Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.

The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predators, the geese population was out of control. The people of Loowater mostly kept clear of the geese. Occasionally, a goose would attack one of the people, and perhaps bite off a finger or two, but in general, the people tolerated the geese as a minor nuisance.

One day, a freak mutation occurred, and one of the geese spawned a multi-headed fire-breathing dragon. When the dragon grew up, he threatened to burn the Kingdom of Loowater to a crisp. Loowater had a major problem. The king was alarmed, and called on his knights to slay the dragon and save the kingdom.

The knights explained: "To slay the dragon, we must chop off all its heads. Each knight can chop off one of the dragon's heads. The heads of the dragon are of different sizes. In order to chop off a head, a knight must be at least as tall as the diameter of the head. The knights' union demands that for chopping off a head, a knight must be paid a wage equal to one gold coin for each centimetre of the knight's height."

Would there be enough knights to defeat the dragon? The king called on his advisors to help him decide how many and which knights to hire. After having lost a lot of money building Mir Park, the king wanted to minimize the expense of slaying the dragon. As one of the advisors, your job was to help the king. You took it very seriously: if you failed, you and the whole kingdom would be burnt to a crisp!

Input Specification:

The input contains several test cases. The first line of each test case contains two integers between 1 and 20000 inclusive, indicating the number n of heads that the dragon has, and the number m of knights in the kingdom. The next n lines each contain an integer, and give the diameters of the dragon's heads, in centimetres. The following m lines each contain an integer, and specify the heights of the knights of Loowater, also in centimetres.

The last test case is followed by a line containing:

0 0

Output Specification:

For each test case, output a line containing the minimum number of gold coins that the king needs to pay to slay the dragon. If it is not possible for the knights of Loowater to slay the dragon, output the line:

Loowater is doomed!

Sample Input:

2 3
5
4
7
8
4
2 1
5
5
10
0 0

Output for Sample Input:

11
Loowater is doomed! 题目大意:输入n,m表示有n个头和m个勇士,接下来n个头的战斗力,m歌骑士的战斗力。规定一个骑士只能杀掉一个战斗力不大于其自身战斗力的头,同时要支付给他与战斗力等值的金币,问花费最少为多少,不能杀掉就显示样例2的输出。 解题思路:贪心,头和骑士能力从小到大排序,一个一个砍,不能砍掉当前头的骑士就不要。
 #include<iostream>
#include<algorithm>
using namespace std;
int main(){
int n,m;
int heard[],power[];
while(cin>>n>>m){
if(n== && m==)return ;
for(int i=;i<n;i++)cin>>heard[i];
for(int j=;j<m;j++)cin>>power[j];
sort(heard,heard+n);
sort(power,power+m);
int cur=;
int cost=;
for(int i=;i<m;i++){//从小到大一个一个来砍,不能砍下当前的就不砍
if(power[i]>=heard[cur]){
cost+=power[i];
if(++cur == n)break;
}
}
if(cur<n)cout<<"Loowater is doomed!\n";
else cout<<cost<<'\n';
}return ;
}
												

[ACM_水题] UVA 11292 Dragon of Loowater [勇士斗恶龙 双数组排序 贪心]的更多相关文章

  1. UVA 11292 Dragon of Loowater(简单贪心)

    Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...

  2. uva 11292 Dragon of Loowater (勇者斗恶龙)

    Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...

  3. [ACM_水题] UVA 12502 Three Families [2人干3人的活后分钱,水]

      Three Families  Three families share a garden. They usually clean the garden together at the end o ...

  4. UVa 11292 Dragon of Loowater (水题,排序)

    题意:有n个条龙,在雇佣勇士去杀,每个勇士能力值为x,只能杀死头的直径y小于或等于自己能力值的龙,只能被雇佣一次,并且你要给x赏金,求最少的赏金. 析:很简单么,很明显,能力值高的杀直径大的,低的杀直 ...

  5. UVa 11292 - Dragon of Loowater(排序贪心)

    Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.The shore ...

  6. UVa 11292 Dragon of Loowater

    简单贪心 龙头的直径和人的佣金排序,价值小的人和直径小的配 #include<iostream> #include<cstdio> #include<cmath> ...

  7. UVA - 11292 Dragon of Loowater 贪心

    贪心策略:一个直径为X的头颅,应该让雇佣费用满足大于等于X且最小的骑士来砍掉,这样才能使得花费最少. AC代码 #include <cstdio> #include <cmath&g ...

  8. [ACM_水题] UVA 11729 Commando War [不可同时交代任务 可同时执行 最短完成全部时间 贪心]

    There is a war and it doesn't look very promising for your country. Now it's time to act. You have a ...

  9. UVA它11292 - Dragon of Loowater

    Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...

随机推荐

  1. {vlFeat}{Matlab}Linux中matlab的vlFeat配置

    1.下载vlFeat编译后的版本binary package 2.解压后将 toolbox/,bin/,data/ 等文件夹复制到matlab新建工具箱目录 /toolbox/vlfeat/ 中 3. ...

  2. 《C和指针(Pointer on c)》 学习笔记

    转载:http://dsqiu.iteye.com/blog/1687944 首先本文是对参考中三个连接的博客进行的整理,非常感谢三位博主的努力,每次都感叹网友的力量实在太强大了…… 第一章 快速上手 ...

  3. sql ltrim rtrim

    sql中用LTRIM ( ),RTRIM ( ).分别截断首尾空格,返回字符表达式. 例1: DECLARE @string_to_trim varchar(60)SET @string_to_tri ...

  4. Ubuntu 编译安装 Linux 4.0.5 内核,并修复 vmware 网络内核模块编译错误

    . . . . . 今天把 Ubuntu 14.04 升级到了最新的 4.0.5 的内核版本,本来不打算记录下来的,但是升级的过程中确实遇到了一些问题,所以还是记录下来,分享给遇到同样问题的猿友. 先 ...

  5. Linux系统编程-防止僵尸进程产生的常用方法

    1.父进程调用wait函数或waitpid函数回收子进程. 2.让init进程去处理子进程回收工作,代码中加上"signal(SIGCHLD, SIG_IGN)"这句话.

  6. Selenium简单介绍

    WEB自动化测试:指WEB应用系统从用户界面层面进行的自动化测试.通过用户界面测试内部的业务逻辑. 自身特点:(一)WEB页面上出现的元素有可能具有不确定性: (二)不同操作系统上不同WEB浏览器之间 ...

  7. npoi实现 从固定的行读取数据作为表头并返回datable

    using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.D ...

  8. 声明、定义 in C++

    序 声明和定义是我们使用的基础,但是对于声明和定义的概念,我们不甚了了,也就是说感觉好像是这样,但是真要详细说明就说不上来. 有博主对于声明和定义有以下描述:          1.需要建立存储空间的 ...

  9. Slave failed to initialize relay log info structure from the repository

    现象 查看slave 服务状态 show slave status\G; 错误 Last_Errno: 1872 Last_Error: Slave failed to initialize rela ...

  10. idhttp的用法

    1)POST function PostMethod(http: TIDhttp; URL: string; Params: TStringList): string;var RespData: TS ...