LeetCode 343
Integer Break
Given a positive integer n, break it into the sum of at least two positive integers
and maximize the product of those integers. Return the maximum product you can get.
For example, given n = 2, return 1 (2 = 1 + 1); given n = 10, return 36 (10 = 3 + 3 + 4).
Note: you may assume that n is not less than 2.
Hint:
There is a simple O(n) solution to this problem.
You may check the breaking results of n ranging from 7 to 10 to discover the regularities.
/*************************************************************************
> File Name: LeetCode343.c
> Author: Juntaran
> Mail: Jacinthmail@gmail.com
> Created Time: Tue 10 May 2016 04:17:35 PM CST
************************************************************************/ /************************************************************************* Integer Break Given a positive integer n, break it into the sum of at least two positive integers
and maximize the product of those integers. Return the maximum product you can get. For example, given n = 2, return 1 (2 = 1 + 1); given n = 10, return 36 (10 = 3 + 3 + 4). Note: you may assume that n is not less than 2. Hint: There is a simple O(n) solution to this problem.
You may check the breaking results of n ranging from 7 to 10 to discover the regularities. ************************************************************************/ #include<stdio.h> int integerBreak( int n )
{
if( n <= )
{
return ;
}
if( n == )
{
return ;
}
int ret = ;
while( n > )
{
ret *= ;
n -= ;
}
return ret*n;
} int main()
{
int n = ;
int ret = integerBreak(n);
printf("%d\n",ret); return ;
}
LeetCode 343的更多相关文章
- LeetCode 343.整数拆分 - JavaScript
题目描述:给定一个正整数 n,将其拆分为至少两个正整数的和,并使这些整数的乘积最大化. 返回你可以获得的最大乘积. 题目分析 题目中"n 至少可以拆分为两个正整数的和",这个条件说 ...
- [LeetCode] 343. Integer Break 整数拆分
Given a positive integer n, break it into the sum of at least two positive integers and maximize the ...
- LeetCode 343. 整数拆分(Integer Break) 25
343. 整数拆分 343. Integer Break 题目描述 给定一个正整数 n,将其拆分为至少两个正整数的和,并使这些整数的乘积最大化. 返回你可以获得的最大乘积. 每日一算法2019/5/2 ...
- leetcode@ [343] Integer Break (Math & Dynamic Programming)
https://leetcode.com/problems/integer-break/ Given a positive integer n, break it into the sum of at ...
- leetcode 343. Integer Break(dp或数学推导)
Given a positive integer n, break it into the sum of at least two positive integers and maximize the ...
- LN : leetcode 343 Integer Break
lc 343 Integer Break 343 Integer Break Given a positive integer n, break it into the sum of at least ...
- Java实现 LeetCode 343 整数拆分(动态规划入门经典)
343. 整数拆分 给定一个正整数 n,将其拆分为至少两个正整数的和,并使这些整数的乘积最大化. 返回你可以获得的最大乘积. 示例 1: 输入: 2 输出: 1 解释: 2 = 1 + 1, 1 × ...
- Leetcode 343. Integer Break
Given a positive integer n, break it into the sum of at least two positive integers and maximize the ...
- leetcode 343 整数拆分
1.这个题拿到之后没有什么思路,此时就应该考虑暴力法.然而每次不知道要拆成几份,没办法用循环,所以想到用递归. 如图所示进行递归,显然有很多重复的计算,所以用自底向上的动态规划. 2.还有一个问题就是 ...
随机推荐
- 【转】Nginx系列(三)--管理进程、多工作进程设计
原博文出于:http://blog.csdn.net/liutengteng130/article/details/46700999 感谢! Nginx由一个master进程和多个worker进程组 ...
- (转)php的扩展和嵌入--php的生命周期与变量详述
本文转自http://blog.csdn.net/cedricliang/article/details/17247749?9435:这是在我想在js的循环中加入一段php,这段php代码会在每次执行 ...
- 关于P2P架构的网络游戏
以下内容摘自<ActionScript大型网页游戏开发> ————————————————————————————————————————————————————————— P2P架构 P ...
- poj 2226 Muddy Fields(最小覆盖点+构图)
http://poj.org/problem?id=2226 Muddy Fields Time Limit: 1000MS Memory Limit: 65536K Total Submissi ...
- java数字保留两位小数四舍五入
import java.math.BigDecimal; import java.text.DecimalFormat; import java.text.NumberFormat; public c ...
- UVaLive 6862 Triples (数学+分类讨论)
题意:给定一个n和m,问你x^j + y^j = z^j 的数量有多少个,其中0 <= x <= y <= z <= m, j = 2, 3, 4, ... n. 析:是一个数 ...
- Unity3D之Mecanim动画系统学习笔记(十一):高级功能应用
动作游戏 还记得读书的时候熬夜打<波斯王子>的时光,我们的王子通过跳跃穿过墙壁的小洞.在高层建筑上进行攀爬和跳跃,还有在操作失误掉下高楼和触发必死机关后使用时之沙的时光倒流功能回归死亡之前 ...
- Js面向对象和数据类型内存分配(转)
一 Js基本数据类型以及内存情况 1 Undefined Undefined类型只有一个值undefined,在使用了声明但未初始化的变量的时候,这个变量值就是undefined 1 var hi; ...
- 正则表达式从右往左进行匹配(Regex)
#匹配最末两位为数字 $x=New-Object regex ('\d{2}','RightToLeft') #$x.RightToLeft $x.Match('abcd22') 结果:
- SPOJ LIS2 Another Longest Increasing Subsequence Problem 三维偏序最长链 CDQ分治
Another Longest Increasing Subsequence Problem Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://a ...