time limit per test1 second

memory limit per test256 megabytes

inputstandard input

outputstandard output

Vasiliy spent his vacation in a sanatorium, came back and found that he completely forgot details of his vacation!

Every day there was a breakfast, a dinner and a supper in a dining room of the sanatorium (of course, in this order). The only thing that Vasiliy has now is a card from the dining room contaning notes how many times he had a breakfast, a dinner and a supper (thus, the card contains three integers). Vasiliy could sometimes have missed some meal, for example, he could have had a breakfast and a supper, but a dinner, or, probably, at some days he haven’t been at the dining room at all.

Vasiliy doesn’t remember what was the time of the day when he arrived to sanatorium (before breakfast, before dinner, before supper or after supper), and the time when he left it (before breakfast, before dinner, before supper or after supper). So he considers any of these options. After Vasiliy arrived to the sanatorium, he was there all the time until he left. Please note, that it’s possible that Vasiliy left the sanatorium on the same day he arrived.

According to the notes in the card, help Vasiliy determine the minimum number of meals in the dining room that he could have missed. We shouldn’t count as missed meals on the arrival day before Vasiliy’s arrival and meals on the departure day after he left.

Input

The only line contains three integers b, d and s (0 ≤ b, d, s ≤ 1018,  b + d + s ≥ 1) — the number of breakfasts, dinners and suppers which Vasiliy had during his vacation in the sanatorium.

Output

Print single integer — the minimum possible number of meals which Vasiliy could have missed during his vacation.

Examples

input

3 2 1

output

1

input

1 0 0

output

0

input

1 1 1

output

0

input

1000000000000000000 0 1000000000000000000

output

999999999999999999

Note

In the first sample, Vasiliy could have missed one supper, for example, in case he have arrived before breakfast, have been in the sanatorium for two days (including the day of arrival) and then have left after breakfast on the third day.

In the second sample, Vasiliy could have arrived before breakfast, have had it, and immediately have left the sanatorium, not missing any meal.

In the third sample, Vasiliy could have been in the sanatorium for one day, not missing any meal.

【题解】



原本以为是很复杂的分类讨论问题;

推了下

a>=b>=c

a>=c>=b

b>=a>=c之后

设最大的数为a,其他两个数无所谓为b和c;

发现答案都是max(a-1,b)-b+max(a-1,c)-c;

然后就大胆的排序贪心下;

#include <cstdio>
#include <algorithm>
#define LL long long using namespace std; LL a[4]; int main()
{
//freopen("F:\\rush.txt", "r", stdin);
scanf("%I64d%I64d%I64d",&a[1],&a[2],&a[3]);
sort(a + 1, a + 1 + 3);
LL ans;
ans = max(a[3] - 1, a[2]) - a[2] + max(a[3] - 1, a[1]) - a[1];
printf("%I64d\n", ans);
return 0;
}

【43.26%】【codeforces 732C】Sanatorium的更多相关文章

  1. 【 BowWow and the Timetable CodeForces - 1204A 】【思维】

    题目链接 可以发现 十进制4 对应 二进制100 十进制16 对应 二进制10000 十进制64 对应 二进制1000000 可以发现每多两个零,4的次幂就增加1. 用string读入题目给定的二进制 ...

  2. 【26.83%】【Codeforces Round #380C】Road to Cinema

    time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard ou ...

  3. 【41.43%】【codeforces 560C】Gerald's Hexagon

    time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard o ...

  4. 【26.09%】【codeforces 579C】A Problem about Polyline

    time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard ou ...

  5. 【26.67%】【codeforces 596C】Wilbur and Points

    time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard o ...

  6. 【30.43%】【codeforces 746C】Tram

    time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard ou ...

  7. 【23.26%】【codeforces 747D】Winter Is Coming

    time limit per test1 second memory limit per test256 megabytes inputstandard input outputstandard ou ...

  8. 【codeforces 797C】Minimal string

    [题目链接]:http://codeforces.com/contest/797/problem/C [题意] 一开始,给你一个字符串s:两个空字符串t和u; 你有两种合法操作; 1.将s的开头字符加 ...

  9. 【codeforces 510C】Fox And Names

    [题目链接]:http://codeforces.com/contest/510/problem/C [题意] 给你n个字符串; 问你要怎么修改字典序; (即原本是a,b,c..z现在你可以修改每个字 ...

随机推荐

  1. Android 6.0 扫描不到 Ble 设备需开启位置权限

    Android 6.0 扫描不到 Ble 设备需开启位置权限 之前做 Ble 开发都是在 Android 6.0 系统以下的版本中进行测试的,今天使用 Android 6.0 的设备测试的时候,发现扫 ...

  2. IDEACould not autowire. No beans of 'xxxMapper' type found.

    作为一名刚开始使用idea的新手,最近在使用maven+springMVC框架时遇到了这样一个问题:Could not autowire. No beans of 'xxxMapper' type f ...

  3. LA 4329 - Ping pong 树状数组(Fenwick树)

    先放看题传送门 哭瞎了,交上去一直 Runtime error .以为那里错了. 狂改!!!!! 然后还是一直... 继续狂改!!!!... 一直.... 最后发现数组开小了.......... 果断 ...

  4. 9.9 Binder系统_Java实现_Android里java程序的编译启动

    如果知道了进程号:通过ls /proc/进程号/task 可以看到所有线程    cat /proc/进程号/task/线程号/comm  可以达到线程名字(主线程是main,主线程号就是进程号) d ...

  5. Android中各种drawable的使用

    转载请说明出处.本文来自Android菜鸟:http://blog.csdn.net/android_cai_niao/article/details/46854767  QQ:2717521606 ...

  6. node-sass的安装问题

    1.认识node-sass 我觉得要解决node-sass的问题,你首先至少要简单的了解node-sass是个什么东西?为什么要安装它? 对于在项目中使用sass的语法的时候,需要通过sass-loa ...

  7. image-base64互转

    package base64StringToImage; import java.awt.image.BufferedImage; import java.io.ByteArrayInputStrea ...

  8. js javascript正则

    var re = new RegExp("^[0-9]$"); 或者 var re2 = /^\d$/;//这个好像兼容性更好,比如你在上面的语句里面写\d,就总是返回false, ...

  9. GCD网络多线程---同步运行,异步运行,串行队列,并行队列

    总结:同步(无论是串行还是并行)----不又一次开辟子线程 异步(无论是串行还是并行)----开辟子线程 GCD: dispatch queue 主线程的main queue 并行队列 global ...

  10. Android JNI编程(六)——C语言函数指针、Unition联合体、枚举、Typedef别名、结构体、结构体指针

    版权声明:本文出自阿钟的博客,转载请注明出处:http://blog.csdn.net/a_zhon/. 目录(?)[+] 一:函数指针 1.函数指针顾名思义就是定义一个指针变量指向一个函数,和一级指 ...