC

    where Student.S#=SC.S# group by SC.S#,Sname 





having    avg(score)>85;

34、查询课程名称为“数据库”,且分数低于60的学生姓





名和分数

    Select Sname,isnull(score,0)

    from Student,SC,Course

    where SC.S#=Student.S# and SC.C#=Course.C# and  





Course.Cname='数据库'and score <60;

35、查询所有学生的选课情况;

    SELECT SC.S#,SC.C#,Sname,Cname

    FROM SC,Student,Course

    where SC.S#=Student.S# and SC.C#=Course.C# ;

36、查询任何一门课程成绩在70分以上的姓名、课程名称





和分数;

    SELECT  distinct 





student.S#,student.Sname,SC.C#,SC.score

    FROM student,Sc

    WHERE SC.score>=70 AND SC.S#=student.S#;

37、查询不及格的课程,并按课程号从大到小排列

    select c# from sc where scor e <60 order by C# 





;

38、查询课程编号为003且课程成绩在80分以上的学生的学





号和姓名;

    select SC.S#,Student.Sname from SC,Student 





where SC.S#=Student.S# and Score>80 and C#='003';

39、求选了课程的学生人数

    select count(*) from sc;

40、查询选修“叶平”老师所授课程的学生中,成绩最高





的学生姓名及其成绩

    select Student.Sname,score

    from Student,SC,Course C,Teacher

    where Student.S#=SC.S# and SC.C#=C.C# and 





C.T#=Teacher.T# and Teacher.Tname='叶平' and 





SC.score=(select max(score)from SC where C#=C.C# );

41、查询各个课程及相应的选修人数

    select count(*) from sc group by C#;

42、查询不同课程成绩相同的学生的学号、课程号、学生





成绩

  select distinct  A.S#,B.score from SC A  ,SC B 





where A.Score=B.Score and A.C# <>B.C# ;

43、查询每门功成绩最好的前两名

    SELECT t1.S# as 学生ID,t1.C# as 课程ID,Score as 





分数

      FROM SC t1

      WHERE score IN (SELECT TOP 2 score

              FROM SC

              WHERE t1.C#= C#

            ORDER BY score DESC

              )

      ORDER BY t1.C#;

44、统计每门课程的学生选修人数(超过10人的课程才统





计)。要求输出课程号和选修人数,查询结果按人数降序





排列,查询结果按人数降序排列,若人数相同,按课程号





升序排列 

    select  C# as 课程号,count(*) as 人数

    from  sc 

    group  by  C#

    order  by  count(*) desc,c# 

45、检索至少选修两门课程的学生学号

    select  S# 

    from  sc 

    group  by  s#

    having  count(*)  >  =  2

46、查询全部学生都选修的课程的课程号和课程名

    select  C#,Cname 

    from  Course 

    where  C#  in  (select  c#  from  sc group  by  





c#) 

47、查询没学过“叶平”老师讲授的任一门课程的学生姓







    select Sname from Student where S# not in 





(select S# from Course,Teacher,SC where 





Course.T#=Teacher.T# and SC.C#=course.C# and 





Tname='叶平');

48、查询两门以上不及格课程的同学的学号及其平均成绩

    select S#,avg(isnull(score,0)) from SC where S# 





in (select S# from SC where score <60 group by S# 





having count(*)>2)group by S#;

49、检索“004”课程分数小于60,按分数降序排列的同学





学号

    select S# from SC where C#='004'and score <60 





order by score desc;

50、删除“002”同学的“001”课程的成绩

delete from Sc where S#='002'and C#='001';

sql基本查询语句练习的更多相关文章

  1. SQL逻辑查询语句执行顺序 需要重新整理

    一.SQL语句定义顺序 1 2 3 4 5 6 7 8 9 10 SELECT DISTINCT <select_list> FROM <left_table> <joi ...

  2. 如何在SQL Server查询语句(Select)中检索存储过程(Store Procedure)的结果集?

    如何在SQL Server查询语句(Select)中检索存储过程(Store Procedure)的结果集?(2006-12-14 09:25:36) 与这个问题具有相同性质的其他描述还包括:如何 ...

  3. python 3 mysql sql逻辑查询语句执行顺序

    python 3 mysql sql逻辑查询语句执行顺序 一 .SELECT语句关键字的定义顺序 SELECT DISTINCT <select_list> FROM <left_t ...

  4. mysql第四篇--SQL逻辑查询语句执行顺序

    mysql第四篇--SQL逻辑查询语句执行顺序 一.SQL语句定义顺序 SELECT DISTINCT <select_list> FROM <left_table> < ...

  5. SQL Server SQL高级查询语句小结(转)

    --select select * from student; --all 查询所有 select all sex from student; --distinct 过滤重复 select disti ...

  6. 45、SQL逻辑查询语句执行顺序

    一 SELECT语句关键字的定义顺序 SELECT DISTINCT <select_list> FROM <left_table> <join_type> JOI ...

  7. sql的查询语句的总结

    一:基本的查询sql 1:基本常用查询 select * from student; --select select all sex from student; --all 查询所有 select d ...

  8. NumberFormatException: Invalid int类型不匹配异常——使用SQL数据库查询语句select * from blacknumber order by _id desc limit ?,20;出现

    异常:类型不匹配 05-06 08:12:38.151: E/AndroidRuntime(14904): java.lang.NumberFormatException: Invalid int: ...

  9. 第四篇:记录相关操作 SQL逻辑查询语句执行顺序

    http://www.cnblogs.com/linhaifeng/articles/7372774.html 一 SELECT语句关键字的定义顺序 SELECT DISTINCT <selec ...

  10. SQL逻辑查询语句执行顺序

    阅读目录 一 SELECT语句关键字的定义顺序 二 SELECT语句关键字的执行顺序 三 准备表和数据 四 准备SQL逻辑查询测试语句 五 执行顺序分析 一 SELECT语句关键字的定义顺序 SELE ...

随机推荐

  1. XSS 跨站脚本攻击实例1

    14.44-16.22  编码,跨站脚本攻击1 16.22-16.53 整理cnblog   这篇文章适合知道有XSS脚本攻击,但是一头雾水,从未操作过,也不知道脚本攻击会给客户端用户带来什么不便之处 ...

  2. EF切换到Mysql数据库,更改web.config

    1)引用: MySql.Data.dll,MySql.Data.Entity.dll,MySql.Data.Entity.EF6.dll 2)添加: <system.data> <D ...

  3. 返回结果的HTTP状态码

    HTTP状态码的职责是当客户端向服务器发送请求时,描述返回的请求结果. 2xx成功 2xx的响应结果表明请求被正常处理. 200 OK 请求已正常处理 204 No Content 请求处理成功,但是 ...

  4. 修复 Xcode 错误 “The identity used to sign the executable is no longer valid”

    如图: 解决方法来自:http://stackoverflow.com/questions/7088441/the-identity-used-to-sign-the-executable-is-no ...

  5. 数据结构录 之 单调队列&单调栈。(转)

    http://www.cnblogs.com/whywhy/p/5066306.html 队列和栈是很常见的应用,大部分算法中都能见到他们的影子. 而单纯的队列和栈经常不能满足需求,所以需要一些很神奇 ...

  6. [转载]java操作word(一)

    一. 需求背景 在做项目的过程中,经常会遇到要把数据库数据导出到Word文件中的需求,因为很多情况下,我们需要将数据导出到WORD中进行打印.此需求可以通过用程序填充数据到word模板中来实现.所谓模 ...

  7. LeetCode OJ:Contains DuplicateII(是否包含重复II)

    Given an array of integers and an integer k, find out whether there are two distinct indices i and j ...

  8. Python_单元测试工具nose

    一.nose的API nose的API地址:http://pythontesting.net/framework/nose/nose-introduction/ 二.安装nose 先用easy_ins ...

  9. Oracle hash分区的秘密

    转自:http://www.hellodb.net/2009/12/hash_partition.html 在面试时经常会问一个问题,请列举出hash在数据库内部的应用,hash的原理虽然简单,但是它 ...

  10. pair对组

    一.pair基本概念 对组(pair)将一对值组合成一个值,这一对值可以具有不同的数据类型,两个值可以分别用pair的两个公有函数first和second访问. 类模板:template <cl ...