[ACM_水题] UVA 11292 Dragon of Loowater [勇士斗恶龙 双数组排序 贪心]
Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.
The shores of Rellau Creek in central Loowater had always been a prime breeding ground for geese. Due to the lack of predators, the geese population was out of control. The people of Loowater mostly kept clear of the geese. Occasionally, a goose would attack one of the people, and perhaps bite off a finger or two, but in general, the people tolerated the geese as a minor nuisance.
One day, a freak mutation occurred, and one of the geese spawned a multi-headed fire-breathing dragon. When the dragon grew up, he threatened to burn the Kingdom of Loowater to a crisp. Loowater had a major problem. The king was alarmed, and called on his knights to slay the dragon and save the kingdom.
The knights explained: "To slay the dragon, we must chop off all its heads. Each knight can chop off one of the dragon's heads. The heads of the dragon are of different sizes. In order to chop off a head, a knight must be at least as tall as the diameter of the head. The knights' union demands that for chopping off a head, a knight must be paid a wage equal to one gold coin for each centimetre of the knight's height."
Would there be enough knights to defeat the dragon? The king called on his advisors to help him decide how many and which knights to hire. After having lost a lot of money building Mir Park, the king wanted to minimize the expense of slaying the dragon. As one of the advisors, your job was to help the king. You took it very seriously: if you failed, you and the whole kingdom would be burnt to a crisp!
Input Specification:
The input contains several test cases. The first line of each test case contains two integers between 1 and 20000 inclusive, indicating the number n of heads that the dragon has, and the number m of knights in the kingdom. The next n lines each contain an integer, and give the diameters of the dragon's heads, in centimetres. The following m lines each contain an integer, and specify the heights of the knights of Loowater, also in centimetres.
The last test case is followed by a line containing:
0 0
Output Specification:
For each test case, output a line containing the minimum number of gold coins that the king needs to pay to slay the dragon. If it is not possible for the knights of Loowater to slay the dragon, output the line:
Loowater is doomed!
Sample Input:
2 3
5
4
7
8
4
2 1
5
5
10
0 0
Output for Sample Input:
11
Loowater is doomed! 题目大意:输入n,m表示有n个头和m个勇士,接下来n个头的战斗力,m歌骑士的战斗力。规定一个骑士只能杀掉一个战斗力不大于其自身战斗力的头,同时要支付给他与战斗力等值的金币,问花费最少为多少,不能杀掉就显示样例2的输出。 解题思路:贪心,头和骑士能力从小到大排序,一个一个砍,不能砍掉当前头的骑士就不要。
#include<iostream>
#include<algorithm>
using namespace std;
int main(){
int n,m;
int heard[],power[];
while(cin>>n>>m){
if(n== && m==)return ;
for(int i=;i<n;i++)cin>>heard[i];
for(int j=;j<m;j++)cin>>power[j];
sort(heard,heard+n);
sort(power,power+m);
int cur=;
int cost=;
for(int i=;i<m;i++){//从小到大一个一个来砍,不能砍下当前的就不砍
if(power[i]>=heard[cur]){
cost+=power[i];
if(++cur == n)break;
}
}
if(cur<n)cout<<"Loowater is doomed!\n";
else cout<<cost<<'\n';
}return ;
}
[ACM_水题] UVA 11292 Dragon of Loowater [勇士斗恶龙 双数组排序 贪心]的更多相关文章
- UVA 11292 Dragon of Loowater(简单贪心)
Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...
- uva 11292 Dragon of Loowater (勇者斗恶龙)
Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...
- [ACM_水题] UVA 12502 Three Families [2人干3人的活后分钱,水]
Three Families Three families share a garden. They usually clean the garden together at the end o ...
- UVa 11292 Dragon of Loowater (水题,排序)
题意:有n个条龙,在雇佣勇士去杀,每个勇士能力值为x,只能杀死头的直径y小于或等于自己能力值的龙,只能被雇佣一次,并且你要给x赏金,求最少的赏金. 析:很简单么,很明显,能力值高的杀直径大的,低的杀直 ...
- UVa 11292 - Dragon of Loowater(排序贪心)
Once upon a time, in the Kingdom of Loowater, a minor nuisance turned into a major problem.The shore ...
- UVa 11292 Dragon of Loowater
简单贪心 龙头的直径和人的佣金排序,价值小的人和直径小的配 #include<iostream> #include<cstdio> #include<cmath> ...
- UVA - 11292 Dragon of Loowater 贪心
贪心策略:一个直径为X的头颅,应该让雇佣费用满足大于等于X且最小的骑士来砍掉,这样才能使得花费最少. AC代码 #include <cstdio> #include <cmath&g ...
- [ACM_水题] UVA 11729 Commando War [不可同时交代任务 可同时执行 最短完成全部时间 贪心]
There is a war and it doesn't look very promising for your country. Now it's time to act. You have a ...
- UVA它11292 - Dragon of Loowater
Problem C: The Dragon of Loowater Once upon a time, in the Kingdom of Loowater, a minor nuisance tur ...
随机推荐
- 1.Mybatis原理
Mybatis是一个持久层框架,Apache底下的一个项目,它的前身是ibatis,它支持普通的SQL查询,存储过程和高级映射的优秀框架.Mybatis消除了几乎所有的JDBC代码和参数的手工设置以及 ...
- TCP/IP、Http的区别
TPC/IP协议是传输层协议,主要解决数据如何在网络中传输,而HTTP是应用层协议,主要解决如何包装数据.关于TCP/IP和HTTP协议的关系,网络有一段比较容易理解的介绍:“我们在传输数据时,可以只 ...
- 联想扬天 电脑 键盘改默认fn功能键
联想扬天电脑改键工具 windows 8 windows8.1 64位版本:http://support1.lenovo.com.cn/lenovo/wsi/Modules/DriverDetail. ...
- oracle数据学习第一天
SQL(Strutured Query Language):结构化查询语言 SQL可分为: <1>数据定义语言(DDL):Data Definition Language 用于建立.修改. ...
- HDU 3974 Assign the task(dfs建树+线段树)
题目大意:公司里有一些员工及对应的上级,给出一些员工的关系,分配给某员工任务后,其和其所有下属都会进行这项任务.输入T表示分配新的任务, 输入C表示查询某员工的任务.本题的难度在于建树,一开始百思不得 ...
- 在Linux下安装配置phpMyAdmin步骤
本文于CentOS 6.5下测试可行,欢迎转载和指正. phpMyAdmin是一种基于Web的免费MySQL管理工具.phpMyAdmin是用PHP编写的,因此只有支持PHP的服务器才能使用phpMy ...
- H5-杂七杂八的标签
1.overflow:设置当内容超出父级的宽高尺寸设置时的处理方式 a.hidden:隐藏超出部分的内容 b.auto:如果内容没有超出,就正常显示,如果超出,就隐藏内容并提供滚动条,可以滚动显示超出 ...
- 使用Resource Owner Password Credentials Grant授权发放Token
对应的应用场景是:为自家的网站开发手机 App(非第三方 App),只需用户在 App 上登录,无需用户对 App 所能访问的数据进行授权. 客户端获取Token: public string Get ...
- AjaxControlToolkit MaskedEdit Unspecified error 未指定错误
使用AjaxControlToolkit 里面的 MaskedEditValidator控件,IE里面在如下的js中出现未指定(Unspecified error)错误, if (document.a ...
- 【转】[caffe]深度学习之图像分类模型AlexNet解读
[caffe]深度学习之图像分类模型AlexNet解读 原文地址:http://blog.csdn.net/sunbaigui/article/details/39938097 本文章已收录于: ...