Dragon Balls

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 6086 Accepted Submission(s): 2248

Problem Description
Five hundred years later, the number of dragon balls will increase unexpectedly, so it's too difficult for Monkey King(WuKong) to gather all of the dragon balls together.

His country has N cities and there are exactly N dragon balls in the world. At first, for the ith dragon ball, the sacred dragon will puts it in the ith city. Through long years, some cities' dragon ball(s) would be transported to other cities. To save physical strength WuKong plans to take Flying Nimbus Cloud, a magical flying cloud to gather dragon balls.
Every time WuKong will collect the information of one dragon ball, he will ask you the information of that ball. You must tell him which city the ball is located and how many dragon balls are there in that city, you also need to tell him how many times the ball has been transported so far.

Input
The first line of the input is a single positive integer T(0 < T <= 100).
For each case, the first line contains two integers: N and Q (2 < N <= 10000 , 2 < Q <= 10000).
Each of the following Q lines contains either a fact or a question as the follow format:
T A B : All the dragon balls which are in the same city with A have been transported to the city the Bth ball in. You can assume that the two cities are different.
Q A : WuKong want to know X (the id of the city Ath ball is in), Y (the count of balls in Xth city) and Z (the tranporting times of the Ath ball). (1 <= A, B <= N)

Output
For each test case, output the test case number formated as sample output. Then for each query, output a line with three integers X Y Z saparated by a blank space.

Sample Input
2
3 3
T 1 2
T 3 2
Q 2
3 4
T 1 2
Q 1
T 1 3
Q 1

Sample Output
Case 1:
2 3 0
Case 2:
2 2 1
3 3 2

跟上道题差不多,忘记输出case了,mdzz。

#include <stdio.h>
#include <string.h>
int size[], cnt[];
int asd;
class Union_Find_Set {
#define MAX_UNION_FIND_SET_SIZE 10005
public:
int setSize;
int father[MAX_UNION_FIND_SET_SIZE];
Union_Find_Set() {
setSize = ;
}
Union_Find_Set(int x) {
setSize = x;
clear(x);
}
void clear(int x) {
for (int i = ; i < x; i++) {
father[i] = i;
}
}
int getFather(int x) {
asd = cnt[x];
int ret = x, tmp;
while (ret != father[ret]) {
asd += cnt[father[ret]];
ret = father[ret];
}
int ttt = asd - cnt[ret];
while (x != father[x]) {
tmp = father[x];
father[x] = ret;
ttt -= cnt[x];
cnt[x] += ttt;
x = tmp;
}
return ret;
}
bool merge(int a, int b) {
a = getFather(a);
b = getFather(b);
if (a != b) {
father[a] = b;
cnt[a]++;
size[b] += (size[a] + );
return true;
} else {
return false;
}
}
int countRoot() {
int ret = ;
for (int i = ; i < setSize; i++) {
if (father[i] = i) {
ret++;
}
}
return ret;
}
};
Union_Find_Set ufs;
int main() {
int tt;
scanf("%d", &tt);
for (int jjjj = ; jjjj <= tt; jjjj++) {
printf("Case %d:\n", jjjj);
int n, q, a, b;
char t;
scanf("%d%d", &n, &q);
ufs.clear();
memset(size, , sizeof(size));
memset(cnt, , sizeof(cnt));
while (q--) {
getchar();
scanf("%c", &t);
if (t == 'T') {
scanf("%d%d", &a, &b);
ufs.merge(a, b);
} else if (t == 'Q') {
scanf("%d", &a);
int f = ufs.getFather(a);
printf("%d %d %d\n", f, size[f] + , asd);
}
}
}
return ;
}

Dragon Balls[HDU3635]的更多相关文章

  1. Dragon Balls(hdu3635带权并查集)

    题意:n个城市有n个龙珠,T  a,b 代表将龙珠a移动到b城市,Q a代表查询龙珠a所在城市,该城市有多少颗龙珠,该龙珠移动了多少次. 注意:移动时是将龙珠所在该城市所有龙珠都移动,每个龙珠不会再回 ...

  2. hdu3635 Dragon Balls

    Problem Description Five hundred years later, the number of dragon balls will increase unexpectedly, ...

  3. hdu 3635 Dragon Balls(并查集)

    Dragon Balls Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Tota ...

  4. hdu 3635 Dragon Balls (带权并查集)

    Dragon Balls Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Tota ...

  5. hdu 3635 Dragon Balls

    Dragon Balls Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Tot ...

  6. hdoj 3635 Dragon Balls【并查集求节点转移次数+节点数+某点根节点】

    Dragon Balls Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)Tota ...

  7. hdu 3635 Dragon Balls(并查集应用)

    Problem Description Five hundred years later, the number of dragon balls will increase unexpectedly, ...

  8. Dragon Balls

    Dragon Balls Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) Total ...

  9. HDU 3635:Dragon Balls(并查集)

    Dragon Balls Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others) Tot ...

随机推荐

  1. 资深程序员总结:彻底理解Spring容器和应用上下文

    点关注,不迷路:持续更新Java架构相关技术及资讯热文!!! 有了Spring之后,通过依赖注入的方式,我们的业务代码不用自己管理关联对象的生命周期.业务代码只需要按照业务本身的流程,走啊走啊,走到哪 ...

  2. JS 猴子

    公园里有一只猴子和一堆桃子,猴子每天吃掉桃子总数的一半,把剩下一半中扔掉一个坏的. 到第七天的时候,猴子睁开眼发现只剩下一个桃子.问公园里刚开始有多少个桃子? <!DOCTYPE html> ...

  3. JQ淡入淡出效果

    <script type="text/javascript"> //页面淡入淡出 $(document).ready(function() { $('body').hi ...

  4. laravel 运行migrate报错 1071 Specified key was too long

     转自:https://segmentfault.com/a/1190000008416200 laravel运行命令migrate时报错: 1071 Specified key was too lo ...

  5. There are no packages available for installation. Sublime3解决方法

    最近在学习Vue,在配置sublime3的时候,想要高亮vue的语法,下载点插件 Package Control的时候,总报  There are no packages available for ...

  6. 洛谷P1914 小书童——密码

    题目背景 某蒟蒻迷上了"小书童",有一天登陆时忘记密码了(他没绑定邮箱or手机),于是便把问题抛给了神犇你. 题目描述 蒟蒻虽然忘记密码,但他还记得密码是由一串字母组成.且密码是由 ...

  7. [luogu2585 ZJOI2006] 三色二叉树 (树形dp)

    传送门 Description Input 输入文件名:TRO.IN 输入文件仅有一行,不超过500000个字符,表示一个二叉树序列. Output 输出文件名:TRO.OUT 输出文件也只有一行,包 ...

  8. JavaScript基础简介

    JavaScript引入的方式 直接在<script>标签中写 <script> console.log('hello world!'); </script> 引入 ...

  9. python 协程 greenlet gevent

    一.并发的本质 切换+保存状态 cpu正在运行一个任务,会在两种情况下切走去执行其他的任务(切换由操作系统强制控制),一种情况是该任务发生了阻塞,另外一种情况是该任务计算的时间过长时间片到了 二.协程 ...

  10. 00072_System类

    1.概念 (1)System中代表程序所在系统,提供了对应的一些系统属性信息,和系统操作: (2)System类不能手动创建对象,因为构造方法被private修饰,阻止外界创建对象: (3)Syste ...