CCC加拿大高中生信息学奥赛

其余来源

  CODEVS[3312]——CCC 1996 01 Deficient, Perfect, and Abundant ——http://codevs.cn/problem/3312/

  POJ[1928]——Perfection——http://poj.org/problem?id=1528

CODEVS描述——中文题目

题目描述 Description

读入一个正整数n,判断整数是完数,亏数还是盈数。

•如果它的约数的和等于它本身,那它便是一个完数(Perfect)(约数包含1,但不包含它本身)。

•如果它的约数的和小于它本身,那它便是一个亏数(Deficient)(约数包含1,但不包含它本身)。

•如果它的约数的和大于它本身,那它便是一个盈数(Abundant)(约数包含1,但不包含它本身)。

输入描述 Input Description

输入文件共两行,

第一行为一个正整数n,

第二行为n个正整数,中间用空格隔开。

输出描述 Output Description

输出为n行,分别为第1..n个数的类别。

完数:Perfect

亏数:Deficient

盈数:Abundant

样例输入 Sample Input

3
4 6 12

样例输出 Sample Output

4 is a deficient number.
6 is a perfect number.
12 is an abundant number.

数据范围及提示 Data Size & Hint

1<=n<=2^31-1

POJ描述(英文)

Description

From the article Number Theory in the 1994 Microsoft Encarta: ``If a, b, c are integers such that a = bc, a is called a multiple of b or of c, and b or c is called a divisor or factor of a. If c is not 1/-1, b is called a proper divisor of a. Even integers, which include 0, are multiples of 2, for example, -4, 0, 2, 10; an odd integer is an integer that is not even, for example, -5, 1, 3, 9. A perfect number is a positive integer that is equal to the sum of all its positive, proper divisors; for example, 6, which equals 1 + 2 + 3, and 28, which equals 1 + 2 + 4 + 7 + 14, are perfect numbers. A positive number that is not perfect is imperfect and is deficient or abundant according to whether the sum of its positive, proper divisors is smaller or larger than the number itself. Thus, 9, with proper divisors 1, 3, is deficient; 12, with proper divisors 1, 2, 3, 4, 6, is abundant." 
Given a number, determine if it is perfect, abundant, or deficient. 

Input

A list of N positive integers (none greater than 60,000), with 1 <= N < 100. A 0 will mark the end of the list.

Output

The first line of output should read PERFECTION OUTPUT. The next N lines of output should list for each input integer whether it is perfect, deficient, or abundant, as shown in the example below. Format counts: the echoed integers should be right justified within the first 5 spaces of the output line, followed by two blank spaces, followed by the description of the integer. The final line of output should read END OF OUTPUT.

Sample Input

  1. 15 28 6 56 60000 22 496 0

Sample Output

  1. PERFECTION OUTPUT
  2. 15 DEFICIENT
  3. 28 PERFECT
  4. 6 PERFECT
  5. 56 ABUNDANT
  6. 60000 ABUNDANT
  7. 22 DEFICIENT
  8. 496 PERFECT
  9. END OF OUTPUT

Source

 
 

思路

  利用数论知识快速计算一个数的约数和,详见程序函数。

样例

  CODEVS:

  1. var t,x:longint;
  2.  
  3. function ans(n:longint):longint;
  4. var i:longint;
  5. begin
  6. ans:=;
  7. for i:= to n do
  8. begin
  9. if (i*i=n) then
  10. begin
  11. ans:=ans+i;
  12. break;
  13. end;
  14. if (i*i>n) then break;
  15. if (n mod i=) then ans:=ans+i+n div i;
  16. end;
  17. end;
  18.  
  19. procedure main;
  20. var anss,n:longint;
  21. begin
  22. read(n);
  23. anss:=ans(n)-n;
  24. if anss<n then writeln(n,' is a deficient number.');
  25. if anss=n then writeln(n,' is a perfect number.');
  26. if anss>n then writeln(n,' is an abundant number.');
  27. end;
  28.  
  29. begin
  30. readln(t);
  31. for x:= to t do main;
  32. end.

  POJ:

  1. var t,x,n:longint;
  2.  
  3. function ans(n:longint):longint;
  4. var i:longint;
  5. begin
  6. ans:=;
  7. for i:= to n do
  8. begin
  9. if (i*i=n) then
  10. begin
  11. ans:=ans+i;
  12. break;
  13. end;
  14. if (i*i>n) then break;
  15. if (n mod i=) then ans:=ans+i+n div i;
  16. end;
  17. end;
  18.  
  19. procedure main;
  20. var anss,x,i:longint;s:ansistring;
  21. begin
  22. anss:=ans(n)-n;
  23. str(n,s);
  24. x:=length(s);
  25. for i:= to -x do write(' ');
  26. if anss<n then writeln(n,' DEFICIENT');
  27. if anss=n then writeln(n,' PERFECT');
  28. if anss>n then writeln(n,' ABUNDANT');
  29. end;
  30.  
  31. begin
  32. writeln('PERFECTION OUTPUT');
  33. while true do
  34. begin
  35. read(n);
  36. if n= then
  37. begin
  38. writeln('END OF OUTPUT');
  39. halt;
  40. end;
  41. main;
  42. end;
  43. end.

[CCC 1996 01]Deficient, Perfect, and Abundant的更多相关文章

  1. HDU1323_Perfection【水题】

    Perfection Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total ...

  2. POJ 1528问题描述

    Description From the article Number Theory in the 1994 Microsoft Encarta: ``If a, b, c are integers ...

  3. HDOJ 1323 Perfection(简单题)

    Problem Description From the article Number Theory in the 1994 Microsoft Encarta: "If a, b, c a ...

  4. python开发学习-day10(select/poll/epoll回顾、redis、rabbitmq-pika)

    s12-20160319-day10 *:first-child { margin-top: 0 !important; } body>*:last-child { margin-bottom: ...

  5. Python框架之Tornado(二)请求阶段

    概述 上图是tornado程序启动以及接收到客户端请求后的整个过程,对于整个过程可以分为两大部分: 启动程序阶段,又称为待请求阶段(上图1.2所有系列和3.0) 接收并处理客户端请求阶段(上图3系列) ...

  6. python之协程与IO操作

    协程 协程,又称微线程,纤程.英文名Coroutine. 协程的概念很早就提出来了,但直到最近几年才在某些语言(如Lua)中得到广泛应用. 子程序,或者称为函数,在所有语言中都是层级调用,比如A调用B ...

  7. 第二篇:白话tornado源码之待请求阶段

    上篇<白话tornado源码之一个脚本引发的血案>用上帝视角多整个框架做了一个概述,同时也看清了web框架的的本质,下面我们从tornado程序的起始来分析其源码. 概述 上图是torna ...

  8. Python - 异步IO\数据库\队列\缓存

    协程 协程,又称微线程,纤程.英文名Coroutine.一句话说明什么是线程:协程是一种用户态的轻量级线程,协程一定是在单线程运行的. 协程拥有自己的寄存器上下文和栈.协程调度切换时,将寄存器上下文和 ...

  9. sellect、poll、epoll

    http://www.cnblogs.com/alex3714/p/4372426.html select select最早于1983年出现在4.2BSD中,它通过一个select()系统调用来监视多 ...

随机推荐

  1. 【python】迭代一列 斐波那契数列

    def fabm(n): if n < 1: print('输入不能小于1') return -1 if n == 1 or n == 2: return 1 else: return fabm ...

  2. android开发两种退出程序方式(killProcess,System.exit)

    KillProcess: 在android中我们如果想要程序的进程结束可以这样写: android.os.Process.killProcess(android.os.Process.myPid()) ...

  3. Call Azure Queue get "The remote server returned an error: (400) Bad Request."

    这几天开始研究Windows Azure, 在使用Azure Queue 的时候,CreateInfNotExists 总是抛出异常 "The remote server returned ...

  4. check whether the crystal report runtime is exists 检查crystalreport运行时是否存在

    1. Try Dim rptDoc As New CrystalDecisions.CrystalReports.Engine.ReportClass() Dim rptView As New Cry ...

  5. 开发软件设计模型 visual studio UML

    http://www.ibm.com/developerworks/cn/rational/rationaledge/content/feb05/bell/ http://msdn.microsoft ...

  6. classes system in sencha touch

    //http://www.sencha.com/learn/sencha-class-system var Person = new Ext.Class({ name: 'Mr. Unknown', ...

  7. 微软Hololens学院教程-Hologram 212-Voice(语音)【微软教程已经更新,本文是老版本】

    这是老版本的教程,为了不耽误大家的时间,请直接看原文,本文仅供参考哦!原文链接:https://developer.microsoft.com/EN-US/WINDOWS/HOLOGRAPHIC/ho ...

  8. 使用PyInstaller打包Python程序

    本文转载自: http://www.pycoding.com/2015/04/23/pyinstaller.html

  9. cyg_flag 系列函数

    http://blog.csdn.net/mrwangwang/article/details/7954236 cyg_flag_init Name: cyg_flag_init ( ) - init ...

  10. SPRING IN ACTION 第4版笔记-第六章RENDERING WEB VIEWS-002- Spring的JSP标签之form标签(<sf:input><sf:errors><sf:form>)

    一. Spring offers two JSP tag libraries to help define the view of your Spring MVC web views. One tag ...