Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 51959    Accepted Submission(s): 19706

 

Problem Description
The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.

 



Input
Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 ... nm where m is the number of integers in the set and n1 ... nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.
 



Output
For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer.
 



Sample Input
2
3 5 7 15
6 4 10296 936 1287 792 1
 



Sample Output
105
10296
 
思路:求多个数的最小公倍数
 #include<iostream>
using namespace std;
long long gcd(long long c,long long b)
{
return b? gcd(b,c%b):c;
}
int main()
{
int t;
cin>>t;
while(t--)
{
int n;
long long a[];
cin>>n;
for(int i=;i<n;i++)
{
cin>>a[i];
}
for(int i=;i<n;i++)
{
a[i]=a[i]*a[i-]/gcd(a[i],a[i-]);
}
cout<<a[n-]<<endl;
}
return ;
}

求最大公约数代码:

long long  gcd(long long  c,long long  b)
{
return b? gcd(b,c%b):c;
}

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