803E

dp

dp[i][j]表示到了i赢和输的差为j

如果这位是?向dp[i-1][j-1],dp[i-1][j],dp[i-1][j+1]转移，如果是W向dp[i-1][j-1]转移,如果是L向dp[i-1][j+1]转移，如果是D向dp[i-1][j]转移

#include<bits/stdc++.h>
using namespace std;
const int N = ;
int n, k;
char s[N], ans[N][N * ];
int dp[N][N * ], pre[N][N * ];
int main()
{
    scanf("%d%d", &n, &k);
    scanf("%s", s + );
    dp[][] = ;
    for(int i = ; i <= n; ++i)
        for(int j = -k + ; j <= k + ; ++j)
        {
            ans[i][j] = s[i];
            if(s[i] == '?')
            {
                for(int l = -; l <= ; ++l) if(abs(j + l - ) < k && dp[i - ][j + l])
                {
                    dp[i][j] = dp[i - ][j + l];
                    if(l == -) ans[i][j] = 'W';
                    else if(l == ) ans[i][j] = 'D';
                    else if(l == ) ans[i][j] = 'L';
                    pre[i][j] = j + l;
                }
            }
            else if(s[i] == 'W')
            {
                if(abs(j - ) < k && dp[i - ][j - ])
                {
                    dp[i][j] = ;
                    pre[i][j] = j - ;
                }
            }
            else if(s[i] == 'L')
            {
                if(abs(j - ) < k && dp[i - ][j + ])
                {
                    dp[i][j] = ;
                    pre[i][j] = j + ;
                }
            }
            else if(s[i] == 'D')
            {
                if(abs(j - ) < k && dp[i - ][j])
                {
                    pre[i][j] = j;
                    dp[i][j] = ;
                }
            }
        }
    if(!dp[n][k + ] && !dp[n][-k + ])
    {
        puts("NO");
        return ;
    }
    vector<char> v;
    int now = dp[n][k + ] ? k +  : -k + ;
    for(int i = now, j = n; i && j; i = pre[j][i], --j)
        v.push_back(ans[j][i]);
    reverse(v.begin(), v.end());
    for(int i = ; i < v.size(); ++i) printf("%c", v[i]);
    return ;
}