使用DFS出现超时,改成bfs

DFS

#include <iostream>
#include <vector>
#include <set>
using namespace std;
int n;
int l;
int i,j;
int m,k;
int follower[1001][1001];
vector<int> user_list[1001];
set<int> user_s;
void queryU(int a,int depth){
if(depth==l){
return ;
}
for(int i=0;i<user_list[a].size();i++){
queryU(user_list[a][i],depth+1);
user_s.insert(user_list[a][i]);
} return ;
}
int main()
{
cin>>n>>l;
int a;
for(i=1;i<=n;i++){
cin>>m;
for(j=0;j<m;j++){
cin>>a;
user_list[a].push_back(i);
}
}
cin>>k;
int sum;
for(i=0;i<k;i++){
cin>>a;
user_s.clear();
user_s.insert(a);
queryU(a,0);
cout<<user_s.size()-1<<endl;
}
return 0;
}

  bfs

最后一个测试用例一直MLE,后来用指针优化,就报超时了。

后来参考 https://www.zhihu.com/question/28264519,把队列删除语句省掉,set省掉,终于AC了!

#include <iostream>
#include <vector>
#include <set>
using namespace std;
int n;
int l;
int i,j;
int m,k;
vector<int> user_list[1010];
vector<int> que;
int v[1005];
int main()
{
cin>>n>>l;
int a;
for(i=1;i<=n;i++){
cin>>m;
for(j=0;j<m;j++){
cin>>a;
user_list[a].push_back(i);
}
}
cin>>k;
for(i=1;i<=k;i++){
cin>>a;
v[a]=i;
int depth=0;
que.clear();
que.push_back(a);
int levelSize=0;
int count=1;
for(int z=0;z<que.size();z++){
int num=que[z];
count--;
vector<int> *tmp=&user_list[num];
levelSize+=tmp->size();
for(int y=0;y<tmp->size();y++){
int temp_num=(*tmp)[y];
if(v[temp_num]!=i){
que.push_back(temp_num);
v[temp_num]=i;
}
}
if(count==0){
count=levelSize;
levelSize=0;
depth++;
}
if(depth==l){
break;
}
}
cout<<que.size()-1<<endl;
}
return 0;
}

  

PAT1076. Forwards on Weibo (30)的更多相关文章

  1. 1076. Forwards on Weibo (30)【树+搜索】——PAT (Advanced Level) Practise

    题目信息 1076. Forwards on Weibo (30) 时间限制3000 ms 内存限制65536 kB 代码长度限制16000 B Weibo is known as the Chine ...

  2. PAT 甲级 1076 Forwards on Weibo (30分)(bfs较简单)

    1076 Forwards on Weibo (30分)   Weibo is known as the Chinese version of Twitter. One user on Weibo m ...

  3. 1076. Forwards on Weibo (30)

    时间限制 3000 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Weibo is known as the Chinese v ...

  4. PAT 1076. Forwards on Weibo (30)

    Weibo is known as the Chinese version of Twitter. One user on Weibo may have many followers, and may ...

  5. 1076. Forwards on Weibo (30) - 记录层的BFS改进

    题目如下: Weibo is known as the Chinese version of Twitter. One user on Weibo may have many followers, a ...

  6. 1076 Forwards on Weibo (30)(30 分)

    Weibo is known as the Chinese version of Twitter. One user on Weibo may have many followers, and may ...

  7. PAT Advanced 1076 Forwards on Weibo (30) [图的遍历,BFS,DFS]

    题目 Weibo is known as the Chinese version of Twitter. One user on Weibo may have many followers, and ...

  8. Forwards on Weibo (30)

    BFS,题意比较难懂,是求离query L层的总共人数 #include <stdio.h> #include <string.h> #include <iostream ...

  9. PAT1076. Forwards on Weibo(标准bfs模板)

    //标准的层次遍历模板 //居然因为一个j写成了i,debug半天.....解题前一定要把结构和逻辑想清楚,不能着急动手,理解清楚题意,把处理流程理清楚再动手,恍恍惚惚的写出来自己慢慢debug吧 # ...

随机推荐

  1. 【BZOJ5060】魔方国 特判

    [BZOJ5060]魔方国 Description 小奇和魔法猪打开了战狂的遗迹,穿越到了东元20年.东元元年,战狂率领一千万士兵毁灭了一个又一个文明,并建立起了新文明——昌和帝国,招募了八位伟人:大 ...

  2. 【BZOJ4385】[POI2015]Wilcze doły 单调栈+双指针法

    [BZOJ4385][POI2015]Wilcze doły Description 给定一个长度为n的序列,你有一次机会选中一段连续的长度不超过d的区间,将里面所有数字全部修改为0.请找到最长的一段 ...

  3. Linux下修改Mysql的用(root的密码及修改root登录权限

    修改的用户都以root为列. 一.知道原来的myql数据库的root密码: ①: 在终端命令行输入 mysqladmin -u root -p password "新密码" 回车  ...

  4. android studio 新建项目 界面一直停在 【“building ‘ 项目名’ gradle project info”】

    安装了android studio 之后,按照上文所述的那篇博文下载安装gradle,配置环境变量, 启动android studio,新建项目,发现还是新建不了,界面一直停在 ["buil ...

  5. "AppServer"--->UDP--->"LogWriteServer"

    w 是否应该将日志的“写”独立至局域网的一台或一群专门服务于“写日志”的服务器?这样让“app服务器”专职地处理用户的请求,而不必因为“写日志甚至异步分析日志”来降低用户体验? Spencer老师 其 ...

  6. java连接elastic search 9300

    java连接elastic search 导入jar包:https://www.elastic.co/guide/en/elasticsearch/client/java-api/5.5/_maven ...

  7. Leetcode注意

    List<List<Integer>> res = new ArrayList<>();

  8. Python3 标准库

    Python3标准库 更详尽:http://blog.csdn.net/jurbo/article/details/52334345 文本 string:通用字符串操作 re:正则表达式操作 diff ...

  9. VGA显示

    VGA控制器的编写主要是了解VGA的显示标准和时序,如1024X768@60Hz,确定时钟频率(65MHz=1344X806X60),列像素时间等于时钟周期,扫描从左到右.从上到下(类似于电视扫描PA ...

  10. html当前文档的状态

    <script type="text/javascript"> document.onreadystatechange = loadingChange;//当页面加载状 ...