c语言二维数组传递

c语言二维数组传递，目前我总结三种方法，以及纠正一个不能使用的方法

/*********************************
* 方法1: 第一维的长度可以不指定 *
* 但必须指定第二维的长度 *
*********************************/
void fun(int a[][], int n, int m)
{
    int i, j;

    for (i = ; i < n; i++)
    {
        for (j = ; j < m; j++)
            printf("%d ", a[i][j]);

        printf("\n");
    }
}

/*****************************************
*方法2: 指向一个有5个元素一维数组的指针 *
*****************************************/
void fun(int(*a)[], int n, int m)
{
    int i, j;

    for (i = ; i < n; i++)
    {
        for (j = ; j < m; j++)
            printf("%d ", a[i][j]);
        printf("\n");
    }
}

前面两种方法是必须指明所有维数大小或者省略第一维的。还有一种是网上一直有指针的指针来传递，我用vs2013试了一下，代码如下；

void fun(int **a, int n, int m)

这个直接用fun(a,3,3)是出错的

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HBYhpYjBBxwWIaWIwQccFiGliMEHHBYhpYjBBxwWIaWIwQccFiGliMEHHBYhr399sPHz5efasQQgJzd/cJi2ms18m7dz/d3X26+rYhhLTm7u7Tjz++32x+juMHGRZ78+ZXHz/+ebt9IISIyGbz8zff/DqOH2RYDADABxYDANlgMQCQDRYDANlgMQCQDRYDANn8H+sOzVA8s2F+AAAAAElFTkSuQmCC" 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所以，我另想一个方法，因为数组是顺序存储，所以我们只要传数组的第一个地址过去就可以得到其他，具体看下面代码

#include<stdio.h>
void fun(int *a, int n, int m)
{
    for (int i = ; i < n; i++)
    {
        for (int j = ; j < m; j++)
        {
            printf("%d ", *(a + i*m + j));
        }
        printf("\n");
    }
}

int main()
{

    int a[][] =
    {
        { ,  },
        { , ,  },
        {  }
    };
    printf("%d %d\n",a,a[]);

    fun(*a,,);//fun(a[0][0],3,3)   fun(a[0],3,3)这三种都可以

    return ;
}