【首先膜拜大湿】poj-2386-Lake Counting-DFS模板题
Time Limit: 1000MS | Memory Limit: 65536K | |
Total Submissions: 16802 | Accepted: 8523 |
Description
out how many ponds have formed in his field. A pond is a connected set of squares with water in them, where a square is considered adjacent to all eight of its neighbors.
Given a diagram of Farmer John's field, determine how many ponds he has.
Input
* Lines 2..N+1: M characters per line representing one row of Farmer John's field. Each character is either 'W' or '.'. The characters do not have spaces between them.
Output
Sample Input
10 12
W........WW.
.WWW.....WWW
....WW...WW.
.........WW.
.........W..
..W......W..
.W.W.....WW.
W.W.W.....W.
.W.W......W.
..W.......W.
Sample Output
3
题目如上:
AC代码如下:
#include<iostream>
#include<stdio.h> #define Max 105
using namespace std; char f[Max][Max];
int N ,M;
void DFS(int x,int y)
{
f[x][y] = '.';
for(int dx = -1; dx <= 1; dx++)
for(int dy = -1; dy <= 1; dy++)
{
int nx, ny;
nx = x + dx; ny = y + dy;
if(nx < N&& ny < M&& nx >= 0&& ny >= 0&&f[nx][ny] == 'W') DFS(nx,ny);
} return ;
}
int main()
{
int res = 0,i,j;
cin>>N;
cin>>M; for(i = 0; i < N; i++)
scanf("%s",&f[i]); for(int i = 0; i < N; i++)
for(int j = 0; j < M; j++)
if(f[i][j] == 'W')
{
DFS(i,j);
res++;
}
printf("%d\n",res);
}【存在的问题】1、脑残地把坐标轴坐标和矩阵的坐标对应起来了;
2、解决了以上问题后程序还是在傲娇地RE,原来还是脑残地把“=”敲成“==”了;
再后来程序还傲娇地WA了,于是
3、经大湿的指点把原输入
for(i = 0; i < N; i++)
for(j = 0; j < M; j++)
scanf("%c",&f[i][j]);
换成了
for(i = 0; i < N; i++)
scanf("%s", &f[i]);
蓝后就AC了~~o(≧v≦)o~~
原因就是%c输入把换行符给吃掉了~~蓝后造成了移位。。。。
ORZ。。。。
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