leetcode@ [136/137] Single Number & Single Number II
https://leetcode.com/problems/single-number/
Given an array of integers, every element appears twice except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
class Solution {
public:
int singleNumber(vector<int>& nums) {
if(nums.size() == ) return nums[]; vector<int> bitNums(, ); int res = ;
for(int i=;i<bitNums.size();++i) {
for(int j=;j<nums.size();++j) {
bitNums[i] += (nums[j] >> i) & ;
}
res |= (bitNums[i] % ) << i;
} return res;
}
};
https://leetcode.com/problems/single-number-ii/
Given an array of integers, every element appears three times except for one. Find that single one.
Note:
Your algorithm should have a linear runtime complexity. Could you implement it without using extra memory?
class Solution {
public:
int singleNumber(vector<int>& nums) {
if(nums.size() == ) return nums[]; vector<int> bitNums(, ); int res = ;
for(int i=;i<;++i) {
for(int j=;j<nums.size();++j) {
bitNums[i] += (nums[j] >> i) & ;
cout << ((nums[j] >> i) & ) << " ";
}
cout<<endl;
} for(int i=;i<bitNums.size();++i) {
res += (bitNums[i] % ) << i;
}
return res;
}
};
leetcode@ [136/137] Single Number & Single Number II的更多相关文章
- [LeetCode#136, 137]Single Number, Single Number 2
The question: Single Number Given an array of integers, every element appears twice except for one. ...
- leetcode 136 137 Single Number
题目描述(面试常考题) 借助了异或的思想 class Solution { public: int singleNumber(vector<int>& nums) { ; ; i ...
- Leetcode 136 137 260 SingleNumber I II III
Leetccode 136 SingleNumber I Given an array of integers, every element appears twice except for one. ...
- leetcode 136. Single Number 、 137. Single Number II 、 260. Single Number III(剑指offer40 数组中只出现一次的数字)
136. Single Number 除了一个数字,其他数字都出现了两遍. 用亦或解决,亦或的特点:1.相同的数结果为0,不同的数结果为1 2.与自己亦或为0,与0亦或为原来的数 class Solu ...
- LeetCode(137) Single Number II
题目 Given an array of integers, every element appears three times except for one. Find that single on ...
- 【LeetCode】137. Single Number II 解题报告(Python)
[LeetCode]137. Single Number II 解题报告(Python) 标签: LeetCode 题目地址:https://leetcode.com/problems/single- ...
- leetcode 136 Single Number, 260 Single Number III
leetcode 136. Single Number Given an array of integers, every element appears twice except for one. ...
- LeetCode 136. Single Number(只出现一次的数字)
LeetCode 136. Single Number(只出现一次的数字)
- [LeetCode] Number of Islands II 岛屿的数量之二
A 2d grid map of m rows and n columns is initially filled with water. We may perform an addLand oper ...
随机推荐
- Kafka 之 async producer (1)
问题 很多条消息是怎么打包在一起的? 如果消息是发给很多不同的topic的, async producer如何在按batch发送的同时区分topic的 它是如何用key来做partition的? 是如 ...
- linux MySQL安装配置
执行下面的命令初始化授权表: ./scripts/mysql_install_db --user=mysql
- ANDROID_MARS学习笔记_S01_002View、监听器初步
一.View.监听器介绍 二.在Activity中获取view和设置属性,设置button的监听器 1.activity_main.xml <LinearLayout xmlns:android ...
- POJ2115——C Looooops(扩展欧几里德+求解模线性方程)
C Looooops DescriptionA Compiler Mystery: We are given a C-language style for loop of type for (vari ...
- JS中访问对象的属性
方式一: 对象名.属性名; 方式二: 对象名["属性名"]; ★注意:方式二中,属性名以字符串的形式出现在方括号中,这意味着通过方式二访问属性的话,可以实现“动态访问对象的 ...
- 让JAVA代码跑得更快
本文简单介绍一下在写代码过程中用到的一些让JAVA代码更高效的技巧. 1. 将一些系统资源放在池中(如数据库连接, 线程等) 在standalone的应用中, 数据库连接池可以使用一些开源的连接池 ...
- Ubuntu12.04下arm交叉编译环境的建立
http://blog.csdn.net/heyangya2009/article/details/5424376 备注:ubuntu12.04+Android+Real6410 在主机上用来编译其他 ...
- linux 入门教程
linux入门教程 搜索 Linux入门教程 前言 第一章 关于Linux的历史 第二章 图形界面还是命令窗口 第三章 Linux操作系统的安装 第四章 初步进入linux世界 第五章 Linux系统 ...
- bzoj2757
非常神的数位dp,我调了几乎一天首先和bzoj3131类似,乘积是可以预处理出来的,注意这里乘积有一个表示的技巧因为这里质因数只有2,3,5,7,所以我们可以表示成2^a*3^b*5^c*7^d,也就 ...
- bzoj1079: [SCOI2008]着色方案
dp.以上次染色时用的颜色的数量和每种数量所含有的颜色作状态. #include<cstdio> #include<algorithm> #include<cstring ...