2-sat基础题 uvalive 3211

蓝书325页的基础题

二分+2-sat

//看看会不会爆int!数组会不会少了一维！
//取物问题一定要小心先手胜利的条件
#include <bits/stdc++.h>
using namespace std;
#pragma comment(linker,"/STACK:102400000,102400000")
#define LL long long
#define ALL(a) a.begin(), a.end()
#define pb push_back
#define mk make_pair
#define fi first
#define se second
#define haha printf("haha\n")
const int maxn =  + ;
 
struct TwoSAT{
    int n;
    vector<int> G[maxn];
    bool mark[maxn];
    int c, s[maxn];///c是表示目前dfs到的个数和已经被标记的集合s
    bool dfs(int x){
        if (mark[x ^ ]) return false;
        if (mark[x]) return true;
        mark[x] = true;
        s[c++] = x;
        for (int i = ; i < G[x].size(); i++)
            if (!dfs(G[x][i])) return false;
        return true;
    }
 
    void init(int n){
        this->n = n;
        for (int i = ; i <  * n; i++) G[i].clear();
        memset(mark, , sizeof(mark));
    }
 
    void add_edge(int x, int xval, int y, int yval){
        x = x *  + xval, y = y *  + yval;
        G[x ^ ].push_back(y);
        G[y ^ ].push_back(x);
    }
 
    bool solve(){
        for (int i = ; i <  * n; i += ){
            if (!mark[i] && !mark[i + ]){
                c = ;
                if (!dfs(i)){
                    while (c) mark[s[--c]] = false;
                    if (!dfs(i + )) return false;
                }
            }
        }
        return true;
    }
};
 
TwoSAT sat;
int n;
int E[maxn], L[maxn];
int ti[maxn][];
 
bool test(int p){
    sat.init(n);
    for (int i = ; i < n; i++){
        for (int x = ; x < ; x++){
            for (int j = i + ; j < n; j++){
                for (int y = ; y < ; y++){
                    if (abs(ti[i][x] - ti[j][y]) < p){
                        ///那就说明不成立，因此要建立成立的边
                        sat.add_edge(i, x ^ , j, y ^ );
                    }
                }
            }
        }
    }
    return sat.solve();
}
 
int main(){
    while (scanf("%d", &n) == ){
        int lb = , rb = ;
        for (int i = ; i < n; i++){
            scanf("%d%d", E + i, L + i);
            ti[i][] = E[i], ti[i][] = L[i];
            rb = max(rb, max(E[i], L[i]));
        }
        rb++;
        while (lb < rb - ){
            int mid = (lb + rb) / ;
            if (test(mid)) lb = mid;
            else rb = mid;
        }
        printf("%d\n",lb);
    }
    return ;
}