表名和字段

学生表

Student(s_id,s_name,s_birth,s_sex):学生编号、学生姓名、出生年月、学生性别。

课程表

Course(c_id,c_name,t_id):课程编号、课程名称、教师编号。

教师表

Teacher(t_id,t_name):教师编号、教师姓名。

成绩表

Score(s_id,c_id,s_score):学生编号、课程编号、分数。

建表语句

# 建表
# 学生表
CREATE TABLE `student`(
`s_id` VARCHAR(20),
`s_name` VARCHAR(20) NOT NULL DEFAULT '',
`s_birth` VARCHAR(20) NOT NULL DEFAULT '',
`s_sex` VARCHAR(10) NOT NULL DEFAULT '',
PRIMARY KEY(`s_id`)
);
# 课程表
CREATE TABLE `course`(
`c_id` VARCHAR(20),
`c_name` VARCHAR(20) NOT NULL DEFAULT '',
`t_id` VARCHAR(20) NOT NULL,
PRIMARY KEY(`c_id`)
);
# 教师表
CREATE TABLE `teacher`(
`t_id` VARCHAR(20),
`t_name` VARCHAR(20) NOT NULL DEFAULT '',
PRIMARY KEY(`t_id`)
);
# 成绩表
CREATE TABLE `score`(
`s_id` VARCHAR(20),
`c_id` VARCHAR(20),
`s_score` INT(3),
PRIMARY KEY(`s_id`,`c_id`)
); # 插入数据
# 插入学生表测试数据
insert into Student values('1', '赵雷', '1990-01-01', '男');
insert into Student values('2', '钱电', '1990-12-21', '男');
insert into Student values('3', '孙风', '1990-05-20', '男');
insert into Student values('4', '李云', '1990-08-06', '男');
insert into Student values('5', '周梅', '1991-12-01', '女');
insert into Student values('6', '吴兰', '1992-03-01', '女');
insert into Student values('7', '郑竹', '1989-07-01', '女');
insert into Student values('8', '王菊', '1990-01-20', '女'); # 插入课程表测试数据
insert into Course values('1', '语文', '2');
insert into Course values('2', '数学', '1');
insert into Course values('3', '英语', '3'); # 插入教师表测试数据
insert into Teacher values('1', '张三');
insert into Teacher values('2', '李四');
insert into Teacher values('3', '王五'); # 插入成绩表测试数据
insert into Score values('1', '1', 80);
insert into Score values('1', '2', 90);
insert into Score values('1', '3', 99);
insert into Score values('2', '1', 70);
insert into Score values('2', '2', 60);
insert into Score values('2', '3', 80);
insert into Score values('3', '1', 80);
insert into Score values('3', '2', 80);
insert into Score values('3', '3', 80);
insert into Score values('4', '1', 50);
insert into Score values('4', '2', 30);
insert into Score values('4', '3', 20);
insert into Score values('5', '1', 76);
insert into Score values('5', '2', 87);
insert into Score values('6', '1', 31);
insert into Score values('6', '3', 34);
insert into Score values('7', '2', 89);
insert into Score values('7', '3', 98);

题目及答案

# 1.查询"1"课程比"2"课程成绩高的学生的信息及课程分数。
SELECT
student.*,
s1.s_score AS "语文成绩",
s2.s_score AS "数学成绩"
FROM
student
LEFT JOIN
score AS s1
ON
student.s_id = s1.s_id AND s1.c_id = 1
LEFT JOIN
score AS s2
ON
student.s_id = s2.s_id AND s2.c_id = 2
WHERE
s1.s_score > s2.s_score; # 2.查询"1"课程比"2"课程成绩低的学生的信息及课程分数。
SELECT
student.*,
s1.s_score AS "语文成绩",
s2.s_score AS "数学成绩"
FROM
student
LEFT JOIN
score AS s1
ON
s1.s_id = student.s_id AND s1.c_id = 1
LEFT JOIN
score AS s2
ON
s2.s_id = student.s_id AND s2.c_id = 2
WHERE
s1.s_score < s2.s_score; # 3.查询平均成绩大于等于60分的同学的学生编号和学生姓名和平均成绩。
SELECT
student.s_id AS "学生编号",
student.s_name AS "学生姓名",
ROUND(AVG(score.s_score),2) AS "平均成绩"
FROM
student
LEFT JOIN
score
ON
score.s_id = student.s_id
GROUP BY
student.s_id
HAVING
AVG(score.s_score) >= 60; # 4.查询平均成绩小于60分的同学的学生编号和学生姓名和平均成绩(包括有成绩的和无成绩的)。
SELECT
student.s_id AS "学生编号",
student.s_name AS "学生姓名",
IFNULL(ROUND(AVG(score.s_score),2),0) AS "平均成绩"
FROM
student
LEFT JOIN
score
ON
score.s_id = student.s_id
GROUP BY
student.s_id
HAVING
AVG(score.s_score) < 60 OR AVG(score.s_score) IS NULL; # 5.查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩。
SELECT
student.s_id AS "学生编号",
student.s_name AS "学生姓名",
COUNT(course.c_id) AS "选课总数",
IFNULL(SUM(score.s_score),0) AS "所有课程总成绩"
FROM
student
LEFT JOIN
score
ON
student.s_id = score.s_id
LEFT JOIN
course
ON
course.c_id = score.c_id
GROUP BY
student.s_id; # 6.查询"李"姓老师的数量。
SELECT
COUNT(t_id)
FROM
teacher
WHERE
t_name LIKE "李%"; # 7.查询学过"张三"老师授课的同学的信息。
SELECT
student.*
FROM
student
LEFT JOIN
score
ON
student.s_id = score.s_id
LEFT JOIN
course
ON
score.c_id = course.c_id
LEFT JOIN
teacher
ON
course.t_id = teacher.t_id
WHERE
teacher.t_name = "张三"; # 8.查询没学过"张三"老师授课的同学的信息。
SELECT
student.*
FROM
student
WHERE
student.s_id NOT IN
(
SELECT
student.s_id
FROM
student
LEFT JOIN
score
ON
score.s_id = student.s_id
WHERE
score.c_id IN
(
SELECT
course.c_id
FROM
course
LEFT JOIN
teacher
ON
course.t_id = teacher.t_id
WHERE
teacher.t_name = "张三"
)
) # 9.查询学过编号为"1"并且也学过编号为"2"的课程的同学的信息。
SELECT
student.*
FROM
student
INNER JOIN
score
ON
score.s_id = student.s_id
INNER JOIN
course
ON
course.c_id = score.c_id
GROUP BY
student.s_id
HAVING
SUM(IF(course.c_id = 1 OR course.c_id = 2, 1, 0)) > 1; # 10.查询学过编号为"1"但是没有学过编号为"2"的课程的同学的信息。
SELECT
student.*
FROM
student
INNER JOIN
score
ON
score.s_id = student.s_id AND score.c_id = 1
WHERE
student.s_id NOT IN
(
SELECT
student.s_id
FROM
student
INNER JOIN
score
ON
score.s_id = student.s_id AND score.c_id = 2
); # 11.查询没有学全所有课程的同学的信息。
SELECT
student.*
FROM
student
LEFT JOIN
score
ON
score.s_id = student.s_id
GROUP BY
student.s_id
HAVING
COUNT(c_id) < (
SELECT
COUNT(c_id)
FROM
course
); # 12.查询至少有一门课与学号为"1的同学所学相同的同学的信息。
SELECT
student.*
FROM
student
LEFT JOIN
score
ON
score.s_id = student.s_id
WHERE
c_id IN (
SELECT
c_id
FROM
score
LEFT JOIN
student
ON
score.s_id = student.s_id
WHERE
student.s_id = 1
)
GROUP BY
student.s_id; # 13.查询和"1"号的同学学习的课程完全相同的其他同学的信息。
SELECT
student.*
FROM
student
LEFT JOIN
score
ON
score.s_id = student.s_id
GROUP BY
student.s_id
HAVING
GROUP_CONCAT(c_id) = (
SELECT
GROUP_CONCAT(c_id)
FROM
student
LEFT JOIN
score
ON
score.s_id = student.s_id
GROUP BY
student.s_id
HAVING
student.s_id = 1
); # 14.查询没学过"张三"老师讲授的任一门课程的学生姓名。
SELECT
s_name
FROM
student
WHERE
s_id NOT IN (
SELECT
s_id
FROM
score
INNER JOIN
course
ON
course.c_id = score.c_id
INNER JOIN
teacher
ON
teacher.t_id = course.t_id AND t_name = "张三"
); # 15.查询两门及其以上不及格课程的同学的学号,姓名及其平均成绩。
SELECT
student.s_id AS "学号",
s_name AS "姓名",
IFNULL(ROUND(AVG(s_score),2),0) AS "平均成绩"
FROM
student
LEFT JOIN
score
ON
score.s_id = student.s_id
GROUP BY
student.s_id
HAVING
SUM(IF(s_score < 60, 1, 0)) >= 2; SELECT st.s_id,st.s_name, sc.* FROM score AS sc LEFT JOIN student AS st ON sc.s_id = st.s_id WHERE sc.s_score < 60 GROUP BY sc.s_id; # 16.检索"1"课程分数小于60,按分数降序排列的学生信息。
SELECT
student.*,
s_score AS "分数"
FROM
student
INNER JOIN
score
ON
score.s_id = student.s_id AND c_id = 1
WHERE
s_score < 60
ORDER BY
s_score DESC; # 17.按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩。
SELECT
s_name,
IFNULL(s1.s_score, 0) AS "语文成绩",
IFNULL(s2.s_score, 0) AS "数学成绩",
IFNULL(s3.s_score, 0) AS "英语成绩",
IFNULL(ROUND(AVG(s4.s_score), 2), 0) AS "平均成绩"
FROM
student
LEFT JOIN
score AS s1
ON
s1.s_id = student.s_id AND s1.c_id = 1
LEFT JOIN
score AS s2
ON
s2.s_id = student.s_id AND s2.c_id = 2
LEFT JOIN
score AS s3
ON
s3.s_id = student.s_id AND s3.c_id = 3
LEFT JOIN
score AS s4
ON
s4.s_id = student.s_id
GROUP BY
student.s_id
ORDER BY
AVG(s4.s_score) DESC; # 18.查询各科成绩最高分、最低分和平均分:以如下形式显示:课程ID,课程name,最高分,最低分,平均分,及格率,中等率,优良率,优秀率。
# 及格为>=60,中等为:70-80,优良为:80-90,优秀为:>=90。
SELECT
course.c_id AS "课程ID",
c_name AS "课程名称",
MAX(s_score) AS "最高分",
MIN(s_score) AS "最低分",
AVG(s_score) AS "平均分",
(SUM(IF(s_score >= 60, 1, 0)) / COUNT(1)) AS "及格率",
(SUM(IF(s_score >= 70 AND s_score < 80, 1, 0)) / COUNT(1)) AS "中等率",
(SUM(IF(s_score >= 80 AND s_score < 90, 1, 0)) / COUNT(1)) AS "优良率",
(SUM(IF(s_score >= 90, 1, 0)) / COUNT(1)) AS "优秀率"
FROM
course
INNER JOIN
score
ON
score.c_id = course.c_id
GROUP BY
course.c_id; # 19.按各科成绩进行排序,并显示排名。
SELECT
c_name AS "课程名称",
s_score AS "分数",
(
CASE
WHEN @p = s_score THEN @rank
WHEN @p := s_score THEN @rank := @rank + 1
END
) AS "排名"
FROM
(
SELECT
c_name,
s_score
FROM
course
INNER JOIN
score
ON
score.c_id = course.c_id
WHERE
course.c_id = 1
ORDER BY
s_score DESC
) AS tab,
(SELECT @rank := 0, @p := NULL) AS r
UNION ALL
SELECT
c_name AS "课程名称",
s_score AS "分数",
(
CASE
WHEN @p2 = s_score THEN @rank2
WHEN @p2 := s_score THEN @rank2 := @rank2 + 1
END
) AS "排名"
FROM
(
SELECT
c_name,
s_score
FROM
course
INNER JOIN
score
ON
score.c_id = course.c_id
WHERE
course.c_id = 2
ORDER BY
s_score DESC
) AS tab,
(SELECT @rank2 := 0, @p2 := NULL) AS r
UNION ALL
SELECT
c_name AS "课程名称",
s_score AS "分数",
(
CASE
WHEN @p3 = s_score THEN @rank3
WHEN @p3 := s_score THEN @rank3 := @rank3 + 1
END
) AS "排名"
FROM
(
SELECT
c_name,
s_score
FROM
course
INNER JOIN
score
ON
score.c_id = course.c_id
WHERE
course.c_id = 3
ORDER BY
s_score DESC
) AS tab,
(SELECT @rank3 := 0, @p3 := NULL) AS r; # 20.查询学生的总成绩并进行排名。
SELECT
s_name AS "学生姓名",
IFNULL(SUM(s_score), 0) AS "总成绩"
FROM
student
LEFT JOIN
score
ON
score.s_id = student.s_id
GROUP BY
student.s_id
ORDER BY
SUM(s_score) DESC; # 21.查询不同老师所教不同课程平均分从高到低显示。
SELECT
teacher.t_name AS "老师姓名",
c_name AS "课程名称",
AVG(s_score) AS "平均分"
FROM
teacher
INNER JOIN
course
ON
course.t_id = teacher.t_id
INNER JOIN
score
ON
score.c_id = course.c_id
GROUP BY
course.c_id
ORDER BY
AVG(s_score) DESC; # 22.查询所有课程的成绩第2名到第3名的学生信息及该课程成绩。
(SELECT
c_name AS "课程名称",
student.*,
s_score AS "分数"
FROM
student
INNER JOIN
score
ON
student.s_id = score.s_id
INNER JOIN
course
ON
course.c_id = score.c_id AND course.c_id = 1
ORDER BY
s_score DESC
LIMIT 1, 2)
UNION ALL
(SELECT
c_name AS "课程名称",
student.*,
s_score AS "分数"
FROM
student
INNER JOIN
score
ON
student.s_id = score.s_id
INNER JOIN
course
ON
course.c_id = score.c_id AND course.c_id = 2
ORDER BY
s_score DESC
LIMIT 1, 2)
UNION ALL
(SELECT
c_name AS "课程名称",
student.*,
s_score AS "分数"
FROM
student
INNER JOIN
score
ON
student.s_id = score.s_id
INNER JOIN
course
ON
course.c_id = score.c_id AND course.c_id = 3
ORDER BY
s_score DESC
LIMIT 1, 2); # 23.统计各科成绩各分数段人数:课程编号,课程名称,[100-85],[85-70],[70-60],[0-60]及所占百分比。
SELECT
course.c_id AS "课程编号",
c_name AS "课程名称",
SUM(IF(s_score > 85 AND s_score <= 100, 1, 0)) AS "[85-100]人数",
(SUM(IF(s_score > 85 AND s_score <= 100, 1, 0)) / COUNT(1)) AS "所百分比",
SUM(IF(s_score > 70 AND s_score <= 85, 1, 0)) AS "[70-85]人数",
(SUM(IF(s_score > 70 AND s_score <= 85, 1, 0)) / COUNT(1)) AS "所百分比",
SUM(IF(s_score > 60 AND s_score <= 70, 1, 0)) AS "[60-70]人数",
(SUM(IF(s_score > 60 AND s_score <= 70, 1, 0)) / COUNT(1)) AS "所百分比",
SUM(IF(s_score <= 60, 1, 0)) AS "[0-60]人数",
(SUM(IF(s_score <= 60, 1, 0)) / COUNT(1)) AS "所百分比"
FROM
score
INNER JOIN
course
ON
score.c_id = course.c_id
GROUP BY
course.c_id; # 24.查询学生平均成绩及其名次。
SELECT
s_name AS "学生姓名",
avg AS "平均分",
(
CASE
WHEN @p = avg THEN @rank
WHEN @p := avg THEN @rank := @rank + 1
END
) AS "排名"
FROM
(
SELECT
s_name,
ROUND(IFNULL(AVG(s_score), 0), 2) AS avg
FROM
student
LEFT JOIN
score
ON
score.s_id = student.s_id
GROUP BY
student.s_id
ORDER BY
AVG(s_score) DESC
) AS tab,
(SELECT @rank := 0, @p := NULL) AS r; # 25.查询各科成绩前三名的记录。
(SELECT
c_name AS "课程名称",
s_score AS "分数"
FROM
score
INNER JOIN
course
ON
course.c_id = score.c_id AND course.c_id = 1
ORDER BY
s_score DESC
LIMIT 3)
UNION ALL
(SELECT
c_name AS "课程名称",
s_score AS "分数"
FROM
score
INNER JOIN
course
ON
course.c_id = score.c_id AND course.c_id = 2
ORDER BY
s_score DESC
LIMIT 3)
UNION ALL
(SELECT
c_name AS "课程名称",
s_score AS "分数"
FROM
score
INNER JOIN
course
ON
course.c_id = score.c_id AND course.c_id = 3
ORDER BY
s_score DESC
LIMIT 3) # 26.查询每门课程被选修的学生数。
SELECT
c_name AS "课程名称",
COUNT(s_id) AS "人数"
FROM
course
INNER JOIN
score
ON
score.c_id = course.c_id
GROUP BY
course.c_id; # 27.查询出只有两门课程的全部学生的学号和姓名。
SELECT
student.s_id AS "学号",
s_name AS "姓名"
FROM
student
LEFT JOIN
score
ON
score.s_id = student.s_id
GROUP BY
student.s_id
HAVING
COUNT(score.c_id) = 2; # 28.查询男生、女生人数。
SELECT
s_sex AS "性别",
COUNT(s_sex) AS "人数"
FROM
student
GROUP BY
s_sex; # 29.查询名字中含有"风"字的学生信息。
SELECT
*
FROM
student
WHERE
s_name LIKE "%风%"; # 30.查询同名同性学生名单,并统计同名人数。
SELECT
s_name AS "姓名",
s_sex AS "性别",
COUNT(s_name) AS "人数"
FROM
student
GROUP BY
s_name,
s_sex
HAVING
COUNT(s_name) > 1; # 31.查询1990年出生的学生名单。
SELECT
s_name AS "姓名"
FROM
student
WHERE
s_birth LIKE "1990%"; # 32.查询每门课程的平均成绩,结果按平均成绩降序排列,平均成绩相同时,按课程编号升序排列。
SELECT
course.c_id AS "课程编号",
c_name AS "课程名称",
ROUND(AVG(s_score), 2) AS "平均成绩"
FROM
score
INNER JOIN
course
ON
course.c_id = score.c_id
GROUP BY
course.c_id
ORDER BY
AVG(s_score) DESC,
course.c_id ASC; # 33.查询平均成绩大于等于85的所有学生的学号、姓名和平均成绩。
SELECT
student.s_id AS "编号",
s_name AS "姓名",
ROUND(AVG(s_score), 2) AS "平均成绩"
FROM
student
LEFT JOIN
score
ON
student.s_id = score.s_id
GROUP BY
student.s_id
HAVING
AVG(s_score) >= 85; # 34.查询课程名称为"数学",且分数低于60的学生姓名和分数。
SELECT
s_name AS "学生姓名",
s_score AS "分数"
FROM
student
INNER JOIN
score
ON
student.s_id = score.s_id
INNER JOIN
course
ON
course.c_id = score.c_id AND c_name = "数学"
WHERE
s_score < 60; # 35.查询所有学生的课程及分数情况。
SELECT
student.s_id AS "学号",
s_name AS "姓名",
c_name AS "课程名称",
IFNULL(s_score, 0) AS "分数"
FROM
student
LEFT JOIN
score
ON
score.s_id = student.s_id
LEFT JOIN
course
ON
course.c_id = score.c_id; # 36.查询任何一门课程成绩在70分以上的姓名、课程名称和分数。
SELECT
s_name AS "姓名",
c_name AS "课程名称",
s_score AS "分数"
FROM
student
LEFT JOIN
score
ON
score.s_id = student.s_id
LEFT JOIN
course
ON
course.c_id = score.c_id
WHERE
s_score > 70; # 37.查询不及格的课程。
SELECT
c_name AS "课程名称",
s_score AS "分数"
FROM
course
INNER JOIN
score
ON
score.c_id = course.c_id
WHERE
s_score < 60; # 38.查询课程编号为"1程成绩在80分以上的学生的学号和姓名。
SELECT
student.s_id AS "学号",
s_name AS "姓名"
FROM
student
INNER JOIN
score
ON
score.s_id = student.s_id AND c_id = 1 AND s_score >= 80; # 39.求每门课程的学生人数。
SELECT
c_name AS "课程名称",
COUNT(s_id) AS "学生人数"
FROM
course
INNER JOIN
score
ON
score.c_id = course.c_id
GROUP BY
course.c_id; # 40.查询选修"张三"老师所授课程的学生中,成绩最高的学生信息及其成绩。
SELECT
student.*,
s_score AS "分数"
FROM
student
INNER JOIN
score
ON
score.s_id = student.s_id
INNER JOIN
course
ON
course.c_id = score.c_id
INNER JOIN
teacher
ON
teacher.t_id = course.t_id
WHERE
t_name = "张三"
ORDER BY
s_score DESC
LIMIT 1; # 41.查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩。
SELECT
student.s_id AS "学生学号",
s_name AS "学生姓名",
s1.c_id AS "课程编号",
s1.s_score AS "分数"
FROM
student
LEFT JOIN
score AS s1
ON
s1.s_id = student.s_id
LEFT JOIN
course AS c1
ON
c1.c_id = s1.c_id
WHERE
(
SELECT
COUNT(1)
FROM
student
LEFT JOIN
score AS s2
ON
s2.s_id = student.s_id
LEFT JOIN
course AS c2
ON
c2.c_id = s2.c_id
WHERE
s1.s_score = s2.s_score
AND
c1.c_id != c2.c_id
) > 1; # 42.查询每门功成绩最好的前两名。
(
SELECT
c_name AS "课程名称",
s_name AS "学生姓名",
s_score AS "分数"
FROM
student
LEFT JOIN
score
ON
score.s_id = student.s_id
LEFT JOIN
course
ON
course.c_id = score.c_id
WHERE
course.c_id = 1
LIMIT 2
)
UNION ALL
(
SELECT
c_name AS "课程名称",
s_name AS "学生姓名",
s_score AS "分数"
FROM
student
LEFT JOIN
score
ON
score.s_id = student.s_id
LEFT JOIN
course
ON
course.c_id = score.c_id
WHERE
course.c_id = 2
LIMIT 2
)
UNION ALL
(
SELECT
c_name AS "课程名称",
s_name AS "学生姓名",
s_score AS "分数"
FROM
student
LEFT JOIN
score
ON
score.s_id = student.s_id
LEFT JOIN
course
ON
course.c_id = score.c_id
WHERE
course.c_id = 3
LIMIT 2
); # 43.统计每门课程的学生选修人数(超过5人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,若人数相同,按课程号升序排列。
SELECT
c_id AS "课程编号",
COUNT(s_score) AS "学生人数"
FROM
score
GROUP BY
c_id
HAVING
COUNT(s_score) > 5
ORDER BY
COUNT(s_score) DESC,
c_id ASC; # 44.检索至少选修两门课程的学生学号。
SELECT
s_id AS "学号"
FROM
score
GROUP BY
s_id
HAVING
COUNT(c_id) >= 2; # 45.查询选修了全部课程的学生信息。
SELECT
student.*
FROM
student
LEFT JOIN
score
ON
score.s_id = student.s_id
GROUP BY
student.s_id
HAVING
COUNT(c_id) = (
SELECT
COUNT(1)
FROM
course
); # 46.查询各学生的年龄。
SELECT
s_name AS "姓名",
TIMESTAMPDIFF(YEAR, s_birth, NOW())
FROM
student; # 47.查询本周过生日的学生。
SELECT
student.*
FROM
student
WHERE
WEEK(NOW(), 1) = WEEK(CONCAT(YEAR(s_birth), '-', MONTH(s_birth), '-', DAY(s_birth)), 1); # 48.查询下周过生日的学生。
SELECT
student.*
FROM
student
WHERE
WEEK(NOW(), 1) = WEEK(CONCAT(YEAR(s_birth), '-', MONTH(s_birth), '-', DAY(s_birth)), 1) - 1; # 49.查询本月过生日的学生。
SELECT
student.*
FROM
student
WHERE
MONTH(NOW()) = MONTH(CONCAT(YEAR(s_birth), '-', MONTH(s_birth), '-', DAY(s_birth))); # 50.查询下月过生日的学生。
SELECT
student.*
FROM
student
WHERE
MONTH(NOW()) = MONTH(CONCAT(YEAR(s_birth), '-', MONTH(s_birth), '-', DAY(s_birth))) - 1;

如有问题或有更优写法,欢迎大家留言提建议!

MySQL最经典50道练习题的更多相关文章

  1. 转,sql 50道练习题

    SQL语句50题   -- 一.创建教学系统的数据库,表,以及数据 --student(sno,sname,sage,ssex) 学生表--course(cno,cname,tno) 课程表--sc( ...

  2. 50道sql练习题和答案

    最近两年的工作没有写过多少SQL,感觉水平下降十分严重,网上找了50道练习题学习和复习 原文地址:50道SQL练习题及答案与详细分析 1.0数据表介绍 --1.学生表 Student(SId,Snam ...

  3. 50道SQL练习题及答案与详细分析(MySQL)

    50道SQL练习题及答案与详细分析(MySQL) 网上的经典50到SQL题,经过一阵子的半抄带做,基于个人理解使用MySQL重新完成一遍,感觉个人比较喜欢用join,联合查询较少 希望与大家一起学习研 ...

  4. Mysql Sql 语句练习题 (50道)

    MySql 语句练习50题 表名和字段 –1.学生表 Student(s_id,s_name,s_birth,s_sex) –学生编号,学生姓名, 出生年月,学生性别 –2.课程表 Course(c_ ...

  5. 学生选课数据库SQL语句45道练习题整理及mysql常用函数(20161019)

    学生选课数据库SQL语句45道练习题: 一.            设有一数据库,包括四个表:学生表(Student).课程表(Course).成绩表(Score)以及教师信息表(Teacher).四 ...

  6. 【不断更新】mysql经典50道题自我练习

    mysql经典50道题自我练习 测试数据和练习题均转载自CSDN博主@启明星的指引的文章sql语句练习50题(Mysql版),用于mysql的每日自我练习 表名和字段 –1.学生表 Student(s ...

  7. 100道MySQL数据库经典面试题解析(收藏版)

    前言 100道MySQL数据库经典面试题解析,已经上传github啦 https://github.com/whx123/JavaHome/tree/master/Java面试题集结号 公众号:捡田螺 ...

  8. 50道经典的JAVA编程题(汇总)

    这是一次不可思议的编程历程.从2013年的最后一天开始做这份题,中间连续好几天的考试,包括java考试(今天考试的JAVA编程题),直到今天完成了.挺有成就感的...废话不多说了,来电实质性的吧. 全 ...

  9. 50道经典的JAVA编程题(46-50)

    50道经典的JAVA编程题(46-50),最后五道题了,这是一个美妙的过程,编程真的能让我忘掉一切投入其中,感觉很棒.今天下午考完微机原理了,大三上学期就这样度过了,这学期算是解放了,可是感觉我还是没 ...

随机推荐

  1. SpringIOC基础知识总结

    目录 1.BeanFactory和ApplicationContext的区别: 2.实例化bean的三种方式: ⽅式⼀:使⽤⽆参构造函数 ⽅式⼆:使⽤静态⽅法创建 ⽅式三:使⽤实例化⽅法创建 3.Be ...

  2. elasticsearch集群安装+安全验证+kibana安装

    准备环境 启动4个centos容器, 并暴露相对应端口 (我的本机ip为172.16.1.236,以下涉及到的地方需要修改为自己的ip) node_name ip http port transpor ...

  3. [原题复现+审计][ZJCTF 2019] WEB NiZhuanSiWei(反序列化、PHP伪协议、数组绕过)

    简介  原题复现:https://github.com/CTFTraining/zjctf_2019_final_web_nizhuansiwei/  考察知识点:反序列化.PHP伪协议.数组绕过   ...

  4. Markdown进阶

    ### 事项清单 - [x] 拖地 - [x] 擦窗 - [ ] 写作业 - [ ] 交资料 效果 事项清单 [x] 拖地 [x] 擦窗 [ ] 写作业 [ ] 交资料 流程图 graph LR A[ ...

  5. 标准库之time,random,sys,os

    # import time # print(time.time()) # 时间戳 # print(time.mktime(time.localtime())) # 结构化时间转换为时间戳 # prin ...

  6. 【ES6】ES6入门笔记

    1.概要 - ECMAScript2015(ES6)是Javascript最标准的语法式样,是在2015年6月由Ecma国籍组织公布的最新版本,现在已经被多个领域和浏览器所广泛采纳和使用. 2.学习网 ...

  7. ELK---- Elasticsearch 使用ik中文分词器增加拓展热词

    进入到我们ik分词器安装目录下的config目录 cd /usr/local/myapp/elasticsearch-6.4.3/plugins/ik/configvi IKAnalyzer.cfg. ...

  8. symfony框架中使用service

    在config文件里面的service.yml写入自己service 1 chat.group_list: //service的名字 2 class: Chat\Service\GroupListSe ...

  9. c++11-17 模板核心知识(九)—— 理解decltype与decltype(auto)

    decltype介绍 为什么需要decltype decltype(auto) 注意(entity) 与模板参数推导和auto推导一样,decltype的结果大多数情况下是正常的,但是也有少部分情况是 ...

  10. PowerManagerService流程分析

    一.PowerManagerService简介 PowerManagerService主要服务Android系统电源管理工作,这样讲比较笼统,就具体细节上大致可以认为PowerManagerServi ...